anonymous
  • anonymous
if you are trying to find an angle and you only have this equation, 3x-14, how do you solve
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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theEric
  • theEric
Well, that's actually an expression, not an equation. An equation needs equal expressions, like\[y=3x-14\]I assume that the angle you want to know is on the graph of \(y=3x-14\). Does that seem right, so far?
anonymous
  • anonymous
yes
theEric
  • theEric
Alright, now, have you learned trigonometric functions yet?

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anonymous
  • anonymous
not yet
theEric
  • theEric
Is this a question for class, or is it your own curiosity? I might have to research another way to get the angle than I had thought of using earlier.
anonymous
  • anonymous
this is homework from summer
theEric
  • theEric
And you don't know about the tangent a.k.a. \(tan\) function?
anonymous
  • anonymous
no
theEric
  • theEric
Well, I guess we might as well look at the graph.|dw:1374722124721:dw|I'm not sure which angle the question wants, but I assume it's the angle of the line measured from the x-axis and you would use the tangent function. Maybe I can find others to help us... With the tangent function, you use the equation \(tan^{-1}(m)=\theta\) where \(m\) is your slope and \(\theta\) is its angle.
anonymous
  • anonymous
ok
anonymous
  • anonymous
nevermind
theEric
  • theEric
I would imagine you are, especially if you never used the tangent function! But I don't know any other way!
Hero
  • Hero
Alternatively you can just use a protractor and graph paper.
theEric
  • theEric
Ahhhhhh.... I seeee.... So, measuring, not calculating. I think I remember doing that before, too.
anonymous
  • anonymous
oh so instead of finding y you just measure from what x is?
theEric
  • theEric
So you'll need to have grid paper, so your line is straight and your axes are perpendicular and everything is accurate. Then you can measure the line accurately. Thank you, @Hero !
theEric
  • theEric
|dw:1374722785269:dw|
theEric
  • theEric
Do you have grid paper and a protractor?
anonymous
  • anonymous
ya and i think i got it thank you @theEric
theEric
  • theEric
Sweet. Just set up the protractor along the \(x\)-axis (or at least parallel to the \(x\)-axis) and have that point on the line. Good luck :)

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