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Which conditional and its converse are both true? If x = 3, then x2 = 6. If x = 2, then x2 = 4. If x2 = 4, then x = 2. If x = 1, then 2x = 2. - i think its C but i dont know

Mathematics
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B and D are both correct... in case of C If x2 = 4, then x = +2,-2 which is not an option
im confused
Let's look at each one. A. If x = 3, then x2 = 6. Is this true?

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Other answers:

you;re confused about C or B and D?
What is \(3^2 =\)
c
im confuced a bout c
C. If \(x^2 = 4\), what can x =? What numbers squared = 4?
C says If x2 = 4, then x = 2. which is incorrect \[x=\sqrt{4}=+2 , -2\]
\[(-2)^{2}=2^{2}=4\] remember?
ok well idk if my are just tried but it look to me that a is correct
A can't be right... see If x = 3, then x^2=3^2=9 while A says If x = 3, then x^2 = 6.
then which one is correct
nm b is correct
thank you guys
You're not done.
For each conditional, you need to see if both the conditional and its converse are true. Let's start with A.: If x = 3, x^2 = 6. This is false since 3^2 = 9, so if x = 3, x^2 = 9 not 6. Here the conditinal is false, so there is no need to check the converse.
B. If x = 2, then x2 = 4. This conditional is true. If x = 2, 2^2 = 4. Now we need to check the converse. If x^2 = 4, then x = 2. This converse is false. If x^2 = 4, then x = -2 or +2. For B. the conditional was true but the converse was false. So B. is not the answer.
C. If x2 = 4, then x = 2. If x^2 = 4, then x = -2 or +2. This conditional is false, so there is no need to check its converse.
D. If x = 1, then 2x = 2. This conditional is true. If x = 1, then 2x = 2(1) = 2, or you can multiply both sides by2 to get 2x = 2. Now let's check the converse: If 2x = 2, then x = 1. We divide both sides by 2, to get: x = 1. The converse is also true. The answer is D. because that is the only conditional that is true , and its converse is also true.
ok i get it thank you for explaining
wlcm

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