anonymous
  • anonymous
Solve 2x2 - 8x = -7. I just want to know if my answer is correct. I got x=2+- 2 sqr 2
Mathematics
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anonymous
  • anonymous
Solve 2x2 - 8x = -7. I just want to know if my answer is correct. I got x=2+- 2 sqr 2
Mathematics
katieb
  • katieb
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swissgirl
  • swissgirl
\(2x^2-8x+7=0\) \(A=2, B=-8, C=7\) \(\large \frac{-(-8) \pm \sqrt{(-8)^2-4(2)(7)}}{2(2)}\) \(\large \frac{8 \pm \sqrt{64-56}}{4}\) \(\large \frac{8 \pm \sqrt{8}}{4}\) \(\large \frac{8 \pm 2\sqrt{2}}{4}\) \(\large \frac{4\pm \sqrt{2}}{2}\) OR \(\large 2\frac{\pm \sqrt{2}}{2}\)
swissgirl
  • swissgirl
hmmm are you sure this is the right equation?
anonymous
  • anonymous
oh sorry these are the answer choices: negative 2 plus or minus square root of 2 negative 2 plus or minus 2 square root of 2 quantity of 2 plus or minus square root of 2 all over 2 2 plus or minus square root of 2 end root over 2

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swissgirl
  • swissgirl
So what do you think?
anonymous
  • anonymous
im not sure I cant understand what you typed up there..haha
swissgirl
  • swissgirl
So how did you get your answer?
anonymous
  • anonymous
my own answer is x=2+-2 sqr 2
swissgirl
  • swissgirl
How did you get that?
anonymous
  • anonymous
its long in my notebook haha I just need to know if my answer is correct or not
swissgirl
  • swissgirl
Your answer is incorrect
swissgirl
  • swissgirl
Look at my answer above
anonymous
  • anonymous
OH it shows now! thanks! ill review it and find my mistake!
swissgirl
  • swissgirl
\( \large 2 \pm \frac{\sqrt{2}}{2}\)
anonymous
  • anonymous
Thanks!

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