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anonymous
 3 years ago
2^2x 6.2^x +8 =0
anonymous
 3 years ago
2^2x 6.2^x +8 =0

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ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1say k = \(\large 2^x\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(\large 2^{2x} 6.2^x +8 =0\) \(\large (2^{x})^2 6.2^x +8 =0\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1plugin k and you will see a quadratic in k solve k

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok but how abaout the number 8???

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1wat do u get after putting \(2^x=k\) ?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1we get this : \(\large k^26k+8=0\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1this is just a quadratic equation you knw how to solve a quadratic equaiton ha ?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1good, factor it and solve k first

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0humm ok ok i got it k thanks

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(\large (k2)(k4) = 0\) \(k = 2, k=4\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i get the answer are 2 and 4

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1when k = 2, \(2^x = k\) \(2^x = 2^1\) \(x = 1\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1when k = 4, \(2^x = k\) \(2^x = 4\) \(2^x = 2^2\) \(x = 2\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1so the solutions are : 1, 2
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