Zackeria_x3
The tables below show solutions for two linear equations. If the two equations make up a system of linear equations, in which quadrant is the solution?
Quadrant I
Quadrant II
Quadrant III
Quadrant IV
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Zackeria_x3
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melody16
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do you know what the solution is?
Zackeria_x3
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No.
melody16
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Don't you think you should in order to answer the question
Zackeria_x3
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.-. Thats why I came for help ?
melody16
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Do you know how?
Zackeria_x3
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No.
melody16
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a way you could find the answer and solution is by graphing. Do you know how to do that?
Zackeria_x3
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Mhmm
melody16
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So when you graph, you will find the answer.
Zackeria_x3
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-.- Are you gonna help me or not ?
melody16
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I just told you how to get the answer. What do you need help on?
Zackeria_x3
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.-. Just forget it.. I'll ask someone else.. thanks though ..
melody16
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What do you need help on? i could help you.
Zackeria_x3
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THIS!
melody16
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You need to graph both lines. Do you know how to do that?
Zackeria_x3
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No.
melody16
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OK, so since you have the table of pairs, you can find the slope. Do you know how to find a slope using two points?
Zackeria_x3
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You ask sooo many questions .-. is this an interview ? JK :P Um..I didnt really learn about slopes .-.
melody16
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I am just trying to help you by asking what you know. The equation to find your slope is (y2-y1)/ (x2-x1) (x,y)1 (x,y)2
melody16
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(y2-y1)/ (x2-x1) <-- equation
SnuggieLad
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You need to do it yourself. We can not do it for you. It is against the CoC.
Zackeria_x3
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.-.
SnuggieLad
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We can help you learn but we can not answer it for you.
Zackeria_x3
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I've gotten lots of answers before..
melody16
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They were doing it wrong then. If i give you the answer you will continue to have the question and during the test you will be lost.
Zackeria_x3
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.-. Im doing FLVS so Im not gonna get a test...
Zackeria_x3
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You just gimmie the answer and I move on..
melody16
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Try to do what I am saying. Pick two points from one line. and plug it into the equation
Zackeria_x3
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I chose the 3rd one.
SnuggieLad
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First of all FLVS DOES give tests!
Juriyah
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is number 3 right