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xoxox123

  • 2 years ago

really need HELP!!! The formula for that area of a triangle is A = 1/2}bh. If the base is 5\sqrt 3 and the height is \sqrt {18} , what is the area of this triangle in radical form?

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  1. campbell_st
    • 2 years ago
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    \[Area = \frac{1}{2} \times \frac{5}{\sqrt{3}} \times \sqrt{18} = \frac{1}{2} \times 5 \times \sqrt{\frac{18}{3}}\] simplify the fraction inside the radical for the answer.

  2. mathstudent55
    • 2 years ago
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    @campbell_st Perhaps the poster meant this: \(A = \dfrac{bh}{2} \) \(A = \dfrac{5 \sqrt{3} \times \sqrt{18} }{2} \)

  3. campbell_st
    • 2 years ago
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    well if thats the case its \[Area = \frac{5 \times \sqrt{3 \times 18}}{2}\]

  4. xoxox123
    • 2 years ago
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    I dont have a calculator to find the sqaure root can someone do it please ?

  5. swissgirl
    • 2 years ago
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    \(Area = \large \frac{5* \sqrt{54}}{2} = \frac{5* \sqrt{9*6}}{2}=\frac{15\sqrt{6}}{2} \) If you would not like the sqrt in your answer thennn \( \sqrt{6}\) is approximately 2.45 sooo \( Area = \large \frac{15*2.45}{2}\)

  6. xoxox123
    • 2 years ago
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    so your answer would be 18.375 ?

  7. swissgirl
    • 2 years ago
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    yess aproximately

  8. xoxox123
    • 2 years ago
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    is this in radical form ??

  9. swissgirl
    • 2 years ago
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    nooooooo Radical form is what I showed above \( Area = \large \frac{15\sqrt{6}}{2}\)

  10. xoxox123
    • 2 years ago
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    what is the area of this triangle in radical form? in the question it says this so how would i write this ?

  11. xoxox123
    • 2 years ago
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    for the answer

  12. swissgirl
    • 2 years ago
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    There I showed u above

  13. xoxox123
    • 2 years ago
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    ok so can u tell me the final answer ?

  14. xoxox123
    • 2 years ago
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    i dont have that sqrt sign on my keyboard

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