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sky12 Group Title

Assume that the reading on the thermometers are normally distributed with a mean of 0 and standard deviation of 1.00 celsius. a thermometer is randomly selected and tested. Find the temperature reading corresponding to P98, the 98th percentil. this is the temperature reading separating the bottom 98% from the top 2%. Using the standard distribution table.

  • one year ago
  • one year ago

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  1. genius12 Group Title
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    Note that the percentile position is calculated by:\[\bf P_n=\frac{n( x+1) }{ 100 }\]Where n is the percentile you're finding, x is the total number of frequencies and Pn is the position of that corresponding percentile in the data set.

    • one year ago
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    @sky12

    • one year ago
  3. sky12 Group Title
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    Ok but this is with the standard distribution table. I just dont know how to do it. Can you put the numbers in the formula so I can see? I don't know how to figure out the problem but somehow you use the standard distribution table.

    • one year ago
  4. sky12 Group Title
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    @genius12

    • one year ago
  5. genius12 Group Title
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    OK so P98 would look like this:\[\bf P_{98}=\frac{ 98(x+1) }{ 100 }\]Now plug in the total number of data values that you have for 'x' and then evaluate. The resulting answer will give you P98, which is the position of the value under which 98% of the data falls. @sky12

    • one year ago
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