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 one year ago
Given: AG and CI are common internal tangents of .H and .B, HG =7, ED=18, and ED=EF. What is the measure of EC?@
 one year ago
Given: AG and CI are common internal tangents of .H and .B, HG =7, ED=18, and ED=EF. What is the measure of EC?@

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SNIIX18
 one year ago
Best ResponseYou've already chosen the best response.0@RadEn CAN YOU HELP ME PLZ

RadEn
 one year ago
Best ResponseYou've already chosen the best response.1EC = EI (let be x) HI = HF = HG = radius = 7 EH = FE + HF = 18+7 = 25 look at the triangle of HIE (it is a right triangle), use the pythagorean theorem to get EI so, EI^2 = EH^2  HI^2 EI^2 = 25^2  7^2 solve for HI

RadEn
 one year ago
Best ResponseYou've already chosen the best response.1i already supposed EI be x so, x^2 = 25^2  7^2 solve for x

SNIIX18
 one year ago
Best ResponseYou've already chosen the best response.0BUTI DONT KNOW THE MEASUREMENTS ARE THEY THE ONES YOU GAVE ME 7, AND 25

RadEn
 one year ago
Best ResponseYou've already chosen the best response.1from information above, HG = 7 nah, HI = HF = HG = radius = 7

RadEn
 one year ago
Best ResponseYou've already chosen the best response.1EI^2 = 25^2  7^2 EI^2 = 625  49 EI^2 = 576 EI = sqrt(576) = 24

RadEn
 one year ago
Best ResponseYou've already chosen the best response.1because EC = EI so, EC = 24

SNIIX18
 one year ago
Best ResponseYou've already chosen the best response.0HOLD UP BUT HOW DID YOU GET 625

RadEn
 one year ago
Best ResponseYou've already chosen the best response.125^2 = 25 x 25 = 625 note : ^ sign means square

SNIIX18
 one year ago
Best ResponseYou've already chosen the best response.0LOL IKNOW AND THANK YOU SO MUCH I LEARNED ALOT TODAY MY HEAD IS ACCTUALLY GOING TO BLOW UP :)

RadEn
 one year ago
Best ResponseYou've already chosen the best response.1you're welcome dont eat to more :) wkkkkkkkk
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