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KarolinaJosephine
Group Title
can anyone help with this? it seems like such a simple question but my brain just isn't grasping it.
in the US approximately one child in every 10,000 is born with phenylketonuria a syndrome that affects individuals homozygous for the recessive allele. given this incidence what percent of the population are heterozygous carriers of the recessive PKU allele? give answer to the nearest hundredth of a percent
 one year ago
 one year ago
KarolinaJosephine Group Title
can anyone help with this? it seems like such a simple question but my brain just isn't grasping it. in the US approximately one child in every 10,000 is born with phenylketonuria a syndrome that affects individuals homozygous for the recessive allele. given this incidence what percent of the population are heterozygous carriers of the recessive PKU allele? give answer to the nearest hundredth of a percent
 one year ago
 one year ago

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aaronq Group TitleBest ResponseYou've already chosen the best response.3
The only equations you need for these types of problems: p + q =1 p = frequency of the dominant allele in the population q = frequency of the recessive allele in the population and p^2 + 2pq + q^2 =1 p^2 = percentage of homozygous dominant individuals q^2 = percentage of homozygous recessive individuals 2pq = percentage of heterozygous individuals
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.3
you know it's recessive and they give you a number of individuals, you can convert it to a percentage of homozygous recessive individuals (q^2). You're trying to find out what 2pq is.
 one year ago

KarolinaJosephine Group TitleBest ResponseYou've already chosen the best response.0
so what is p
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.3
p = frequency of the dominant allele in the population
 one year ago

KarolinaJosephine Group TitleBest ResponseYou've already chosen the best response.0
yes I know but I don't know what it is
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.3
that's the challenge in the question, if i told you the answer i wouldn't be of much help would i? use the formulas i wrote.
 one year ago

KarolinaJosephine Group TitleBest ResponseYou've already chosen the best response.0
but I don't know how. that's the reason I posted it.
 one year ago

KarolinaJosephine Group TitleBest ResponseYou've already chosen the best response.0
I have a paper with some equations on it so I have that but I don't know what to do with it
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.3
they gave you q^2 right? find q, since p+q=1 > p=1q
 one year ago

KarolinaJosephine Group TitleBest ResponseYou've already chosen the best response.0
I have \[p^{2}+2pq+q^{2}=1\] and p+q=1
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.3
look at the last thing i wrote
 one year ago

KarolinaJosephine Group TitleBest ResponseYou've already chosen the best response.0
wouldn't that give a negative number?
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.3
how? taking the squared root of the percentage of homozygous recessive individuals wouldn't give you a negative number.
 one year ago

KarolinaJosephine Group TitleBest ResponseYou've already chosen the best response.0
idk I'm all confused
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.3
what are you confused about? \[q ^{2}= a \to \sqrt{q ^{2}}=\sqrt{a}\] \[q = \sqrt{a}\]
 one year ago

KarolinaJosephine Group TitleBest ResponseYou've already chosen the best response.0
and how did you come up with that
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.3
it's math... one child in every 10,000 is born with phenylketonuria a syndrome that affects individuals homozygous.. q^2 = percentage of homozygous recessive individuals so solve for q, just take the squared root of both sides
 one year ago

KarolinaJosephine Group TitleBest ResponseYou've already chosen the best response.0
I'm about to say F it. I don't understand any of this.
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.3
so, you have q^2=1/10000 to solve for q, you take the squared root of both sides: \[q ^{2}=\frac{ 1 }{ 10000 } \to q=\sqrt{\frac{ 1 }{ 10000 }} \to q=0.01\] so p=1q = 0.99 2ab is the percentage of heterozygous individuals (i.e. carriers) 2(0.99)(0.01)= 0.0198 1.98 % Watch this video, i think he explains it well. http://www.youtube.com/watch?v=xPkOAnK20kw
 one year ago

KarolinaJosephine Group TitleBest ResponseYou've already chosen the best response.0
watched it. still confused.
 one year ago

asmagul Group TitleBest ResponseYou've already chosen the best response.0
you have to study genetics and hardy Weinberg theorem
 one year ago

KarolinaJosephine Group TitleBest ResponseYou've already chosen the best response.0
well I know that much.
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.3
what don't you understand?
 one year ago

KarolinaJosephine Group TitleBest ResponseYou've already chosen the best response.0
all of it
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.3
reread the question and narrow down what you don't understand, i can't help you otherwise.
 one year ago

KarolinaJosephine Group TitleBest ResponseYou've already chosen the best response.0
I never said you alone had to help me.
 one year ago
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