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mathcalculus
 one year ago
HELP! how to solve system of equations
x2y+z=1
y+2z=4
x+y+3z=5
what do we do when there is a missing variable??? :(
mathcalculus
 one year ago
HELP! how to solve system of equations x2y+z=1 y+2z=4 x+y+3z=5 what do we do when there is a missing variable??? :(

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woody84
 one year ago
Best ResponseYou've already chosen the best response.0what are you solving for??

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure what to do since the x is missing.

Directrix
 one year ago
Best ResponseYou've already chosen the best response.1Write the system as: x  2y +z =1 0x +y+ 2z=4 x + y + 3z = 5 In the first and third equations, eliminate the variable x. Then, you will have a system of 2 by 2 equations in the unknowns y and z. Of those two equations, eliminate a variable and solve for the other. If you are allowed to use technology, take a look at the online 3 x 3 linear equation system solver at: http://math.bd.psu.edu/~jpp4/finitemath/3x3solver.html @mathcalculus

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0im trying to solve it step by step

Directrix
 one year ago
Best ResponseYou've already chosen the best response.1x  2y +z =1 0x +y+ 2z=4 x + y + 3z = 5 x  2y +z =1 x  2y +z =1 x + y + 3z = 5 multiply through by 1 > x  y  3z = 5  3y  2z = 4

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0i got a little lost. now i know why

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0i got that, so what about the second equation?

Directrix
 one year ago
Best ResponseYou've already chosen the best response.1@mathcalculus Your Task: Solve this system  Just add them. 3y  2z = 4 y+ 2z=4 

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0it bothers me that the 0x is there.

Directrix
 one year ago
Best ResponseYou've already chosen the best response.1Don't look at it. When I eliminated the "x" in equations #1 and #3, the 0x was not an issue.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0i got this: 2y=0

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0but it can't be. it's undefined.

Directrix
 one year ago
Best ResponseYou've already chosen the best response.1Note that here: Solve this system  Just add them. 3y  2z = 4 y+ 2z=4  I excluded the 0x term. It is just a placeholder of sorts.

Directrix
 one year ago
Best ResponseYou've already chosen the best response.12y = 0 y= 0/2 y = 0> You have division by 0 and division into 0 mixed up.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0okay i got that step right.

Directrix
 one year ago
Best ResponseYou've already chosen the best response.1It is wrong. But, unless you show your steps, I cannot help you find the error.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0i got it right! x=1 y=0 z=2 ! =]

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0thanks so much! i really aprreciate it!
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