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 one year ago
The equation below gives the height h of a passenger on a Ferris wheel at any time t during the ride to be
h = 137 − 122 cos (π/10)t
where h is given in feet and t is given in minutes. Use this equation to find the times at which a passenger will be 120 feet above the ground during the first revolution.
I found the first time, which is about 4.5, but I'm confused on how to find the second time.
 one year ago
The equation below gives the height h of a passenger on a Ferris wheel at any time t during the ride to be h = 137 − 122 cos (π/10)t where h is given in feet and t is given in minutes. Use this equation to find the times at which a passenger will be 120 feet above the ground during the first revolution. I found the first time, which is about 4.5, but I'm confused on how to find the second time.

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robz8
 one year ago
Best ResponseYou've already chosen the best response.0are you familiar with the unit circle? the are 2 quadrants in the unit circle which cos(t) is positive

itsonlycdeee
 one year ago
Best ResponseYou've already chosen the best response.0Yes, the 1st quadrant and the 4th quadrant.

robz8
 one year ago
Best ResponseYou've already chosen the best response.0is t inside or outside of the cos?

robz8
 one year ago
Best ResponseYou've already chosen the best response.0are you sure?, because then h = 137 − 122 cos (π/10)t would be linear, meaning there is only 1 time h = 120

itsonlycdeee
 one year ago
Best ResponseYou've already chosen the best response.0Oh, then inside does make more sense.

robz8
 one year ago
Best ResponseYou've already chosen the best response.0120 = 137 − 122 cos (π/10*t) 17 = 112 cos(π/10*t) 17/112 = cos(pi/10*t) \[\cos^{1} (17/112) = \frac{ \pi }{ 10 }t\]

itsonlycdeee
 one year ago
Best ResponseYou've already chosen the best response.0Thank you I just figured it out!
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