anonymous
  • anonymous
Given: AG and CI are common internal tangents of .H and .B, HG =7, ED=18, and ED=EF. What is the measure of EC?@
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@RadEn CAN YOU HELP ME PLZ
RadEn
  • RadEn
EC = EI (let be x) HI = HF = HG = radius = 7 EH = FE + HF = 18+7 = 25 look at the triangle of HIE (it is a right triangle), use the pythagorean theorem to get EI so, EI^2 = EH^2 - HI^2 EI^2 = 25^2 - 7^2 solve for HI

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RadEn
  • RadEn
i mean solve for EI
RadEn
  • RadEn
i already supposed EI be x so, x^2 = 25^2 - 7^2 solve for x
anonymous
  • anonymous
BUTI DONT KNOW THE MEASUREMENTS ARE THEY THE ONES YOU GAVE ME 7, AND 25
RadEn
  • RadEn
from information above, HG = 7 nah, HI = HF = HG = radius = 7
anonymous
  • anonymous
I GOT 674
RadEn
  • RadEn
still wrong
RadEn
  • RadEn
EI^2 = 25^2 - 7^2 EI^2 = 625 - 49 EI^2 = 576 EI = sqrt(576) = 24
RadEn
  • RadEn
because EC = EI so, EC = 24
anonymous
  • anonymous
HOLD UP BUT HOW DID YOU GET 625
RadEn
  • RadEn
25^2 = 25 x 25 = 625 note : ^ sign means square
RadEn
  • RadEn
7^2 = 7 * 7 = 49
anonymous
  • anonymous
LOL IKNOW AND THANK YOU SO MUCH I LEARNED ALOT TODAY MY HEAD IS ACCTUALLY GOING TO BLOW UP :)
RadEn
  • RadEn
you're welcome dont eat to more :) wkkkkkkkk

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