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anonymous
 2 years ago
Determine the general formula(s) for the solution. Then, determine the specific solutions on the interval [0,2pi).
2cos^2(theta)3cos(theta)+1=0
anonymous
 2 years ago
Determine the general formula(s) for the solution. Then, determine the specific solutions on the interval [0,2pi). 2cos^2(theta)3cos(theta)+1=0

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0let cos\(\theta\)= x, you have the form of \(2x^23x+1=0\) solve for x as a quadratic equation, then plulg back to x = cos \(\theta\) to solve for \(\theta\)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0thank you! but i mistyped the question it is actually plus 3, not 1. :( so would the quadratic equation be \[2x ^{2}3x+3\]?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0i cannot figure out how to factor that

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0which class are you in? do you know Euler's formula for complex number?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0i am just in a college trig class. 1316. we have not gotten to euler's formula thus far

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0this is the actual problem \[2\sin ^{2}\Theta3\cos \Theta=3\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0hey, it totally different,!! heehe , let see. 2 sin^2 = 2  2cos^2 therefore, 22cos^2 3 cos +3 =0 2cos^2 +3 cos 5 =0, can solve it now

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0you should post the original one, friend.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0you really scared me!! I thought I met a Ph.D student.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0lol i know i got it confused with another problem. I was really good at algebra but this stuff is just killing me...

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0hahaha no ph.d student here

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0so? everything is quite simple, right?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0so i have \[2x ^{2}+3x5=0\] and now factor? im sorry this class has confused me so much

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0if you know how to factor, do it. if not, use discriminant. Either way is ok.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0yes, and reject 5/2, out of interval

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0okay. so: cos(theta)=1? how do i make the general formula in form of of: _+_k

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0not finish yet, cos \(\theta\) =1 \(\rightarrow \theta\) = 0 + 2k\(\pi\) that 's the general formula solution for you

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0so the only solution is 0? because subbing 1 for k would make 2pi which would not be included in the interval?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0yes, you are right. general form is 2kpi, specific solution in the interval is 0 Medal for a good student

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0oh my gosh thank you so much for your help!

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0do I help? No! just you work on it, I did nothing. hehee
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