anonymous
  • anonymous
mhmm
Mathematics
katieb
  • katieb
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swissgirl
  • swissgirl
\(8 \sqrt{63x^5} \) Is it like this?
swissgirl
  • swissgirl
Ok So \( \sqrt{63} = \sqrt{9*7} \)
swissgirl
  • swissgirl
We know that \( \sqrt{9}=3\) Sooo \( \sqrt{63}= \sqrt{9*7}=3\sqrt{7}\)

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swissgirl
  • swissgirl
Okkk but we didnt finish off the problem What is the answer?
swissgirl
  • swissgirl
Well is x in the squareroot or out? Is it the way you typed or the way I typed it?
swissgirl
  • swissgirl
Ok so we can write it out as \( \sqrt{63x^5}= \sqrt{9*7*x*x*x*x*x}=\sqrt{3^2*7*x^2*x^2*x}=3*x*x \sqrt{7*x}\) \(=3x^2\sqrt{7x}\)
swissgirl
  • swissgirl
Do you follow what I did?
swissgirl
  • swissgirl
Ok so basically I broke evrything down 63=7*9 x^5=x*x*x*x*x
swissgirl
  • swissgirl
Then I tried to make everything squared so 9=3^2 and we know that sqrt of any number squared is the number itself sooo \( \sqrt{3^2}=3\) and \(\sqrt{x^2}=x\)
swissgirl
  • swissgirl
Actually it didnt
swissgirl
  • swissgirl
ok but the final answer is \( 8*3x^2\sqrt{7x} = 24x^2\sqrt{7x}\)
swissgirl
  • swissgirl
Your Welcome :)
swissgirl
  • swissgirl
You're Welcome Bad grammar :)
swissgirl
  • swissgirl
yes :)

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