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malehuman01

  • 2 years ago

mhmm

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  1. swissgirl
    • 2 years ago
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    \(8 \sqrt{63x^5} \) Is it like this?

  2. swissgirl
    • 2 years ago
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    Ok So \( \sqrt{63} = \sqrt{9*7} \)

  3. swissgirl
    • 2 years ago
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    We know that \( \sqrt{9}=3\) Sooo \( \sqrt{63}= \sqrt{9*7}=3\sqrt{7}\)

  4. swissgirl
    • 2 years ago
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    Okkk but we didnt finish off the problem What is the answer?

  5. swissgirl
    • 2 years ago
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    Well is x in the squareroot or out? Is it the way you typed or the way I typed it?

  6. swissgirl
    • 2 years ago
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    Ok so we can write it out as \( \sqrt{63x^5}= \sqrt{9*7*x*x*x*x*x}=\sqrt{3^2*7*x^2*x^2*x}=3*x*x \sqrt{7*x}\) \(=3x^2\sqrt{7x}\)

  7. swissgirl
    • 2 years ago
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    Do you follow what I did?

  8. swissgirl
    • 2 years ago
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    Ok so basically I broke evrything down 63=7*9 x^5=x*x*x*x*x

  9. swissgirl
    • 2 years ago
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    Then I tried to make everything squared so 9=3^2 and we know that sqrt of any number squared is the number itself sooo \( \sqrt{3^2}=3\) and \(\sqrt{x^2}=x\)

  10. swissgirl
    • 2 years ago
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    Actually it didnt

  11. swissgirl
    • 2 years ago
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    ok but the final answer is \( 8*3x^2\sqrt{7x} = 24x^2\sqrt{7x}\)

  12. swissgirl
    • 2 years ago
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    Your Welcome :)

  13. swissgirl
    • 2 years ago
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    You're Welcome Bad grammar :)

  14. swissgirl
    • 2 years ago
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    yes :)

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