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\[a^3-a^2 = a^2(a-1)\]right?

Nothing appears to be a common factor with the denominator, does it?

What if you now factor the denominator?

yes. @whpalmer4
see the image: (but there could be 2 answers; see the top and bottom image)

the original restrictions on \(a\) still apply: \(a \ne \pm 1\)

oh ok thanks
@whpalmer4
by the way, what original restrictions?

ah... okay thank you so much @whpalmer4

you're welcome.