anonymous
  • anonymous
On an exam, a class ended with a mean raw score of 80 with standard deviation of 10. The distribution of grades in the class was approximately normal. If the teacher wants to give "A" to the top 25th percentile (top 25%) of the class, what is the lowest raw score we could get and still get an "A" on the exam?
Probability
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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dan815
  • dan815
|dw:1373527655365:dw|
anonymous
  • anonymous
standard deviation of 10
dan815
  • dan815
lol i mean how many deviation points wud u have to travel, to be left with only 25% area on the right side

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More answers

dan815
  • dan815
look up the probability distribution graph numbers
anonymous
  • anonymous
Sorry sir, I could not follow you. Could you please explain
dan815
  • dan815
https://www.google.ca/search?gs_rn=17&gs_ri=psy-ab&tok=tEH_WKdK4z3EM3ono5y2dg&pq=probability+distribution&cp=27&gs_id=35&xhr=t&q=probability+distribution+chart&bav=on.2,or.r_qf.&bvm=bv.48705608,d.aWc&biw=1280&bih=897&um=1&ie=UTF-8&hl=en&tbm=isch&source=og&sa=N&tab=wi&ei=2GneUbvnMYWTyAH8HA#facrc=_&imgdii=_&imgrc=N1qZOwVnVPP-9M%3A%3B1jQwC4INkQn0OM%3Bhttp%253A%252F%252Fmathbits.com%252FMathBits%252FTISection%252FStatistics2%252FlabeledChart2.jpg%3Bhttp%253A%252F%252Fmathbits.com%252FMathBits%252FTISection%252FStatistics2%252Fnormaldistribution.htm%3B721%3B381
dan815
  • dan815
look at that and see at what standard deviation you have to be to be left with only 25% area on the right side
dan815
  • dan815
|dw:1373530622874:dw|
anonymous
  • anonymous
Is it 21% with 0.8 standard deviation?
anonymous
  • anonymous
It is only one standard deviation point above the mean is to be covered. Isn't it? Other please explain
dan815
  • dan815
|dw:1373533594767:dw|
dan815
  • dan815
how much more deviation does she have to go to cover upto 75%
dan815
  • dan815
look at that chart and figure it out
dan815
  • dan815
|dw:1373533703309:dw|
dan815
  • dan815
its somewhre inbetween 0.5 and 1
dan815
  • dan815
id say around 0.75
dan815
  • dan815
so 0.75 of 10 = ? 7.5 marks
dan815
  • dan815
then 87.5 should be the marks she needs to set it at
dan815
  • dan815
im just estimating values here, im sure u got some formulas to calculate the exact z values and stuff
dan815
  • dan815
|dw:1373533813410:dw|
anonymous
  • anonymous
This Z values I am not aware sir. I am just browsing about this
dan815
  • dan815
this will give u more accurate vlaue
dan815
  • dan815
|dw:1373533861018:dw|
dan815
  • dan815
|dw:1373533886859:dw|
dan815
  • dan815
|dw:1373533895795:dw|
dan815
  • dan815
|dw:1373533946389:dw|
dan815
  • dan815
|dw:1373533966949:dw|
dan815
  • dan815
|dw:1373533987799:dw|
anonymous
  • anonymous
|dw:1373534025223:dw|
anonymous
  • anonymous
what is this equation you have used
dan815
  • dan815
5.6/15
dan815
  • dan815
because
dan815
  • dan815
look at the chart
dan815
  • dan815
at 0.5 deviation on right how much percent have you covered?
anonymous
  • anonymous
and how did you get 0.37
dan815
  • dan815
do you know the answer already
anonymous
  • anonymous
????? 5*6/15=0.37 ????
dan815
  • dan815
whats the answer supposed to be
dan815
  • dan815
its 5.6 not 5 * 6
dan815
  • dan815
i cant help you if u arent answering my questions
anonymous
  • anonymous
No. Idon't know the answer
dan815
  • dan815
then dont bother with stuff
dan815
  • dan815
first understand the graph
anonymous
  • anonymous
I want to know more about this Z score
anonymous
  • anonymous
Ok sir
dan815
  • dan815
https://www.google.ca/search?gs_rn=17&gs_ri=psy-ab&tok=tEH_WKdK4z3EM3ono5y2dg&pq=probability+distribution&cp=27&gs_id=35&xhr=t&q=probability+distribution+chart&bav=on.2,or.r_qf.&bvm=bv.48705608,d.aWc&biw=1280&bih=897&um=1&ie=UTF-8&hl=en&tbm=isch&source=og&sa=N&tab=wi&ei=2GneUbvnMYWTyAH8HA#facrc=_&imgdii=_&imgrc=N1qZOwVnVPP-9M%3A%3B1jQwC4INkQn0OM%3Bhttp%253A%252F%252Fmathbits.com%252FMathBits%252FTISection%252FStatistics2%252FlabeledChart2.jpg%3Bhttp%253A%252F%252Fmathbits.com%252FMathBits%252FTISection%252FStatistics2%252Fnormaldistribution.htm%3B721%3B381
dan815
  • dan815
the graph is pretty self explanatory and questions about it?
dan815
  • dan815
any questions?
anonymous
  • anonymous
just a second sir,
anonymous
  • anonymous
Now it is clear. But one question. May I ask
anonymous
  • anonymous
Why did you divide by 15. It is only 14 parts. Right
anonymous
  • anonymous
Sorry. Now I have fully understood.
anonymous
  • anonymous
It is not the 14 parts. It is the area of that part.
anonymous
  • anonymous
Thank you very much explaining in detailed manner
anonymous
  • anonymous
Thanks for your patience and analysing for a lehman.
anonymous
  • anonymous
Mean 80 standard deviation 10 z=-0.67 X=73.3
anonymous
  • anonymous
mine answer is 73.3 marks min to get A
anonymous
  • anonymous
you have to take Z value -0.67
dan815
  • dan815
musadiq no try taking 0.67 Z
anonymous
  • anonymous
well table value is 0.67 that's lies at left side !

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