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## anonymous 3 years ago Solve 2x2 - 8x = -7. I just want to know if my answer is correct. I got x=2+- 2 sqr 2

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1. anonymous

$$2x^2-8x+7=0$$ $$A=2, B=-8, C=7$$ $$\large \frac{-(-8) \pm \sqrt{(-8)^2-4(2)(7)}}{2(2)}$$ $$\large \frac{8 \pm \sqrt{64-56}}{4}$$ $$\large \frac{8 \pm \sqrt{8}}{4}$$ $$\large \frac{8 \pm 2\sqrt{2}}{4}$$ $$\large \frac{4\pm \sqrt{2}}{2}$$ OR $$\large 2\frac{\pm \sqrt{2}}{2}$$

2. anonymous

hmmm are you sure this is the right equation?

3. anonymous

oh sorry these are the answer choices: negative 2 plus or minus square root of 2 negative 2 plus or minus 2 square root of 2 quantity of 2 plus or minus square root of 2 all over 2 2 plus or minus square root of 2 end root over 2

4. anonymous

So what do you think?

5. anonymous

im not sure I cant understand what you typed up there..haha

6. anonymous

So how did you get your answer?

7. anonymous

my own answer is x=2+-2 sqr 2

8. anonymous

How did you get that?

9. anonymous

its long in my notebook haha I just need to know if my answer is correct or not

10. anonymous

Your answer is incorrect

11. anonymous

Look at my answer above

12. anonymous

OH it shows now! thanks! ill review it and find my mistake!

13. anonymous

$$\large 2 \pm \frac{\sqrt{2}}{2}$$

14. anonymous

Thanks!

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