Here's the question you clicked on:
samigupta8
a monkey while trying to reach the top of a pole of height 12 metres takes every time a jump of 2 metres but slips 1 metre while holding the pole.the number of jumps required to reach the top of the ople is
The number of jumps required to reach the top of the pole is what?
exactly that's my question
Well so basically in other terms we can say that the monkey only jumps 1 meter every jump
Since every jump he moves up 2 meters but slips 1 meter which is 2-1=1
Oh haha I read that wrong!..Im sorry.. but swiss girl is right.
So we can model our equation as follow 2x-x=12 Or (2-1)x=12 and then solve for x
It takes 11 jumps. He won't slip from 12 to 11 on the last jump because he's already at the top. You are basically counting the elements in the following: 2, 3, 4, . . . , 12 which is 11 each element is the position before the slip but after the jump.
well, why would a monkey be jumping on a bare pole anyway? is not like it has figs or bananas, so really on every jump the monkey is wasting 2 meters plus momentum of eneergy :P
Hmmm I think tcarroll is correct
u r right tcarrol.....
thanks much. That was a fun problem! That monkey better get a better grip!