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KarolinaJosephine
 2 years ago
can anyone help with this? it seems like such a simple question but my brain just isn't grasping it.
in the US approximately one child in every 10,000 is born with phenylketonuria a syndrome that affects individuals homozygous for the recessive allele. given this incidence what percent of the population are heterozygous carriers of the recessive PKU allele? give answer to the nearest hundredth of a percent
KarolinaJosephine
 2 years ago
can anyone help with this? it seems like such a simple question but my brain just isn't grasping it. in the US approximately one child in every 10,000 is born with phenylketonuria a syndrome that affects individuals homozygous for the recessive allele. given this incidence what percent of the population are heterozygous carriers of the recessive PKU allele? give answer to the nearest hundredth of a percent

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aaronq
 2 years ago
Best ResponseYou've already chosen the best response.3The only equations you need for these types of problems: p + q =1 p = frequency of the dominant allele in the population q = frequency of the recessive allele in the population and p^2 + 2pq + q^2 =1 p^2 = percentage of homozygous dominant individuals q^2 = percentage of homozygous recessive individuals 2pq = percentage of heterozygous individuals

aaronq
 2 years ago
Best ResponseYou've already chosen the best response.3you know it's recessive and they give you a number of individuals, you can convert it to a percentage of homozygous recessive individuals (q^2). You're trying to find out what 2pq is.

aaronq
 2 years ago
Best ResponseYou've already chosen the best response.3p = frequency of the dominant allele in the population

KarolinaJosephine
 2 years ago
Best ResponseYou've already chosen the best response.0yes I know but I don't know what it is

aaronq
 2 years ago
Best ResponseYou've already chosen the best response.3that's the challenge in the question, if i told you the answer i wouldn't be of much help would i? use the formulas i wrote.

KarolinaJosephine
 2 years ago
Best ResponseYou've already chosen the best response.0but I don't know how. that's the reason I posted it.

KarolinaJosephine
 2 years ago
Best ResponseYou've already chosen the best response.0I have a paper with some equations on it so I have that but I don't know what to do with it

aaronq
 2 years ago
Best ResponseYou've already chosen the best response.3they gave you q^2 right? find q, since p+q=1 > p=1q

KarolinaJosephine
 2 years ago
Best ResponseYou've already chosen the best response.0I have \[p^{2}+2pq+q^{2}=1\] and p+q=1

aaronq
 2 years ago
Best ResponseYou've already chosen the best response.3look at the last thing i wrote

KarolinaJosephine
 2 years ago
Best ResponseYou've already chosen the best response.0wouldn't that give a negative number?

aaronq
 2 years ago
Best ResponseYou've already chosen the best response.3how? taking the squared root of the percentage of homozygous recessive individuals wouldn't give you a negative number.

KarolinaJosephine
 2 years ago
Best ResponseYou've already chosen the best response.0idk I'm all confused

aaronq
 2 years ago
Best ResponseYou've already chosen the best response.3what are you confused about? \[q ^{2}= a \to \sqrt{q ^{2}}=\sqrt{a}\] \[q = \sqrt{a}\]

KarolinaJosephine
 2 years ago
Best ResponseYou've already chosen the best response.0and how did you come up with that

aaronq
 2 years ago
Best ResponseYou've already chosen the best response.3it's math... one child in every 10,000 is born with phenylketonuria a syndrome that affects individuals homozygous.. q^2 = percentage of homozygous recessive individuals so solve for q, just take the squared root of both sides

KarolinaJosephine
 2 years ago
Best ResponseYou've already chosen the best response.0I'm about to say F it. I don't understand any of this.

aaronq
 2 years ago
Best ResponseYou've already chosen the best response.3so, you have q^2=1/10000 to solve for q, you take the squared root of both sides: \[q ^{2}=\frac{ 1 }{ 10000 } \to q=\sqrt{\frac{ 1 }{ 10000 }} \to q=0.01\] so p=1q = 0.99 2ab is the percentage of heterozygous individuals (i.e. carriers) 2(0.99)(0.01)= 0.0198 1.98 % Watch this video, i think he explains it well. http://www.youtube.com/watch?v=xPkOAnK20kw

KarolinaJosephine
 2 years ago
Best ResponseYou've already chosen the best response.0watched it. still confused.

asmagul
 2 years ago
Best ResponseYou've already chosen the best response.0you have to study genetics and hardy Weinberg theorem

KarolinaJosephine
 2 years ago
Best ResponseYou've already chosen the best response.0well I know that much.

aaronq
 2 years ago
Best ResponseYou've already chosen the best response.3what don't you understand?

aaronq
 2 years ago
Best ResponseYou've already chosen the best response.3reread the question and narrow down what you don't understand, i can't help you otherwise.

KarolinaJosephine
 2 years ago
Best ResponseYou've already chosen the best response.0I never said you alone had to help me.
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