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 one year ago
Assume that the reading on the thermometers are normally distributed with a mean of 0 and standard deviation of 1.00 celsius. a thermometer is randomly selected and tested. Find the temperature reading corresponding to P98, the 98th percentil. this is the temperature reading separating the bottom 98% from the top 2%. Using the standard distribution table.
 one year ago
Assume that the reading on the thermometers are normally distributed with a mean of 0 and standard deviation of 1.00 celsius. a thermometer is randomly selected and tested. Find the temperature reading corresponding to P98, the 98th percentil. this is the temperature reading separating the bottom 98% from the top 2%. Using the standard distribution table.

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genius12
 one year ago
Best ResponseYou've already chosen the best response.0Note that the percentile position is calculated by:\[\bf P_n=\frac{n( x+1) }{ 100 }\]Where n is the percentile you're finding, x is the total number of frequencies and Pn is the position of that corresponding percentile in the data set.

sky12
 one year ago
Best ResponseYou've already chosen the best response.0Ok but this is with the standard distribution table. I just dont know how to do it. Can you put the numbers in the formula so I can see? I don't know how to figure out the problem but somehow you use the standard distribution table.

genius12
 one year ago
Best ResponseYou've already chosen the best response.0OK so P98 would look like this:\[\bf P_{98}=\frac{ 98(x+1) }{ 100 }\]Now plug in the total number of data values that you have for 'x' and then evaluate. The resulting answer will give you P98, which is the position of the value under which 98% of the data falls. @sky12
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