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anonymous
 3 years ago
Given: AG and CI are common internal tangents of .H and .B, HG =7, ED=18, and ED=EF. What is the measure of EC?@
anonymous
 3 years ago
Given: AG and CI are common internal tangents of .H and .B, HG =7, ED=18, and ED=EF. What is the measure of EC?@

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@RadEn CAN YOU HELP ME PLZ

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.1EC = EI (let be x) HI = HF = HG = radius = 7 EH = FE + HF = 18+7 = 25 look at the triangle of HIE (it is a right triangle), use the pythagorean theorem to get EI so, EI^2 = EH^2  HI^2 EI^2 = 25^2  7^2 solve for HI

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.1i already supposed EI be x so, x^2 = 25^2  7^2 solve for x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0BUTI DONT KNOW THE MEASUREMENTS ARE THEY THE ONES YOU GAVE ME 7, AND 25

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.1from information above, HG = 7 nah, HI = HF = HG = radius = 7

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.1EI^2 = 25^2  7^2 EI^2 = 625  49 EI^2 = 576 EI = sqrt(576) = 24

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.1because EC = EI so, EC = 24

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0HOLD UP BUT HOW DID YOU GET 625

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.125^2 = 25 x 25 = 625 note : ^ sign means square

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0LOL IKNOW AND THANK YOU SO MUCH I LEARNED ALOT TODAY MY HEAD IS ACCTUALLY GOING TO BLOW UP :)

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.1you're welcome dont eat to more :) wkkkkkkkk
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