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SNIIX18
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If the period of a pendulum is 2.0 seconds and the acceleration due to gravity is 9.8 meters/second^2, What is the length of the cord on the pendulum?
A)1.0 meters
B)0.67 meters
C)1.3 meters
D)3.5 meters
 one year ago
 one year ago
SNIIX18 Group Title
If the period of a pendulum is 2.0 seconds and the acceleration due to gravity is 9.8 meters/second^2, What is the length of the cord on the pendulum? A)1.0 meters B)0.67 meters C)1.3 meters D)3.5 meters
 one year ago
 one year ago

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SNIIX18 Group TitleBest ResponseYou've already chosen the best response.0
can you help me
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Are you speaking of a simple pendulum?
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Then you'll want the equation that uses math to describe the relationships between different physical quantities. I think I've show it to you before. I found it at http://hyperphysics.phyastr.gsu.edu/hbase/pend.html It is:\[T=2\pi\sqrt{\frac{L}{g}}\] \(T\) is the period. \(L\) is the length of the chord. \(g\) is the acceleration caused by gravity. You want to solve for \(L\).
 one year ago

SNIIX18 Group TitleBest ResponseYou've already chosen the best response.0
OKAY HOLD ON
 one year ago

SNIIX18 Group TitleBest ResponseYou've already chosen the best response.0
I GOT O.67 IS THAT RIGHT
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
It's not what I got! How did you solve for \(L\)?
 one year ago

SNIIX18 Group TitleBest ResponseYou've already chosen the best response.0
I squared 2 then i divided 2.0 by 9.8
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
I'm confused... Can you show me what you got? You squared the 2?
 one year ago

SNIIX18 Group TitleBest ResponseYou've already chosen the best response.0
now im confused cause your confused
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Haha, you start with \[T=2\pi\sqrt{\frac{L}{g}}\]Now, what did you square?
 one year ago

SNIIX18 Group TitleBest ResponseYou've already chosen the best response.0
owwww okay i see what i did wrong i was suppost to pi the 2 instead of square
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
I would divide the equation by \(2\pi\), square the equation, and multiply the equation by \(g\), if you know what I mean. Then you have \(L\) by itself after applicable cancelations, if you know what I mean.
 one year ago
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