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helpplease1
Group Title
Determine the general formula(s) for the solution. Then, determine the specific solutions on the interval [0,2pi).
2cos^2(theta)3cos(theta)+1=0
 one year ago
 one year ago
helpplease1 Group Title
Determine the general formula(s) for the solution. Then, determine the specific solutions on the interval [0,2pi). 2cos^2(theta)3cos(theta)+1=0
 one year ago
 one year ago

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looser66 Group TitleBest ResponseYou've already chosen the best response.0
still need help?
 one year ago

helpplease1 Group TitleBest ResponseYou've already chosen the best response.1
yes i do :(
 one year ago

looser66 Group TitleBest ResponseYou've already chosen the best response.0
let cos\(\theta\)= x, you have the form of \(2x^23x+1=0\) solve for x as a quadratic equation, then plulg back to x = cos \(\theta\) to solve for \(\theta\)
 one year ago

helpplease1 Group TitleBest ResponseYou've already chosen the best response.1
thank you! but i mistyped the question it is actually plus 3, not 1. :( so would the quadratic equation be \[2x ^{2}3x+3\]?
 one year ago

helpplease1 Group TitleBest ResponseYou've already chosen the best response.1
i cannot figure out how to factor that
 one year ago

looser66 Group TitleBest ResponseYou've already chosen the best response.0
which class are you in? do you know Euler's formula for complex number?
 one year ago

helpplease1 Group TitleBest ResponseYou've already chosen the best response.1
i am just in a college trig class. 1316. we have not gotten to euler's formula thus far
 one year ago

helpplease1 Group TitleBest ResponseYou've already chosen the best response.1
this is the actual problem \[2\sin ^{2}\Theta3\cos \Theta=3\]
 one year ago

looser66 Group TitleBest ResponseYou've already chosen the best response.0
hey, it totally different,!! heehe , let see. 2 sin^2 = 2  2cos^2 therefore, 22cos^2 3 cos +3 =0 2cos^2 +3 cos 5 =0, can solve it now
 one year ago

looser66 Group TitleBest ResponseYou've already chosen the best response.0
you should post the original one, friend.
 one year ago

looser66 Group TitleBest ResponseYou've already chosen the best response.0
you really scared me!! I thought I met a Ph.D student.
 one year ago

helpplease1 Group TitleBest ResponseYou've already chosen the best response.1
lol i know i got it confused with another problem. I was really good at algebra but this stuff is just killing me...
 one year ago

helpplease1 Group TitleBest ResponseYou've already chosen the best response.1
hahaha no ph.d student here
 one year ago

looser66 Group TitleBest ResponseYou've already chosen the best response.0
so? everything is quite simple, right?
 one year ago

helpplease1 Group TitleBest ResponseYou've already chosen the best response.1
so i have \[2x ^{2}+3x5=0\] and now factor? im sorry this class has confused me so much
 one year ago

looser66 Group TitleBest ResponseYou've already chosen the best response.0
if you know how to factor, do it. if not, use discriminant. Either way is ok.
 one year ago

helpplease1 Group TitleBest ResponseYou've already chosen the best response.1
x=5/2 and x=1?
 one year ago

looser66 Group TitleBest ResponseYou've already chosen the best response.0
yes, and reject 5/2, out of interval
 one year ago

helpplease1 Group TitleBest ResponseYou've already chosen the best response.1
okay. so: cos(theta)=1? how do i make the general formula in form of of: _+_k
 one year ago

looser66 Group TitleBest ResponseYou've already chosen the best response.0
not finish yet, cos \(\theta\) =1 \(\rightarrow \theta\) = 0 + 2k\(\pi\) that 's the general formula solution for you
 one year ago

helpplease1 Group TitleBest ResponseYou've already chosen the best response.1
so the only solution is 0? because subbing 1 for k would make 2pi which would not be included in the interval?
 one year ago

looser66 Group TitleBest ResponseYou've already chosen the best response.0
yes, you are right. general form is 2kpi, specific solution in the interval is 0 Medal for a good student
 one year ago

helpplease1 Group TitleBest ResponseYou've already chosen the best response.1
oh my gosh thank you so much for your help!
 one year ago

looser66 Group TitleBest ResponseYou've already chosen the best response.0
do I help? No! just you work on it, I did nothing. hehee
 one year ago
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