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anonymous
 3 years ago
calculating the limit:
anonymous
 3 years ago
calculating the limit:

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The last one is obviously 1000

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes but i tried sketching only it takes to long, and it says calculate

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@FutureMathProfessor do you know how to calculate? instead of sketching.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The first one is undefined, the second one is 12, the third one is 1000 since it's undefined because the first 2 limits aren't equal to each other, which means undefined.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0are you guessing? @Idealist

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0because it's wrong. the second one is ZERO.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0does anyone know how to calculate or not.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i didn't ask for the answer.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@idealist Might wanna check your arithmatic

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm not guessing. Since the first limit is 2, which means you must plug in 2 into the function where it says x<2, the second limit is 2+, which means you must plug in to x>2, whatever you get, if these 2 limits don't have the same answer, then the last limit will be undefined and the answer will be 1000.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0And you're right, if you plug in 2 for the second limit, the answer is 0. I was mindless because I plugged in 2 instead of 2. But now you know it. I'm not guessing.
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