## ninashabrang Group Title Solve 2x2 - 8x = -7. I just want to know if my answer is correct. I got x=2+- 2 sqr 2 one year ago one year ago

1. swissgirl Group Title

$$2x^2-8x+7=0$$ $$A=2, B=-8, C=7$$ $$\large \frac{-(-8) \pm \sqrt{(-8)^2-4(2)(7)}}{2(2)}$$ $$\large \frac{8 \pm \sqrt{64-56}}{4}$$ $$\large \frac{8 \pm \sqrt{8}}{4}$$ $$\large \frac{8 \pm 2\sqrt{2}}{4}$$ $$\large \frac{4\pm \sqrt{2}}{2}$$ OR $$\large 2\frac{\pm \sqrt{2}}{2}$$

2. swissgirl Group Title

hmmm are you sure this is the right equation?

3. ninashabrang Group Title

oh sorry these are the answer choices: negative 2 plus or minus square root of 2 negative 2 plus or minus 2 square root of 2 quantity of 2 plus or minus square root of 2 all over 2 2 plus or minus square root of 2 end root over 2

4. swissgirl Group Title

So what do you think?

5. ninashabrang Group Title

im not sure I cant understand what you typed up there..haha

6. swissgirl Group Title

7. ninashabrang Group Title

my own answer is x=2+-2 sqr 2

8. swissgirl Group Title

How did you get that?

9. ninashabrang Group Title

its long in my notebook haha I just need to know if my answer is correct or not

10. swissgirl Group Title

11. swissgirl Group Title

12. ninashabrang Group Title

OH it shows now! thanks! ill review it and find my mistake!

13. swissgirl Group Title

$$\large 2 \pm \frac{\sqrt{2}}{2}$$

14. ninashabrang Group Title

Thanks!