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The equation below gives the height h of a passenger on a Ferris wheel at any time t during the ride to be
h = 137 − 122 cos (π/10)t
where h is given in feet and t is given in minutes. Use this equation to find the times at which a passenger will be 120 feet above the ground during the first revolution.
I found the first time, which is about 4.5, but I'm confused on how to find the second time.
 9 months ago
 9 months ago
The equation below gives the height h of a passenger on a Ferris wheel at any time t during the ride to be h = 137 − 122 cos (π/10)t where h is given in feet and t is given in minutes. Use this equation to find the times at which a passenger will be 120 feet above the ground during the first revolution. I found the first time, which is about 4.5, but I'm confused on how to find the second time.
 9 months ago
 9 months ago

This Question is Closed

robz8Best ResponseYou've already chosen the best response.0
are you familiar with the unit circle? the are 2 quadrants in the unit circle which cos(t) is positive
 9 months ago

itsonlycdeeeBest ResponseYou've already chosen the best response.0
Yes, the 1st quadrant and the 4th quadrant.
 9 months ago

robz8Best ResponseYou've already chosen the best response.0
is t inside or outside of the cos?
 9 months ago

robz8Best ResponseYou've already chosen the best response.0
are you sure?, because then h = 137 − 122 cos (π/10)t would be linear, meaning there is only 1 time h = 120
 9 months ago

itsonlycdeeeBest ResponseYou've already chosen the best response.0
Oh, then inside does make more sense.
 9 months ago

robz8Best ResponseYou've already chosen the best response.0
120 = 137 − 122 cos (π/10*t) 17 = 112 cos(π/10*t) 17/112 = cos(pi/10*t) \[\cos^{1} (17/112) = \frac{ \pi }{ 10 }t\]
 9 months ago

itsonlycdeeeBest ResponseYou've already chosen the best response.0
Thank you I just figured it out!
 9 months ago
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