anonymous
  • anonymous
help me with some manometers here please. The fluid in a manometer tube is 40% water and 60% alcohol (specific gravity = 0.8). What is the manometer fluid height difference if a 50kPa pressure difference is applied across the two ends of manometer?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
I think alcohol and water are miscible (never tried though!). So we have to use average density of liquid.
anonymous
  • anonymous
that is what I am thinking as well. but my classmates insist that there is a height difference here and we can assume the two fluids to be immiscible.
anonymous
  • anonymous
if they are miscible, their height will be the same at both sides right?

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anonymous
  • anonymous
It would be complicated if they were immiscible. Also in that case we will have to know on which side pressure was applied - where there is alcohol on top or where there is water on top.
anonymous
  • anonymous
we can say that the water is going to at the bottom since the water is more dense than alcohol right?
anonymous
  • anonymous
|dw:1373287012937:dw|
anonymous
  • anonymous
\[avg \ density, \ d = (\rho _{w} * n _{w}+\rho_{a}*n_{a}) / 100\] where \( \rho_{w}\) is density of water = 1000 kg/\(m^{3}\) \(n_{w}\) is % of water present = 40% \(\rho_{a}\) = density of alcohol = 0.8 \(\rho_{w}\) = 800kg/m\(^{3}\) \(n_{a}\) = % of alcohol = 60% You will be able to calculate h from the formula i showed in the drawing above after using this value of d.
anonymous
  • anonymous
ok, ill try this one. lots of thanks.
anonymous
  • anonymous
i cant see the whole version of the picture, can u type the written words here?
anonymous
  • anonymous
Strange ,i can see it ! I have written (exact words) : "See that 'h' height of liquid will have to balance 50kPa pressure So 50 kPa= hdg where 'd' i average density of 40% water and 60% alcohol"
anonymous
  • anonymous
maybe my screen is not wide enough. thanks a lot again. :)
anonymous
  • anonymous
welcome!

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