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UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2\[\newcommand\p\newcommand \p\dd [1] {\,\mathrm d#1} % infinitesimal \p\ve [1] {\boldsymbol#1} % vector \p\ints [3] {\int_{#1}{\dd #3}{#2}} % integral \p\dif {\operatorname\nabla} % differential operator \large{\begin{align} \frac 1{v(E)}&\frac{\dd\Phi(\ve r,E,\ve \Omega,t)}{\dd t}\\= &\ve\Omega\cdot\dif\Phi(\ve r,E,\ve\Omega,t)\Sigma_t(\ve r,E,\ve \Omega)\Phi(\ve r,E,\ve\Omega,t)\\ &+\chi(E)\ints{E'}{}{E}\ints{\Omega'}{\nu\Sigma_f(\ve r,E',\ve\Omega',t)}{\Omega'}\Phi(\ve r,E',\ve\Omega',t)\\ &+\ints{E'}{}{E'}\ints{\Omega'}{\Sigma_s(\ve r;E'\to E;\ve\Omega'\to\ve\Omega)\Phi(\ve r,E',\Omega',t)}{\Omega'} \end{align}}\]

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.0\[ \LARGE \mathbb{\color{green}{AWESOME} \huge \star}\]
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