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place the answer in correct scientific notation, when appropriate and simplify the units. work with the units, cancel units when possible, and show simplified units in the final answer.
K=1/2(3.6*10^2 kg) (2.32*10^5 m/s)^2
 8 months ago
 8 months ago
place the answer in correct scientific notation, when appropriate and simplify the units. work with the units, cancel units when possible, and show simplified units in the final answer. K=1/2(3.6*10^2 kg) (2.32*10^5 m/s)^2
 8 months ago
 8 months ago

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theEricBest ResponseYou've already chosen the best response.2
Alright, I'll start by making that equation "pretty"...\[K=\frac{1}{2}(3.6*10^2 [kg]) \ (2.32*10^5 [m/s])^2\] Now, do you understand what this question wants you to do? All that is pretty much saying: calculate. Solve the problem and see what \(K\) is. And make sure you handle the units well.
 8 months ago

RosieS12Best ResponseYou've already chosen the best response.0
ok so first we can convert the units
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
We could. We could look at the units separately, to make it easier. I put units in \([\ ]\)'s to tell them apart by the way. So...\[[units\ of\ K]=[kg]\ \left( [m/s]\right)^2\] Do you see what I did, there?
 8 months ago

RosieS12Best ResponseYou've already chosen the best response.0
yea so wat would the next step be?
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
Solving. So multiply units like you would variables or numbers. And that \(m/s\) is squared. So treat that like \(\Large\left(\frac{m}{s}\right)^2\) when you do your math.
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
Understood? You can let me know what you get to see if we agree on what that is. If we have different answers, we can work through it together :)
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
Let me know what you get, if I'm still on when you solve it! After you work the units out, you try to find if they are actually one unit themselves! And you can calculate the numbers separately  that's just putting it into a calculator correctly, though. Right? Good luck!
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
Alright. Have you started any work yet?
 8 months ago

RosieS12Best ResponseYou've already chosen the best response.0
yea i tried and like to convert them but idk how u meant with ur method
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
So, like, you have\[[kg]\ [m/s]^2\]\[=[kg]\ [m\div s]^2\]\[=[kg]\ [m]^2\div [s]^2\]So, in the end, you have\[[units\ of\ K]=\frac{[kg][m]^2}{[s]^2}\]
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
Now it's memory work. I can only remember units from equations. Like, force is in newtons, and force is mass * acceleration which is kg * m/s^2. So newtons are "kg m / s^2"
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
Do you know what "work" is in physics? If not, I'd like you to look at the equation.
 8 months ago

RosieS12Best ResponseYou've already chosen the best response.0
ok let me write that down
 8 months ago

RosieS12Best ResponseYou've already chosen the best response.0
wait wat do u mean by m/s isnt it one unit?
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
meters per second can be a unit, because it is a unit of velocity. However, meters and seconds are also units themselves, of distance and time respectively. A unit is just what you can measure something in.
 8 months ago

RosieS12Best ResponseYou've already chosen the best response.0
ok so i put : (3.6*10^2kg) (2.32*10^5s)^2 (3.6*10^2kg) (2.32*10^5)/ (2.32*10^5)
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
And you can treat units like variables. They can cancel each other out and multiply and stuff. You see it a lot when converting.
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
I don't know if we're on the same page! I didn't get to the numbers yet, but you can do that separately.
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
Sure. I'll do a similar probably, and you'll see how I do it. Then we'll go to your problem, and apply it. I'll think of a quick one. Got it!
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
I'll make the numbers have decimals, to make it more similar. \[F=(65.3\ [kg])(9.81\ [m/s^2])\]So the units are different, and the numbers are different, but it's still physics. We'll do this: 1. Solve to see what the units are, or I guess we'd say what the unit is. 2. Solve to see what the number is, making sure we have the correct significant figures. 3. Putting them together.
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
So\[F=(65.3\ [kg])(9.81\ [m/s^2])\]\[[units\ of\ F]=[kg][m/s^2]\]\[[units\ of\ F]=\frac{[kg]\ [m]}{[s]^2}\] And kg m / s^2 is actually newtons, N. Like I said, F=ma and so [N]=[kg][m/s^2]. Your equation is like \(K=\frac{1}{2}mv^2\), which is kinetic energy, which is an energy, and it's in joules. So remember that for yours. Next, onto the numbers. Do you know how significant figures work with multiplying and dividing?
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
So now we look at the numbers, by which I mean\[F=(65.3)(9.81)\] Now that's simple, right? Its \(641.\). I had the same number of sig figs in each number. You always use the lesser amount.
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
Now, put the numbers with the units and you have \(641\ [N]\).
 8 months ago

RosieS12Best ResponseYou've already chosen the best response.0
so that would be the final answer?
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
Yup! Now to yours! Your units are \[\frac{[kg]\ [m^2]}{[s^2]}=[J]\]joules. And what is your number?
 8 months ago

RosieS12Best ResponseYou've already chosen the best response.0
well for kg we have 3.6*10^2
 8 months ago

RosieS12Best ResponseYou've already chosen the best response.0
and for m is 2.32*10^5
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
You don't actually need to consider the units now. You can look at the numbers on there own! Like, this was my example:\[F=(65.3\ [kg])(9.81\ [m/s^2])\]\[\qquad\qquad\downarrow\]\[F=(65.3)(9.81)\]
 8 months ago

RosieS12Best ResponseYou've already chosen the best response.0
so they r 3.6 and 2.32?
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
You have \[K=\frac{1}{2}(3.6*10^2 [kg]) \ (2.32*10^5 [m/s])^2\] So just take the units away. Actually, here's the text for that equation: K=\frac{1}{2}(3.6*10^2 [kg]) \ (2.32*10^5 [m/s])^2 Erase the "[kg]" and [m/s]. Then post what's left.
 8 months ago

RosieS12Best ResponseYou've already chosen the best response.0
ok so it can be 3.6*10^2 and 2.32*10^5
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
K=\frac{1}{2}(3.6*10^2 [kg]) \ (2.32*10^5 [m/s])^2 Erase the "[kg]" and [m/s]. Then post what's left. You can surround what's left in `\[` and `\]` to make OpenStudy make it look cool!
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
By doing so, you are no longer considering the units, but just the number amount.
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
Is that something you'd rather not do?
 8 months ago

RosieS12Best ResponseYou've already chosen the best response.0
im just trying to figure this out. im kida new at this
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
Understood! That's when it is the hardest! So here is everything: K=(1/2) (3.6*10^2 [kg]) (2.32*10^5 [m/s] )^2 Erase all the units. What would it be without them?
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
You can copy and paste that, or type it.
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
Here's what I mean, but I'll show you with the math feature on here.\[K=\frac{1}{2}(3.6*10^2 \cancel{[kg]}) \ (2.32*10^5 \cancel{[m/s]})^2\]\[K=\frac{1}{2}(3.6*10^2) \ (2.32*10^5)^2\]
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
\(\it{That's}\) what I meant
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
And the \(\frac{1}{2}\) is exact, so it won't affect your significant figures.
 8 months ago

theEricBest ResponseYou've already chosen the best response.2
I have to go. Good luck, and take care! Just remember to use the right number of significant figures.
 8 months ago
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