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SNIIX18

  • 2 years ago

A spacecraft's landing is cushioned by air bags. As it lands on Mars, the velocity of downward fall is 20 meters/second. Immediately after impact the velocity is 10 meters/second. If the spacecraft has a mass of 7.1 × 10^4 kilograms, what is the value of the impulse? A)1.2 x10^4 kilogram meters/second (B)2.2x10^5 kilogram meters/second (C)7.1x10^5 kilogram meters/second (D)3.6x10^4 kilogram meters/second

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  1. SNIIX18
    • 2 years ago
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    @souvik

  2. SNIIX18
    • 2 years ago
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    @mr.singh

  3. souvik
    • 2 years ago
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    impulse=change in momentum... so find change in momentum

  4. mr.singh
    • 2 years ago
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    c

  5. mr.singh
    • 2 years ago
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    impulse=m(v-u)

  6. SNIIX18
    • 2 years ago
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    @souvik How do you do that and @mr.singh thank you it was right

  7. souvik
    • 2 years ago
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    that is.....mass*change in velocity

  8. SNIIX18
    • 2 years ago
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    oww okay grazie :)

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