## anonymous 3 years ago At what height from surface of earth, acceleration due to gravity becomes g/2 ?

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1. Fifciol

$\frac{ g }{ 2}=\frac{ GM }{2R ^{2} }= \frac{ GM }{(R+h) ^{2} }\rightarrow h=R(\sqrt{2}-1)= 2639 km$

2. anonymous

2.6km aproximately