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here are the answer choices x = 5
x = 7
x = 13
x = 15

Well Lets try to isolate x
So first we subtract 50.001 from both sides
logx=-53.001

i typed it wrong, its base x+5 to the 0.001-3

Then we know that \( e^{ \log{x}} =x\)
So \( e^{ \log{x}}=e^{-53.001}\)

hmmmm
Can you retype it please cuz I dont think I am following?

better yet, draw it!

|dw:1373413752114:dw|

Seems like the base is x+5 not 10

ah, that's much different :-)

yaaaaaaaaaaaa

so it is asking us to find a value \(x\) such that \[(x+5)^{-3} = 0.001\]

Here's a hint: \[x^{-n} = \frac{1}{x^n}\] and \[0.001 = \frac{1}{1000}\]

yeah i understand that. so whats the final answer?

maybe work backwards — what number cubed gives you 1000?

x = 5
x = 7
x = 13
x = 15
would it be x=5

it would!
\[(5+5)^{-3} = 10^{-3} = \frac{1}{10^3} = \frac{1}{1000} = 0.001\]

thank you!!!

next time, please don't make us do a warm-up problem ;-)