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greeneyes<3 Group Title

SUMMER MATH PACKET!! Check my work? :)

  • one year ago
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  1. Zacharymartin Group Title
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    Sure

    • one year ago
  2. Zacharymartin Group Title
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    ill see what i can do

    • one year ago
  3. greeneyes<3 Group Title
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    \[\sqrt{81x^5/3x}\] my answer was \[9x^2\sqrt{3}\]

    • one year ago
  4. greeneyes<3 Group Title
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    3x-[5-4(2x-7)] my answer was x-7

    • one year ago
  5. Hero Group Title
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    For the first one, 81/3 = 27 so...your answer to that one needs some adjusting

    • one year ago
  6. Zacharymartin Group Title
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    The second one is correct

    • one year ago
  7. Zacharymartin Group Title
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    Ya the second one is all good!

    • one year ago
  8. agent0smith Group Title
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    \[\Large \sqrt{\frac{ 81x^5 }{ 3x}} = \sqrt {27 x^4} = \sqrt { 9*3 x^4}\]

    • one year ago
  9. greeneyes<3 Group Title
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    so the first answer is...\[3x^2\sqrt{3}\]

    • one year ago
  10. greeneyes<3 Group Title
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    \[\sqrt{16x^2}\] x\[\sqrt{3x^3}\] my answer was \[4x^2\sqrt{3x}\]

    • one year ago
  11. greeneyes<3 Group Title
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    \[45x ^{7}y ^{4}z\]\[\div 9x ^{2}y ^{8}z ^{4}\] my answer was \[5x ^{5}\div y ^{4}z ^{3}\]

    • one year ago
  12. some_someone Group Title
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    Q: \[45x^7y^4z÷9x^2y^8z^4\] A: \[\frac{ 5x^5 }{ y^4z^3 }\]

    • one year ago
  13. some_someone Group Title
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    Seems right.

    • one year ago
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