santiagosoto
Factor completely: 2x3 + 6x2 + 2x + 6
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SnuggieLad
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Well, this is going to be a fun one.

santiagosoto
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Great :)

santiagosoto
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Hello?


SnuggieLad
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Read that.

ivettef365
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you can divide it in 2 parts as follows:
(2x^3+6x^2) + (2x+6) then simplify

ivettef365
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you get
2x^2(x+3)+2(x+3)

ivettef365
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that is equal to
(2x^2+2)(x+3)

santiagosoto
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What happens to the GCF?

santiagosoto
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ok, so @SnuggieLad, would this be it, 2[(x + 3)(x2 + 1)]

ivettef365
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no, the GCF could be
2x^2(x+3)+2(x+3)

SnuggieLad
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Ive you got this one.

santiagosoto
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@ivettef365, how? Not all of the constants or coefficients have the x^2

ivettef365
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that is why it needs to be divided in two parts, otherwise the GCF for the whole problem would be 2

santiagosoto
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Which is what I thought.

ivettef365
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and then you have
2(x^3+3x^2+x+3)

ivettef365
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but the question asks to factor completely

santiagosoto
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Yea, so when you factor everything don't you get 2[(x + 3)(x2 + 1)] so when you distribute you get the original problem.