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douglas12
 2 years ago
Use natural logarithms to solve the equation. Round to the nearest thousandth.
5e^2x+8=22
A. 0.515
B. 0.264
C. 0.896
D. –3.259
douglas12
 2 years ago
Use natural logarithms to solve the equation. Round to the nearest thousandth. 5e^2x+8=22 A. 0.515 B. 0.264 C. 0.896 D. –3.259

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dan815
 2 years ago
Best ResponseYou've already chosen the best response.0what are you having trouble with

campbell_st
 2 years ago
Best ResponseYou've already chosen the best response.0is the question \[5e^{2x + 8} = 22\] or \[5 e^{2x} + 8 = 22\]

campbell_st
 2 years ago
Best ResponseYou've already chosen the best response.0ok... so the 1st step is subtract 8 from both sides of the equation. then divide both sides of the equation by 5 what do you get?

dan815
 2 years ago
Best ResponseYou've already chosen the best response.0you must use ln to cancel e

dan815
 2 years ago
Best ResponseYou've already chosen the best response.0so if you have log of base e of somethinh e to power something then the power must be your simplification

jdoe0001
 2 years ago
Best ResponseYou've already chosen the best response.0$$ \large { \text{log cancellation rule}\\ \color{blue}{log_aa^x = x}\\ e^{2x} = whatever\\ ln = log_e\\ log_e(e^{2x}) = log_e(whatever)\\ 2x = log_e(whatever) } $$
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