A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Open

4n1m0s1ty
 one year ago
Best ResponseYou've already chosen the best response.1Here's the relationship: \[c = f*\lambda\] if c is the speed of light (which is constant in all frames of reference) and you increase \[\lambda\] which is the wavelength, what must happen to f?

theEric
 one year ago
Best ResponseYou've already chosen the best response.1I agree completely with @4n1m0s1ty , noting that \(c\) is appropriate only in a vacuum. Otherwise, you generally use "\(v\)" for velocity. In case you want to take 4n1m0s1ty 's approach another way, you use \(c=f\ \lambda\), rearrange it to be \(f=\Large\frac{c}{\lambda}\), and take out all variables that don't depend on \(f\) or \(\lambda\), but using the \(\alpha\) symbol to show proportionality rather than equality.\[f\ \ \ \alpha\ \ \ \frac{1}{\lambda}\]...It looks better on paper, but people often use that to discuss general proportionality. So, increase \(\lambda\), and see what happens to the other side. This is pretty much the same approach as 4n1m0s1ty, but more formal. That is, it's unnecessarily complex :P But it's also common. If you want to say "frequency is inversely proportional to wavelength," then you can just write \(f\ \ \ \alpha\ \ \ \Large\frac{1}{\lambda}\). Solving for \(f\) might make it easier, no matter how you do it. It just depends on how your mind works.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.