## anonymous 3 years ago really need HELP!!! The formula for that area of a triangle is A = 1/2}bh. If the base is 5\sqrt 3 and the height is \sqrt {18} , what is the area of this triangle in radical form?

1. campbell_st

$Area = \frac{1}{2} \times \frac{5}{\sqrt{3}} \times \sqrt{18} = \frac{1}{2} \times 5 \times \sqrt{\frac{18}{3}}$ simplify the fraction inside the radical for the answer.

2. mathstudent55

@campbell_st Perhaps the poster meant this: $$A = \dfrac{bh}{2}$$ $$A = \dfrac{5 \sqrt{3} \times \sqrt{18} }{2}$$

3. campbell_st

well if thats the case its $Area = \frac{5 \times \sqrt{3 \times 18}}{2}$

4. anonymous

I dont have a calculator to find the sqaure root can someone do it please ?

5. anonymous

$$Area = \large \frac{5* \sqrt{54}}{2} = \frac{5* \sqrt{9*6}}{2}=\frac{15\sqrt{6}}{2}$$ If you would not like the sqrt in your answer thennn $$\sqrt{6}$$ is approximately 2.45 sooo $$Area = \large \frac{15*2.45}{2}$$

6. anonymous

7. anonymous

yess aproximately

8. anonymous

is this in radical form ??

9. anonymous

nooooooo Radical form is what I showed above $$Area = \large \frac{15\sqrt{6}}{2}$$

10. anonymous

what is the area of this triangle in radical form? in the question it says this so how would i write this ?

11. anonymous

12. anonymous

There I showed u above

13. anonymous

ok so can u tell me the final answer ?

14. anonymous

i dont have that sqrt sign on my keyboard