A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 2 years ago
Which of the following is a possible equivalence that can be used in a conversion?
ten cubed kL over one L
ten squared daL over one L
ten to the negative second power L over one cL
ten to the negative first power L over one mL
anonymous
 2 years ago
Which of the following is a possible equivalence that can be used in a conversion? ten cubed kL over one L ten squared daL over one L ten to the negative second power L over one cL ten to the negative first power L over one mL

This Question is Closed

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Let me look this one up

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0agree with @Claflamme3

theEric
 2 years ago
Best ResponseYou've already chosen the best response.3Hi! You have your answer, which I agree with, but I want to explain how you'd know that! Firstly, when you convert to a different unit, the value  what the number represents  doesn't change. You're actually multiplying the number by \(1\). Its a fraction, where the top and bottom are equal. I'll derive a simple conversion that I hope you agree with. Even if you're in the stubborn U.S., it's important to know the metric system. Like, 1 meter is one hundred centimters. In math, \(1\ [m]=100\ [cm]\) This would imply that, by dividing by 1 meter,\[\frac{1\ [m]}{1\ [m]}=\frac{100\ [cm]}{1\ [m]}\]\[\qquad\qquad\Downarrow\]\[\frac{\cancel{1\ [m]}}{\cancel{1\ [m]}}=\frac{100\ [cm]}{1\ [m]}\]\[\qquad\qquad\Downarrow\]\[1=\frac{100\ [cm]}{1\ [m]}\] That sort of thing is always good to know for unit conversions. And reversing that on your multiple choices will check to see if they are good! \[\frac{10^3\ [kL]}{[L]}\qquad\rightarrow\qquad 10^3\ [kL]\overset{?}{=}[L]\] \[\frac{10^2\ [daL]}{[L]}\qquad\rightarrow\qquad 10^2\ [daL]\overset{?}{=}[L]\] \[\frac{10^{2}\ [L]}{[cL]}\qquad\rightarrow\qquad 10^{2}\ [L]\overset{?}{=}[cL]\] \[\frac{10^{1}\ [L]}{[mL]}\qquad\rightarrow\qquad 10^{1}\ [L]\overset{?}{=}[mL]\] And note that \(\Large 10^{1}=\frac{1}{10^1}\) and that \(\Large 10^{2}=\frac{1}{10^2}\), just by the meaning of negative exponents. Just for my own fun... \[\frac{10^3\ [kL]}{[L]}\qquad\rightarrow\qquad 10^3\ [kL]\cancel{=}[L]\] \[\frac{10^2\ [daL]}{[L]}\qquad\rightarrow\qquad 10^2\ [daL]\cancel{=}[L]\] \[\frac{10^{2}\ [L]}{[cL]}\qquad\rightarrow\qquad 10^{2}\ [L]{=}[cL]\qquad\huge \checkmark \] \[\frac{10^{1}\ [L]}{[mL]}\qquad\rightarrow\qquad 10^{1}\ [L]\cancel{=}[mL]\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.