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malehuman01 Group Title

mhmm

  • one year ago
  • one year ago

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  1. swissgirl Group Title
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    \(8 \sqrt{63x^5} \) Is it like this?

    • one year ago
  2. swissgirl Group Title
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    Ok So \( \sqrt{63} = \sqrt{9*7} \)

    • one year ago
  3. swissgirl Group Title
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    We know that \( \sqrt{9}=3\) Sooo \( \sqrt{63}= \sqrt{9*7}=3\sqrt{7}\)

    • one year ago
  4. swissgirl Group Title
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    Okkk but we didnt finish off the problem What is the answer?

    • one year ago
  5. swissgirl Group Title
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    Well is x in the squareroot or out? Is it the way you typed or the way I typed it?

    • one year ago
  6. swissgirl Group Title
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    Ok so we can write it out as \( \sqrt{63x^5}= \sqrt{9*7*x*x*x*x*x}=\sqrt{3^2*7*x^2*x^2*x}=3*x*x \sqrt{7*x}\) \(=3x^2\sqrt{7x}\)

    • one year ago
  7. swissgirl Group Title
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    Do you follow what I did?

    • one year ago
  8. swissgirl Group Title
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    Ok so basically I broke evrything down 63=7*9 x^5=x*x*x*x*x

    • one year ago
  9. swissgirl Group Title
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    Then I tried to make everything squared so 9=3^2 and we know that sqrt of any number squared is the number itself sooo \( \sqrt{3^2}=3\) and \(\sqrt{x^2}=x\)

    • one year ago
  10. swissgirl Group Title
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    Actually it didnt

    • one year ago
  11. swissgirl Group Title
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    ok but the final answer is \( 8*3x^2\sqrt{7x} = 24x^2\sqrt{7x}\)

    • one year ago
  12. swissgirl Group Title
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    Your Welcome :)

    • one year ago
  13. swissgirl Group Title
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    You're Welcome Bad grammar :)

    • one year ago
  14. swissgirl Group Title
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    yes :)

    • one year ago
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