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helpplease1

  • 2 years ago

Find exact value: sin(2 cos^-1(-3/11))

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  1. zzr0ck3r
    • 2 years ago
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    there are infinite

  2. helpplease1
    • 2 years ago
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    how so?

  3. zzr0ck3r
    • 2 years ago
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    cos(x) = -3/11 has infinite solutions

  4. zzr0ck3r
    • 2 years ago
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    forget what I said, they just want the one

  5. zzr0ck3r
    • 2 years ago
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    cos^(-1)(-3/11) = 105.8 now sin(105.8) = .9622

  6. zzr0ck3r
    • 2 years ago
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    4sqrt(7)/11

  7. helpplease1
    • 2 years ago
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    thank you!

  8. surjithayer
    • 2 years ago
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    \[put \cos^{-1} \left( \frac{ -3 }{ 11 } \right)=x\] \[\cos x=\frac{ -3 }{ 11 }\] hence x lies in second or third quadrant. \[\sin x=\sqrt{1-\left( \frac{ -3 }{11 } \right)^{2}}=\sqrt{1-\frac{ 9 }{121 }}=\frac{ \sqrt{112} }{11 }\] sin x can be positive or negative according as x lies in second or third quadrant. plug in sin 2x= 2 sin x cos x

  9. helpplease1
    • 2 years ago
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    wow thank you so much!

  10. surjithayer
    • 2 years ago
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    yw

  11. zzr0ck3r
    • 2 years ago
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    woops I didn't notice the 2

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