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what are you solving for??
x,y, and z
I'm not sure what to do since the x is missing.
Write the system as: x - 2y +z =-1 0x +y+ 2z=-4 x + y + 3z = -5 In the first and third equations, eliminate the variable x. Then, you will have a system of 2 by 2 equations in the unknowns y and z. Of those two equations, eliminate a variable and solve for the other. If you are allowed to use technology, take a look at the online 3 x 3 linear equation system solver at: http://math.bd.psu.edu/~jpp4/finitemath/3x3solver.html @mathcalculus
im trying to solve it step by step
x - 2y +z =-1 0x +y+ 2z=-4 x + y + 3z = -5 x - 2y +z =-1 x - 2y +z =-1 x + y + 3z = -5 --multiply through by -1 -> -x - y - 3z = 5 ---------------- -3y - 2z = 4
i got a little lost. now i know why
i got that, so what about the second equation?
@mathcalculus Your Task: Solve this system - Just add them. -3y - 2z = 4 y+ 2z=-4 -----------------
it bothers me that the 0x is there.
Don't look at it. When I eliminated the "x" in equations #1 and #3, the 0x was not an issue.
i got this: -2y=0
but it can't be. it's undefined.
Note that here: Solve this system - Just add them. -3y - 2z = 4 y+ 2z=-4 ----------------- I excluded the 0x term. It is just a placeholder of sorts.
yeah i know.
-2y = 0 y= 0/2 y = 0--> You have division by 0 and division into 0 mixed up.
so y is 0?
okay i got that step right.
it's wrong... :(
It is wrong. But, unless you show your steps, I cannot help you find the error.
ok hold on.
i got it right! x=1 y=0 z=-2 ! =]
thanks so much! i really aprreciate it!
You are welcome.