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can anyone help with this? it seems like such a simple question but my brain just isn't grasping it.
in the US approximately one child in every 10,000 is born with phenylketonuria a syndrome that affects individuals homozygous for the recessive allele. given this incidence what percent of the population are heterozygous carriers of the recessive PKU allele? give answer to the nearest hundredth of a percent
 9 months ago
 9 months ago
can anyone help with this? it seems like such a simple question but my brain just isn't grasping it. in the US approximately one child in every 10,000 is born with phenylketonuria a syndrome that affects individuals homozygous for the recessive allele. given this incidence what percent of the population are heterozygous carriers of the recessive PKU allele? give answer to the nearest hundredth of a percent
 9 months ago
 9 months ago

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aaronqBest ResponseYou've already chosen the best response.3
The only equations you need for these types of problems: p + q =1 p = frequency of the dominant allele in the population q = frequency of the recessive allele in the population and p^2 + 2pq + q^2 =1 p^2 = percentage of homozygous dominant individuals q^2 = percentage of homozygous recessive individuals 2pq = percentage of heterozygous individuals
 9 months ago

aaronqBest ResponseYou've already chosen the best response.3
you know it's recessive and they give you a number of individuals, you can convert it to a percentage of homozygous recessive individuals (q^2). You're trying to find out what 2pq is.
 9 months ago

KarolinaJosephineBest ResponseYou've already chosen the best response.0
so what is p
 9 months ago

aaronqBest ResponseYou've already chosen the best response.3
p = frequency of the dominant allele in the population
 9 months ago

KarolinaJosephineBest ResponseYou've already chosen the best response.0
yes I know but I don't know what it is
 9 months ago

aaronqBest ResponseYou've already chosen the best response.3
that's the challenge in the question, if i told you the answer i wouldn't be of much help would i? use the formulas i wrote.
 9 months ago

KarolinaJosephineBest ResponseYou've already chosen the best response.0
but I don't know how. that's the reason I posted it.
 9 months ago

KarolinaJosephineBest ResponseYou've already chosen the best response.0
I have a paper with some equations on it so I have that but I don't know what to do with it
 9 months ago

aaronqBest ResponseYou've already chosen the best response.3
they gave you q^2 right? find q, since p+q=1 > p=1q
 9 months ago

KarolinaJosephineBest ResponseYou've already chosen the best response.0
I have \[p^{2}+2pq+q^{2}=1\] and p+q=1
 9 months ago

aaronqBest ResponseYou've already chosen the best response.3
look at the last thing i wrote
 9 months ago

KarolinaJosephineBest ResponseYou've already chosen the best response.0
wouldn't that give a negative number?
 9 months ago

aaronqBest ResponseYou've already chosen the best response.3
how? taking the squared root of the percentage of homozygous recessive individuals wouldn't give you a negative number.
 9 months ago

KarolinaJosephineBest ResponseYou've already chosen the best response.0
idk I'm all confused
 9 months ago

aaronqBest ResponseYou've already chosen the best response.3
what are you confused about? \[q ^{2}= a \to \sqrt{q ^{2}}=\sqrt{a}\] \[q = \sqrt{a}\]
 9 months ago

KarolinaJosephineBest ResponseYou've already chosen the best response.0
and how did you come up with that
 9 months ago

aaronqBest ResponseYou've already chosen the best response.3
it's math... one child in every 10,000 is born with phenylketonuria a syndrome that affects individuals homozygous.. q^2 = percentage of homozygous recessive individuals so solve for q, just take the squared root of both sides
 9 months ago

KarolinaJosephineBest ResponseYou've already chosen the best response.0
I'm about to say F it. I don't understand any of this.
 9 months ago

aaronqBest ResponseYou've already chosen the best response.3
so, you have q^2=1/10000 to solve for q, you take the squared root of both sides: \[q ^{2}=\frac{ 1 }{ 10000 } \to q=\sqrt{\frac{ 1 }{ 10000 }} \to q=0.01\] so p=1q = 0.99 2ab is the percentage of heterozygous individuals (i.e. carriers) 2(0.99)(0.01)= 0.0198 1.98 % Watch this video, i think he explains it well. http://www.youtube.com/watch?v=xPkOAnK20kw
 9 months ago

KarolinaJosephineBest ResponseYou've already chosen the best response.0
watched it. still confused.
 9 months ago

asmagulBest ResponseYou've already chosen the best response.0
you have to study genetics and hardy Weinberg theorem
 9 months ago

KarolinaJosephineBest ResponseYou've already chosen the best response.0
well I know that much.
 9 months ago

aaronqBest ResponseYou've already chosen the best response.3
what don't you understand?
 9 months ago

aaronqBest ResponseYou've already chosen the best response.3
reread the question and narrow down what you don't understand, i can't help you otherwise.
 9 months ago

KarolinaJosephineBest ResponseYou've already chosen the best response.0
I never said you alone had to help me.
 9 months ago
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