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ok so first we can convert the units

yea so wat would the next step be?

alright thanks :)

thanks i will :)

Alright. Have you started any work yet?

yea i tried and like to convert them but idk how u meant with ur method

Do you know what "work" is in physics?
If not, I'd like you to look at the equation.

ok let me write that down

wait wat do u mean by m/s isnt it one unit?

ok so i put :
(3.6*10^2kg) (2.32*10^5s)^2
(3.6*10^2kg) (2.32*10^5)/ (2.32*10^5)

is that right?

ok thanks :)

ok :)

yes

Now, put the numbers with the units and you have \(641\ [N]\).

so that would be the final answer?

Yup! Now to yours! Your units are \[\frac{[kg]\ [m^2]}{[s^2]}=[J]\]joules.
And what is your number?

well for kg we have 3.6*10^2

and for m is 2.32*10^5

so they r 3.6 and 2.32?

"[m/s]"*

ok so it can be 3.6*10^2 and 2.32*10^5

is that right?

Close....

By doing so, you are no longer considering the units, but just the number amount.

Is that something you'd rather not do?

no its fine. :)

im just trying to figure this out. im kida new at this

You can copy and paste that, or type it.

\(\it{That's}\) what I meant

And the \(\frac{1}{2}\) is exact, so it won't affect your significant figures.