A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Determine the general formula(s) for the solution. Then, determine the specific solutions on the interval [0,2pi).
2cos^2(theta)3cos(theta)+1=0
anonymous
 3 years ago
Determine the general formula(s) for the solution. Then, determine the specific solutions on the interval [0,2pi). 2cos^2(theta)3cos(theta)+1=0

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0let cos\(\theta\)= x, you have the form of \(2x^23x+1=0\) solve for x as a quadratic equation, then plulg back to x = cos \(\theta\) to solve for \(\theta\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you! but i mistyped the question it is actually plus 3, not 1. :( so would the quadratic equation be \[2x ^{2}3x+3\]?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i cannot figure out how to factor that

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0which class are you in? do you know Euler's formula for complex number?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i am just in a college trig class. 1316. we have not gotten to euler's formula thus far

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this is the actual problem \[2\sin ^{2}\Theta3\cos \Theta=3\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hey, it totally different,!! heehe , let see. 2 sin^2 = 2  2cos^2 therefore, 22cos^2 3 cos +3 =0 2cos^2 +3 cos 5 =0, can solve it now

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you should post the original one, friend.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you really scared me!! I thought I met a Ph.D student.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lol i know i got it confused with another problem. I was really good at algebra but this stuff is just killing me...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hahaha no ph.d student here

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so? everything is quite simple, right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so i have \[2x ^{2}+3x5=0\] and now factor? im sorry this class has confused me so much

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if you know how to factor, do it. if not, use discriminant. Either way is ok.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes, and reject 5/2, out of interval

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay. so: cos(theta)=1? how do i make the general formula in form of of: _+_k

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0not finish yet, cos \(\theta\) =1 \(\rightarrow \theta\) = 0 + 2k\(\pi\) that 's the general formula solution for you

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so the only solution is 0? because subbing 1 for k would make 2pi which would not be included in the interval?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes, you are right. general form is 2kpi, specific solution in the interval is 0 Medal for a good student

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh my gosh thank you so much for your help!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do I help? No! just you work on it, I did nothing. hehee
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.