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santiagosoto

  • 2 years ago

Factor completely: 2x3 + 6x2 + 2x + 6 I will award medals

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  1. SnuggieLad
    • 2 years ago
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    Well, this is going to be a fun one.

  2. santiagosoto
    • 2 years ago
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    Great :)

  3. santiagosoto
    • 2 years ago
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    Hello?

  4. SnuggieLad
    • 2 years ago
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    http://www.purplemath.com/modules/factquad4.htm

  5. SnuggieLad
    • 2 years ago
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    Read that.

  6. ivettef365
    • 2 years ago
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    you can divide it in 2 parts as follows: (2x^3+6x^2) + (2x+6) then simplify

  7. ivettef365
    • 2 years ago
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    you get 2x^2(x+3)+2(x+3)

  8. ivettef365
    • 2 years ago
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    that is equal to (2x^2+2)(x+3)

  9. santiagosoto
    • 2 years ago
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    What happens to the GCF?

  10. santiagosoto
    • 2 years ago
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    ok, so @SnuggieLad, would this be it, 2[(x + 3)(x2 + 1)]

  11. ivettef365
    • 2 years ago
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    no, the GCF could be 2x^2(x+3)+2(x+3)

  12. SnuggieLad
    • 2 years ago
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    Ive you got this one.

  13. santiagosoto
    • 2 years ago
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    @ivettef365, how? Not all of the constants or coefficients have the x^2

  14. ivettef365
    • 2 years ago
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    that is why it needs to be divided in two parts, otherwise the GCF for the whole problem would be 2

  15. santiagosoto
    • 2 years ago
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    Which is what I thought.

  16. ivettef365
    • 2 years ago
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    and then you have 2(x^3+3x^2+x+3)

  17. ivettef365
    • 2 years ago
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    but the question asks to factor completely

  18. santiagosoto
    • 2 years ago
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    Yea, so when you factor everything don't you get 2[(x + 3)(x2 + 1)] so when you distribute you get the original problem.

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