Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
HELP MATRICES:
If a= [4,3, 2; 0, 5,2] (2x3 dimension matrix)
c= [ 7,1; 2,7] (2x2 dimension matrix)
then 5AA^t+6c =
 9 months ago
 9 months ago
HELP MATRICES: If a= [4,3, 2; 0, 5,2] (2x3 dimension matrix) c= [ 7,1; 2,7] (2x2 dimension matrix) then 5AA^t+6c =
 9 months ago
 9 months ago

This Question is Closed

blurbendyBest ResponseYou've already chosen the best response.0
I'm assuming A is referring to a? If so, the first thing I would do is take the transpose of matrix a, since you have A^t in your equation. Are you familiar with how to do that?
 9 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
Yes, i transposed A^t= dw:1374263685200:dw
 9 months ago

blurbendyBest ResponseYou've already chosen the best response.0
Looks good, so now I would multiply this matrix by the original a matrix.
 9 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
the problem i have is knowing which number to multiply with which and also last at c
 9 months ago

blurbendyBest ResponseYou've already chosen the best response.0
A good rule of thumb is to multiply scalars at the end. The scalars in this case are 5 and 6
 9 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
i did this: 5(4) (4)+6c 5(3)(3)+6c 5(2) (2)+6c 5(0)(0)+6c 5(5)(5)+6c 5(2)(2)+6c and also, how do i know what dimension the new matrix will look like if a is a 2x3 dimensions and c is a 2x2 dimension? doesn't that say not allowed to be multiplied? unless the middle numbers are the same?
 9 months ago

blurbendyBest ResponseYou've already chosen the best response.0
Hold on, you have to actually multiply matrix a by a^t, so you'd have: dw:1374264066231:dw this is a 2 x 3 matrix * 3 x 2 matrix, which will give you a 2 x 2 matrix. Then you would multiply each value in your 2 x 2 matrix by 5
 9 months ago

blurbendyBest ResponseYou've already chosen the best response.0
i swapped the negatives on the 2's. sorry about that
 9 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
oh okay. so basically I multiply.. row and columns?
 9 months ago

blurbendyBest ResponseYou've already chosen the best response.0
Sort of. Matrix multiplication works like this: dw:1374264402007:dw
 9 months ago

blurbendyBest ResponseYou've already chosen the best response.0
do you understand what you have to do?
 9 months ago

blurbendyBest ResponseYou've already chosen the best response.0
To calculate the position next to 29 in the new matrix, you would multiply the first row in a by the SECOND column in a^t
 9 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
after? not really
 9 months ago

blurbendyBest ResponseYou've already chosen the best response.0
you need the next position in the matrix (next to 29), so to calculate the position next to 29 in the new matrix, you would multiply the first row in a by the SECOND column in a^t
 9 months ago

blurbendyBest ResponseYou've already chosen the best response.0
Just do what you did to get 29, exception this time multiply the first row by the second column
 9 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.