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greeneyes<3

  • 2 years ago

SUMMER MATH PACKET!! Check my work? :)

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  1. Zacharymartin
    • 2 years ago
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    Sure

  2. Zacharymartin
    • 2 years ago
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    ill see what i can do

  3. greeneyes<3
    • 2 years ago
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    \[\sqrt{81x^5/3x}\] my answer was \[9x^2\sqrt{3}\]

  4. greeneyes<3
    • 2 years ago
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    3x-[5-4(2x-7)] my answer was x-7

  5. Hero
    • 2 years ago
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    For the first one, 81/3 = 27 so...your answer to that one needs some adjusting

  6. Zacharymartin
    • 2 years ago
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    The second one is correct

  7. Zacharymartin
    • 2 years ago
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    Ya the second one is all good!

  8. agent0smith
    • 2 years ago
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    \[\Large \sqrt{\frac{ 81x^5 }{ 3x}} = \sqrt {27 x^4} = \sqrt { 9*3 x^4}\]

  9. greeneyes<3
    • 2 years ago
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    so the first answer is...\[3x^2\sqrt{3}\]

  10. greeneyes<3
    • 2 years ago
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    \[\sqrt{16x^2}\] x\[\sqrt{3x^3}\] my answer was \[4x^2\sqrt{3x}\]

  11. greeneyes<3
    • 2 years ago
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    \[45x ^{7}y ^{4}z\]\[\div 9x ^{2}y ^{8}z ^{4}\] my answer was \[5x ^{5}\div y ^{4}z ^{3}\]

  12. some_someone
    • 2 years ago
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    Q: \[45x^7y^4z÷9x^2y^8z^4\] A: \[\frac{ 5x^5 }{ y^4z^3 }\]

  13. some_someone
    • 2 years ago
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    Seems right.

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