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Use natural logarithms to solve the equation. Round to the nearest thousandth.
5e^2x+8=22
A. 0.515
B. 0.264
C. 0.896
D. –3.259
 9 months ago
 9 months ago
Use natural logarithms to solve the equation. Round to the nearest thousandth. 5e^2x+8=22 A. 0.515 B. 0.264 C. 0.896 D. –3.259
 9 months ago
 9 months ago

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dan815Best ResponseYou've already chosen the best response.0
what are you having trouble with
 9 months ago

campbell_stBest ResponseYou've already chosen the best response.0
is the question \[5e^{2x + 8} = 22\] or \[5 e^{2x} + 8 = 22\]
 9 months ago

campbell_stBest ResponseYou've already chosen the best response.0
ok... so the 1st step is subtract 8 from both sides of the equation. then divide both sides of the equation by 5 what do you get?
 9 months ago

dan815Best ResponseYou've already chosen the best response.0
you must use ln to cancel e
 9 months ago

dan815Best ResponseYou've already chosen the best response.0
so if you have log of base e of somethinh e to power something then the power must be your simplification
 9 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
$$ \large { \text{log cancellation rule}\\ \color{blue}{log_aa^x = x}\\ e^{2x} = whatever\\ ln = log_e\\ log_e(e^{2x}) = log_e(whatever)\\ 2x = log_e(whatever) } $$
 9 months ago
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