Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

chika_tika3007

  • 2 years ago

2^2x -6.2^x +8 =0

  • This Question is Closed
  1. ganeshie8
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    say k = \(\large 2^x\)

  2. ganeshie8
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \(\large 2^{2x} -6.2^x +8 =0\) \(\large (2^{x})^2 -6.2^x +8 =0\)

  3. ganeshie8
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    plugin k and you will see a quadratic in k solve k

  4. chika_tika3007
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ok but how abaout the number 8???

  5. ganeshie8
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    wat do u get after putting \(2^x=k\) ?

  6. ganeshie8
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    we get this :- \(\large k^2-6k+8=0\)

  7. ganeshie8
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    this is just a quadratic equation you knw how to solve a quadratic equaiton ha ?

  8. chika_tika3007
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes

  9. ganeshie8
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    good, factor it and solve k first

  10. chika_tika3007
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    humm ok ok i got it k thanks

  11. ganeshie8
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    sure ?

  12. ganeshie8
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \(\large (k-2)(k-4) = 0\) \(k = 2, k=4\)

  13. chika_tika3007
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    i get the answer are -2 and -4

  14. chika_tika3007
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes..

  15. ganeshie8
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    when k = 2, \(2^x = k\) \(2^x = 2^1\) \(x = 1\)

  16. ganeshie8
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    when k = 4, \(2^x = k\) \(2^x = 4\) \(2^x = 2^2\) \(x = 2\)

  17. ganeshie8
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so the solutions are : 1, 2

  18. chika_tika3007
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yup yup

  19. ganeshie8
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    cool :)

  20. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy