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surjithayerBest ResponseYou've already chosen the best response.0
\[\frac{ \sin ^{2}x }{ 22\cos x }=\frac{ 1 }{ 2 }*\frac{\sin ^{2}x }{1\cos x }*\frac{1+\cos x }{1+\cos x }\] \[=\frac{ 1 }{ 2 }*\frac{ \sin ^{2}x \left( 1+\cos x \right) }{ 1\cos ^{2}x }\] you can solve and use \[1\cos ^{2}x=\sin ^{2}x and 1+\cos x=2\cos ^{2}\frac{ x }{ 2 }\]
 9 months ago

yluchoBest ResponseYou've already chosen the best response.0
thanks for the help!!! I never thought about splitting at the beginning into two fractions :P thanks!
 9 months ago
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