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thomaster
 one year ago
Best ResponseYou've already chosen the best response.0Find the vertex: \(\large y = 5x^2 + 4x + 9\)

JA1
 one year ago
Best ResponseYou've already chosen the best response.2Hello there user I have never met before, well you see first we need to know what the value of the terms are, so this is the standard equation: \[y = ax^{2} + bx + c\] so now we need to find out what A, B, and C are, so can you find that out for me?

thomaster
 one year ago
Best ResponseYou've already chosen the best response.0Omg thank you soo much for helping me! i've been waiting for hours! \(\Large\sf\color{#f2f2f2}{LOL}\) So A=5, B=4 and C=9?

JA1
 one year ago
Best ResponseYou've already chosen the best response.2Yes perfect, ok so now we can use this very special formula we use for finding the vertex: \[\frac{ b }{ 2(a) }\] So now can you substitute the numbers you got into this formula?

thomaster
 one year ago
Best ResponseYou've already chosen the best response.0\(\large\dfrac{ 4 }{ 2(5) }=\dfrac{4}{10}=\dfrac{2~~}{~5}~\huge?\)

thomaster
 one year ago
Best ResponseYou've already chosen the best response.0OMG OMG THANK YOU FOR TEACHING ME MASTER!!

JA1
 one year ago
Best ResponseYou've already chosen the best response.2No problem young padawan, I know it has been an honor to learn from me

uri
 one year ago
Best ResponseYou've already chosen the best response.0HAHAHAAHAHHAHAHAHAHAHHAHAHAHHAHAAHAHHAHAHAHAHAHHAHAHHAHAAHHAHAHAHAHAHAHAHAHAHAHAHAHAAHHAHAHAHAHAHAHAHAHAHAAHAHHAHAHAHAHAHAAHAHAHHAAHHAHAHAHAHAAHAHHAHAHAHAHAHHAHAHAHHAHAAHAHHAHAHAHAHAHHAHAHHAHAAHHAHAHAHAHAHAHAHAHAHAHAHAHAAHHAHAHAHAHAHAHAHAHAHAAHAHHAHAHAHAHAHAAHAHAHHAAHHAHAHAAHAHAHHAAHHAHAHAHAHAAHAHHAHAHAHAHAHHAHAHAHHAHAAHAHHAHAHAHAHAHHAHAHHAHAAHHAHAHAHAHAHAHAHAHAHAHAHAHAAHHAHAHAHAHAHAHAHAHAHAAHAHHAHAHAHAHAHAAHAHAHHAAHHAHA

Ejimdonalds
 2 months ago
Best ResponseYou've already chosen the best response.0mehn this is serious. you ve gat to be kidding me

Jaynator495
 11 minutes ago
Best ResponseYou've already chosen the best response.0was this before he was a mod? XD
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