Given: AG and CI are common internal tangents of .H and .B, HG =7, ED=18, and ED=EF. What is the measure of EC?@

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Given: AG and CI are common internal tangents of .H and .B, HG =7, ED=18, and ED=EF. What is the measure of EC?@

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

@RadEn CAN YOU HELP ME PLZ
EC = EI (let be x) HI = HF = HG = radius = 7 EH = FE + HF = 18+7 = 25 look at the triangle of HIE (it is a right triangle), use the pythagorean theorem to get EI so, EI^2 = EH^2 - HI^2 EI^2 = 25^2 - 7^2 solve for HI

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

i mean solve for EI
i already supposed EI be x so, x^2 = 25^2 - 7^2 solve for x
BUTI DONT KNOW THE MEASUREMENTS ARE THEY THE ONES YOU GAVE ME 7, AND 25
from information above, HG = 7 nah, HI = HF = HG = radius = 7
I GOT 674
still wrong
EI^2 = 25^2 - 7^2 EI^2 = 625 - 49 EI^2 = 576 EI = sqrt(576) = 24
because EC = EI so, EC = 24
HOLD UP BUT HOW DID YOU GET 625
25^2 = 25 x 25 = 625 note : ^ sign means square
7^2 = 7 * 7 = 49
LOL IKNOW AND THANK YOU SO MUCH I LEARNED ALOT TODAY MY HEAD IS ACCTUALLY GOING TO BLOW UP :)
you're welcome dont eat to more :) wkkkkkkkk

Not the answer you are looking for?

Search for more explanations.

Ask your own question