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swissgirl
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\(8 \sqrt{63x^5} \)
Is it like this?
swissgirl
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Ok So \( \sqrt{63} = \sqrt{9*7} \)
swissgirl
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We know that \( \sqrt{9}=3\)
Sooo \( \sqrt{63}= \sqrt{9*7}=3\sqrt{7}\)
swissgirl
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Okkk but we didnt finish off the problem
What is the answer?
swissgirl
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Well is x in the squareroot or out?
Is it the way you typed or the way I typed it?
swissgirl
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Ok so we can write it out as
\( \sqrt{63x^5}= \sqrt{9*7*x*x*x*x*x}=\sqrt{3^2*7*x^2*x^2*x}=3*x*x \sqrt{7*x}\)
\(=3x^2\sqrt{7x}\)
swissgirl
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Do you follow what I did?
swissgirl
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Ok so basically I broke evrything down
63=7*9
x^5=x*x*x*x*x
swissgirl
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Then I tried to make everything squared
so 9=3^2 and we know that sqrt of any number squared is the number itself sooo
\( \sqrt{3^2}=3\) and \(\sqrt{x^2}=x\)
swissgirl
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Actually it didnt
swissgirl
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ok but the final answer is
\( 8*3x^2\sqrt{7x} = 24x^2\sqrt{7x}\)
swissgirl
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Your Welcome :)
swissgirl
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You're Welcome
Bad grammar :)
swissgirl
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yes :)