anonymous
  • anonymous
Factor completely: 2x3 + 6x2 + 2x + 6 I will award medals
Mathematics
schrodinger
  • schrodinger
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SnuggieLad
  • SnuggieLad
Well, this is going to be a fun one.
anonymous
  • anonymous
Great :)
anonymous
  • anonymous
Hello?

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SnuggieLad
  • SnuggieLad
http://www.purplemath.com/modules/factquad4.htm
SnuggieLad
  • SnuggieLad
Read that.
ivettef365
  • ivettef365
you can divide it in 2 parts as follows: (2x^3+6x^2) + (2x+6) then simplify
ivettef365
  • ivettef365
you get 2x^2(x+3)+2(x+3)
ivettef365
  • ivettef365
that is equal to (2x^2+2)(x+3)
anonymous
  • anonymous
What happens to the GCF?
anonymous
  • anonymous
ok, so @SnuggieLad, would this be it, 2[(x + 3)(x2 + 1)]
ivettef365
  • ivettef365
no, the GCF could be 2x^2(x+3)+2(x+3)
SnuggieLad
  • SnuggieLad
Ive you got this one.
anonymous
  • anonymous
@ivettef365, how? Not all of the constants or coefficients have the x^2
ivettef365
  • ivettef365
that is why it needs to be divided in two parts, otherwise the GCF for the whole problem would be 2
anonymous
  • anonymous
Which is what I thought.
ivettef365
  • ivettef365
and then you have 2(x^3+3x^2+x+3)
ivettef365
  • ivettef365
but the question asks to factor completely
anonymous
  • anonymous
Yea, so when you factor everything don't you get 2[(x + 3)(x2 + 1)] so when you distribute you get the original problem.

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