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Solve 2x2 - 8x = -7. I just want to know if my answer is correct. I got x=2+- 2 sqr 2

Mathematics
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\(2x^2-8x+7=0\) \(A=2, B=-8, C=7\) \(\large \frac{-(-8) \pm \sqrt{(-8)^2-4(2)(7)}}{2(2)}\) \(\large \frac{8 \pm \sqrt{64-56}}{4}\) \(\large \frac{8 \pm \sqrt{8}}{4}\) \(\large \frac{8 \pm 2\sqrt{2}}{4}\) \(\large \frac{4\pm \sqrt{2}}{2}\) OR \(\large 2\frac{\pm \sqrt{2}}{2}\)
hmmm are you sure this is the right equation?
oh sorry these are the answer choices: negative 2 plus or minus square root of 2 negative 2 plus or minus 2 square root of 2 quantity of 2 plus or minus square root of 2 all over 2 2 plus or minus square root of 2 end root over 2

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Other answers:

So what do you think?
im not sure I cant understand what you typed up there..haha
So how did you get your answer?
my own answer is x=2+-2 sqr 2
How did you get that?
its long in my notebook haha I just need to know if my answer is correct or not
Your answer is incorrect
Look at my answer above
OH it shows now! thanks! ill review it and find my mistake!
\( \large 2 \pm \frac{\sqrt{2}}{2}\)
Thanks!

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