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JJenk Group Title

Solve. open parentheses square root of 7 close parentheses to the 6 x power = 49x-6

  • one year ago
  • one year ago

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  1. marissalovescats Group Title
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    Can you draw this please?

    • one year ago
  2. marissalovescats Group Title
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    |dw:1373139028363:dw|

    • one year ago
  3. JJenk Group Title
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    |dw:1373139009699:dw|

    • one year ago
  4. marissalovescats Group Title
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    Hm... I recognize this. Let me go look at past notes.

    • one year ago
  5. JJenk Group Title
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    These were the choices i was given x = negative 21 over 2 x = -6 x = negative 6 over 5 x = -12

    • one year ago
  6. marissalovescats Group Title
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    Does this happen to be from a lesson called "Solve Exponential Equations" ?

    • one year ago
  7. JJenk Group Title
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    Yes

    • one year ago
  8. marissalovescats Group Title
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    Okay.. Uhm.. I've never seen one with a square root but let me see if I can solve it then I'll show you

    • one year ago
  9. Jhannybean Group Title
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    \[\large \sqrt{(7)}^{6x}=49^{x-6}\]\[\large (\sqrt{7})^{6x} = \color{green}{(\sqrt{7})^{4(x-6)}}\]\[\large 6x = 4(x-6)\]\[\large 6x=4x-24\] solve for x.

    • one year ago
  10. marissalovescats Group Title
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    No^^^ Its not 7^4. It's 7^2.

    • one year ago
  11. marissalovescats Group Title
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    I got -6/5 and I'll show you.

    • one year ago
  12. marissalovescats Group Title
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    |dw:1373139792425:dw|

    • one year ago
  13. Jhannybean Group Title
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    i changed it to the sae base.\(\sqrt{7}^4\)=49. and you've gotthe base \(\sqrt{7}\) on the left side.

    • one year ago
  14. Jhannybean Group Title
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    Tell me how you changed \(\large (\sqrt{7})^{6x}\) to just 7?

    • one year ago
  15. marissalovescats Group Title
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    I just figured because you square it. I've never done one like this. I was going out on a limb. But you are are correct because qroot7^4 is 49.

    • one year ago
  16. marissalovescats Group Title
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    So in that case it's -12 and not -6/5.

    • one year ago
  17. primeralph Group Title
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    @marissalovescats @Jhannybean Same thing.

    • one year ago
  18. primeralph Group Title
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    |dw:1373140157416:dw|

    • one year ago
  19. marissalovescats Group Title
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    Yes but the way she solved it was the correct way.

    • one year ago
  20. primeralph Group Title
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    |dw:1373140211718:dw|

    • one year ago
  21. primeralph Group Title
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    |dw:1373140263170:dw|

    • one year ago
  22. marissalovescats Group Title
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    I just put 7^2 because I knew you have to have like the same "base number" Or whatever.

    • one year ago
  23. primeralph Group Title
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    That 's if you want to use 7 and not sqrt(7)

    • one year ago
  24. Jhannybean Group Title
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    \[\large (\sqrt{7})^4 = 7^{4/2} = 7^2 \]

    • one year ago
  25. Jhannybean Group Title
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    Yeah....same thing.

    • one year ago
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