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help with verifying this please!
tanxcos^2x=2tanxcos^2xtanx/1tan^2x
 8 months ago
 8 months ago
help with verifying this please! tanxcos^2x=2tanxcos^2xtanx/1tan^2x
 8 months ago
 8 months ago

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jdoe0001Best ResponseYou've already chosen the best response.0
\(\bf tan(x)cos^2(x) = \cfrac{2tan(x)cos^2(x)tan(x)}{1tan^2(x)}\ \ ?\)
 8 months ago

yluchoBest ResponseYou've already chosen the best response.0
i worked with the right side and converted everything to sin and cos first, but I just confused myself even more
 8 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
$$\bf tan(x)cos^2(x) = \cfrac{2tan(x)cos^2(x)tan(x)}{1tan^2(x)}\\ \text{let's do the rightside first}\\ \cfrac{\frac{2sin(x)cos^2(x)}{cos(x)}\frac{sin(x)}{cos(x)}} {1\frac{sin^2(x)}{cos^2(x)}}\\ \cfrac{ \frac{2sin(x)cos^2(x)sin(x)}{cos(x)} }{ \frac{cos^2(x)sin^2(x)}{cos^2(x)}}\\ \frac{2sin(x)cos^2(x)sin(x)}{\cancel{cos(x)}} \times \frac{\cancel{cos^2(x)}}{cos^2(x)sin^2(x)} $$
 8 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
$$\bf \frac{sin(x)(2cos^2(x)1)}{1} \times \frac{cos(x)}{cos^2(x)sin^2(x)}\\ \cfrac{sin(x)cos(x)(2cos^2(x)1)}{cos^2(x)sin^2(x)} $$
 8 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
now take a peek at \(\bf 2cos^2(x)1 \implies cos(2x) \)
 8 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
and \(\bf cos(2x) =cos^2(x)sin^2(x)\) which means that \(\bf 2cos^2(x)1 = cos^2(x)sin^2(x)\)
 8 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
thus then $$\bf \cfrac{sin(x)cos(x)(2cos^2(x)1)}{cos^2(x)sin^2(x)} \implies \cfrac{sin(x)cos(x)\cancel{(cos^2(x)sin^2(x))}}{\cancel{cos^2(x)sin^2(x)}} $$
 8 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
now try the left side :)
 8 months ago
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