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A spacecraft's landing is cushioned by air bags. As it lands on Mars, the velocity of downward fall is 20 meters/second. Immediately after impact the velocity is 10 meters/second. If the spacecraft has a mass of 7.1 × 10^4 kilograms, what is the value of the impulse? A)1.2 x10^4 kilogram meters/second (B)2.2x10^5 kilogram meters/second (C)7.1x10^5 kilogram meters/second (D)3.6x10^4 kilogram meters/second

Physics
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@mr.singh
impulse=change in momentum... so find change in momentum

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Other answers:

c
impulse=m(v-u)
@souvik How do you do that and @mr.singh thank you it was right
that is.....mass*change in velocity
oww okay grazie :)

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