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anonymous
 2 years ago
Factor completely: 2x3 + 6x2 + 2x + 6
I will award medals
anonymous
 2 years ago
Factor completely: 2x3 + 6x2 + 2x + 6 I will award medals

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SnuggieLad
 2 years ago
Best ResponseYou've already chosen the best response.1Well, this is going to be a fun one.

ivettef365
 2 years ago
Best ResponseYou've already chosen the best response.1you can divide it in 2 parts as follows: (2x^3+6x^2) + (2x+6) then simplify

ivettef365
 2 years ago
Best ResponseYou've already chosen the best response.1you get 2x^2(x+3)+2(x+3)

ivettef365
 2 years ago
Best ResponseYou've already chosen the best response.1that is equal to (2x^2+2)(x+3)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0What happens to the GCF?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0ok, so @SnuggieLad, would this be it, 2[(x + 3)(x2 + 1)]

ivettef365
 2 years ago
Best ResponseYou've already chosen the best response.1no, the GCF could be 2x^2(x+3)+2(x+3)

SnuggieLad
 2 years ago
Best ResponseYou've already chosen the best response.1Ive you got this one.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0@ivettef365, how? Not all of the constants or coefficients have the x^2

ivettef365
 2 years ago
Best ResponseYou've already chosen the best response.1that is why it needs to be divided in two parts, otherwise the GCF for the whole problem would be 2

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Which is what I thought.

ivettef365
 2 years ago
Best ResponseYou've already chosen the best response.1and then you have 2(x^3+3x^2+x+3)

ivettef365
 2 years ago
Best ResponseYou've already chosen the best response.1but the question asks to factor completely

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Yea, so when you factor everything don't you get 2[(x + 3)(x2 + 1)] so when you distribute you get the original problem.
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