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helpplease1
 one year ago
Determine the general formula(s) for the solution. Then, determine the specific solutions on the interval [0,2pi).
2cos^2(theta)3cos(theta)+1=0
helpplease1
 one year ago
Determine the general formula(s) for the solution. Then, determine the specific solutions on the interval [0,2pi). 2cos^2(theta)3cos(theta)+1=0

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looser66
 one year ago
Best ResponseYou've already chosen the best response.0let cos\(\theta\)= x, you have the form of \(2x^23x+1=0\) solve for x as a quadratic equation, then plulg back to x = cos \(\theta\) to solve for \(\theta\)

helpplease1
 one year ago
Best ResponseYou've already chosen the best response.1thank you! but i mistyped the question it is actually plus 3, not 1. :( so would the quadratic equation be \[2x ^{2}3x+3\]?

helpplease1
 one year ago
Best ResponseYou've already chosen the best response.1i cannot figure out how to factor that

looser66
 one year ago
Best ResponseYou've already chosen the best response.0which class are you in? do you know Euler's formula for complex number?

helpplease1
 one year ago
Best ResponseYou've already chosen the best response.1i am just in a college trig class. 1316. we have not gotten to euler's formula thus far

helpplease1
 one year ago
Best ResponseYou've already chosen the best response.1this is the actual problem \[2\sin ^{2}\Theta3\cos \Theta=3\]

looser66
 one year ago
Best ResponseYou've already chosen the best response.0hey, it totally different,!! heehe , let see. 2 sin^2 = 2  2cos^2 therefore, 22cos^2 3 cos +3 =0 2cos^2 +3 cos 5 =0, can solve it now

looser66
 one year ago
Best ResponseYou've already chosen the best response.0you should post the original one, friend.

looser66
 one year ago
Best ResponseYou've already chosen the best response.0you really scared me!! I thought I met a Ph.D student.

helpplease1
 one year ago
Best ResponseYou've already chosen the best response.1lol i know i got it confused with another problem. I was really good at algebra but this stuff is just killing me...

helpplease1
 one year ago
Best ResponseYou've already chosen the best response.1hahaha no ph.d student here

looser66
 one year ago
Best ResponseYou've already chosen the best response.0so? everything is quite simple, right?

helpplease1
 one year ago
Best ResponseYou've already chosen the best response.1so i have \[2x ^{2}+3x5=0\] and now factor? im sorry this class has confused me so much

looser66
 one year ago
Best ResponseYou've already chosen the best response.0if you know how to factor, do it. if not, use discriminant. Either way is ok.

looser66
 one year ago
Best ResponseYou've already chosen the best response.0yes, and reject 5/2, out of interval

helpplease1
 one year ago
Best ResponseYou've already chosen the best response.1okay. so: cos(theta)=1? how do i make the general formula in form of of: _+_k

looser66
 one year ago
Best ResponseYou've already chosen the best response.0not finish yet, cos \(\theta\) =1 \(\rightarrow \theta\) = 0 + 2k\(\pi\) that 's the general formula solution for you

helpplease1
 one year ago
Best ResponseYou've already chosen the best response.1so the only solution is 0? because subbing 1 for k would make 2pi which would not be included in the interval?

looser66
 one year ago
Best ResponseYou've already chosen the best response.0yes, you are right. general form is 2kpi, specific solution in the interval is 0 Medal for a good student

helpplease1
 one year ago
Best ResponseYou've already chosen the best response.1oh my gosh thank you so much for your help!

looser66
 one year ago
Best ResponseYou've already chosen the best response.0do I help? No! just you work on it, I did nothing. hehee
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