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SNIIX18

A spacecraft's landing is cushioned by air bags. As it lands on Mars, the velocity of downward fall is 20 meters/second. Immediately after impact the velocity is 10 meters/second. If the spacecraft has a mass of 7.1 × 10^4 kilograms, what is the value of the impulse? A)1.2 x10^4 kilogram meters/second (B)2.2x10^5 kilogram meters/second (C)7.1x10^5 kilogram meters/second (D)3.6x10^4 kilogram meters/second

  • 9 months ago
  • 9 months ago

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  1. SNIIX18
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    @souvik

    • 9 months ago
  2. SNIIX18
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    @mr.singh

    • 9 months ago
  3. souvik
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    impulse=change in momentum... so find change in momentum

    • 9 months ago
  4. mr.singh
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    c

    • 9 months ago
  5. mr.singh
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    impulse=m(v-u)

    • 9 months ago
  6. SNIIX18
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    @souvik How do you do that and @mr.singh thank you it was right

    • 9 months ago
  7. souvik
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    that is.....mass*change in velocity

    • 9 months ago
  8. SNIIX18
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    oww okay grazie :)

    • 9 months ago
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