Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

help me with some manometers here please. The fluid in a manometer tube is 40% water and 60% alcohol (specific gravity = 0.8). What is the manometer fluid height difference if a 50kPa pressure difference is applied across the two ends of manometer?

Physics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

I think alcohol and water are miscible (never tried though!). So we have to use average density of liquid.
that is what I am thinking as well. but my classmates insist that there is a height difference here and we can assume the two fluids to be immiscible.
if they are miscible, their height will be the same at both sides right?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

It would be complicated if they were immiscible. Also in that case we will have to know on which side pressure was applied - where there is alcohol on top or where there is water on top.
we can say that the water is going to at the bottom since the water is more dense than alcohol right?
|dw:1373287012937:dw|
\[avg \ density, \ d = (\rho _{w} * n _{w}+\rho_{a}*n_{a}) / 100\] where \( \rho_{w}\) is density of water = 1000 kg/\(m^{3}\) \(n_{w}\) is % of water present = 40% \(\rho_{a}\) = density of alcohol = 0.8 \(\rho_{w}\) = 800kg/m\(^{3}\) \(n_{a}\) = % of alcohol = 60% You will be able to calculate h from the formula i showed in the drawing above after using this value of d.
ok, ill try this one. lots of thanks.
i cant see the whole version of the picture, can u type the written words here?
Strange ,i can see it ! I have written (exact words) : "See that 'h' height of liquid will have to balance 50kPa pressure So 50 kPa= hdg where 'd' i average density of 40% water and 60% alcohol"
maybe my screen is not wide enough. thanks a lot again. :)
welcome!

Not the answer you are looking for?

Search for more explanations.

Ask your own question