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FriedRice

  • 2 years ago

The figure shows triangle ABC with medians AF, BD, and CE. Segment AF is extended to H in such a way that segment GH is congruent to segment AG. Which conclusion can be made based on the given conditions?

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  1. warningiflirt
    • 2 years ago
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    its not showing the pic?

  2. FriedRice
    • 2 years ago
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  3. warningiflirt
    • 2 years ago
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    ok thanks

  4. warningiflirt
    • 2 years ago
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    now the conclusions..... :)

  5. FriedRice
    • 2 years ago
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    Segment GD is congruent to segment GF. Segment GD is parallel to segment HC. Segment GF is parallel to segment EB. Segment BH is congruent to segment HC.

  6. warningiflirt
    • 2 years ago
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    hold on im thinking :)

  7. FriedRice
    • 2 years ago
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    ok

  8. warningiflirt
    • 2 years ago
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    so do you know what parallel means?

  9. warningiflirt
    • 2 years ago
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    because we can eliminate one of the parallel choices by jst looking at it

  10. warningiflirt
    • 2 years ago
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    we can eliminate Segment GF is parallel to segment EB, because they obviously cross at the top.

  11. warningiflirt
    • 2 years ago
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    I think its Segment BH is congruent to segment HC. because the bisecting line in the middle bisects it equally.

  12. FriedRice
    • 2 years ago
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    oh ok

  13. warningiflirt
    • 2 years ago
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    c how I got it?

  14. FriedRice
    • 2 years ago
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    yes

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