A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
mhmm
anonymous
 3 years ago
mhmm

This Question is Closed

swissgirl
 3 years ago
Best ResponseYou've already chosen the best response.1\(8 \sqrt{63x^5} \) Is it like this?

swissgirl
 3 years ago
Best ResponseYou've already chosen the best response.1Ok So \( \sqrt{63} = \sqrt{9*7} \)

swissgirl
 3 years ago
Best ResponseYou've already chosen the best response.1We know that \( \sqrt{9}=3\) Sooo \( \sqrt{63}= \sqrt{9*7}=3\sqrt{7}\)

swissgirl
 3 years ago
Best ResponseYou've already chosen the best response.1Okkk but we didnt finish off the problem What is the answer?

swissgirl
 3 years ago
Best ResponseYou've already chosen the best response.1Well is x in the squareroot or out? Is it the way you typed or the way I typed it?

swissgirl
 3 years ago
Best ResponseYou've already chosen the best response.1Ok so we can write it out as \( \sqrt{63x^5}= \sqrt{9*7*x*x*x*x*x}=\sqrt{3^2*7*x^2*x^2*x}=3*x*x \sqrt{7*x}\) \(=3x^2\sqrt{7x}\)

swissgirl
 3 years ago
Best ResponseYou've already chosen the best response.1Do you follow what I did?

swissgirl
 3 years ago
Best ResponseYou've already chosen the best response.1Ok so basically I broke evrything down 63=7*9 x^5=x*x*x*x*x

swissgirl
 3 years ago
Best ResponseYou've already chosen the best response.1Then I tried to make everything squared so 9=3^2 and we know that sqrt of any number squared is the number itself sooo \( \sqrt{3^2}=3\) and \(\sqrt{x^2}=x\)

swissgirl
 3 years ago
Best ResponseYou've already chosen the best response.1ok but the final answer is \( 8*3x^2\sqrt{7x} = 24x^2\sqrt{7x}\)

swissgirl
 3 years ago
Best ResponseYou've already chosen the best response.1You're Welcome Bad grammar :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.