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jakethekicker
Group Title
Which of the following is a possible equivalence that can be used in a conversion?
ten cubed kL over one L
ten squared daL over one L
ten to the negative second power L over one cL
ten to the negative first power L over one mL
 one year ago
 one year ago
jakethekicker Group Title
Which of the following is a possible equivalence that can be used in a conversion? ten cubed kL over one L ten squared daL over one L ten to the negative second power L over one cL ten to the negative first power L over one mL
 one year ago
 one year ago

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Claflamme3 Group TitleBest ResponseYou've already chosen the best response.0
Let me look this one up
 one year ago

Claflamme3 Group TitleBest ResponseYou've already chosen the best response.0
the third one
 one year ago

mr.singh Group TitleBest ResponseYou've already chosen the best response.0
agree with @Claflamme3
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.1
Hi! You have your answer, which I agree with, but I want to explain how you'd know that! Firstly, when you convert to a different unit, the value  what the number represents  doesn't change. You're actually multiplying the number by \(1\). Its a fraction, where the top and bottom are equal. I'll derive a simple conversion that I hope you agree with. Even if you're in the stubborn U.S., it's important to know the metric system. Like, 1 meter is one hundred centimters. In math, \(1\ [m]=100\ [cm]\) This would imply that, by dividing by 1 meter,\[\frac{1\ [m]}{1\ [m]}=\frac{100\ [cm]}{1\ [m]}\]\[\qquad\qquad\Downarrow\]\[\frac{\cancel{1\ [m]}}{\cancel{1\ [m]}}=\frac{100\ [cm]}{1\ [m]}\]\[\qquad\qquad\Downarrow\]\[1=\frac{100\ [cm]}{1\ [m]}\] That sort of thing is always good to know for unit conversions. And reversing that on your multiple choices will check to see if they are good! \[\frac{10^3\ [kL]}{[L]}\qquad\rightarrow\qquad 10^3\ [kL]\overset{?}{=}[L]\] \[\frac{10^2\ [daL]}{[L]}\qquad\rightarrow\qquad 10^2\ [daL]\overset{?}{=}[L]\] \[\frac{10^{2}\ [L]}{[cL]}\qquad\rightarrow\qquad 10^{2}\ [L]\overset{?}{=}[cL]\] \[\frac{10^{1}\ [L]}{[mL]}\qquad\rightarrow\qquad 10^{1}\ [L]\overset{?}{=}[mL]\] And note that \(\Large 10^{1}=\frac{1}{10^1}\) and that \(\Large 10^{2}=\frac{1}{10^2}\), just by the meaning of negative exponents. Just for my own fun... \[\frac{10^3\ [kL]}{[L]}\qquad\rightarrow\qquad 10^3\ [kL]\cancel{=}[L]\] \[\frac{10^2\ [daL]}{[L]}\qquad\rightarrow\qquad 10^2\ [daL]\cancel{=}[L]\] \[\frac{10^{2}\ [L]}{[cL]}\qquad\rightarrow\qquad 10^{2}\ [L]{=}[cL]\qquad\huge \checkmark \] \[\frac{10^{1}\ [L]}{[mL]}\qquad\rightarrow\qquad 10^{1}\ [L]\cancel{=}[mL]\]
 one year ago
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