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ganeshie8Best ResponseYou've already chosen the best response.1
say k = \(\large 2^x\)
 9 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
\(\large 2^{2x} 6.2^x +8 =0\) \(\large (2^{x})^2 6.2^x +8 =0\)
 9 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
plugin k and you will see a quadratic in k solve k
 9 months ago

chika_tika3007Best ResponseYou've already chosen the best response.1
ok but how abaout the number 8???
 9 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
wat do u get after putting \(2^x=k\) ?
 9 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
we get this : \(\large k^26k+8=0\)
 9 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
this is just a quadratic equation you knw how to solve a quadratic equaiton ha ?
 9 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
good, factor it and solve k first
 9 months ago

chika_tika3007Best ResponseYou've already chosen the best response.1
humm ok ok i got it k thanks
 9 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
\(\large (k2)(k4) = 0\) \(k = 2, k=4\)
 9 months ago

chika_tika3007Best ResponseYou've already chosen the best response.1
i get the answer are 2 and 4
 9 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
when k = 2, \(2^x = k\) \(2^x = 2^1\) \(x = 1\)
 9 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
when k = 4, \(2^x = k\) \(2^x = 4\) \(2^x = 2^2\) \(x = 2\)
 9 months ago

ganeshie8Best ResponseYou've already chosen the best response.1
so the solutions are : 1, 2
 9 months ago
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