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really need HELP!!! The formula for that area of a triangle is A = 1/2}bh. If the base is 5\sqrt 3 and the height is \sqrt {18} , what is the area of this triangle in radical form?

Mathematics
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\[Area = \frac{1}{2} \times \frac{5}{\sqrt{3}} \times \sqrt{18} = \frac{1}{2} \times 5 \times \sqrt{\frac{18}{3}}\] simplify the fraction inside the radical for the answer.
@campbell_st Perhaps the poster meant this: \(A = \dfrac{bh}{2} \) \(A = \dfrac{5 \sqrt{3} \times \sqrt{18} }{2} \)
well if thats the case its \[Area = \frac{5 \times \sqrt{3 \times 18}}{2}\]

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Other answers:

I dont have a calculator to find the sqaure root can someone do it please ?
\(Area = \large \frac{5* \sqrt{54}}{2} = \frac{5* \sqrt{9*6}}{2}=\frac{15\sqrt{6}}{2} \) If you would not like the sqrt in your answer thennn \( \sqrt{6}\) is approximately 2.45 sooo \( Area = \large \frac{15*2.45}{2}\)
so your answer would be 18.375 ?
yess aproximately
is this in radical form ??
nooooooo Radical form is what I showed above \( Area = \large \frac{15\sqrt{6}}{2}\)
what is the area of this triangle in radical form? in the question it says this so how would i write this ?
for the answer
There I showed u above
ok so can u tell me the final answer ?
i dont have that sqrt sign on my keyboard

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