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mathcalculus

  • 2 years ago

calculating the limit:

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  1. mathcalculus
    • 2 years ago
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  2. FutureMathProfessor
    • 2 years ago
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    The last one is obviously 1000

  3. mathcalculus
    • 2 years ago
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    yes but i tried sketching only it takes to long, and it says calculate

  4. mathcalculus
    • 2 years ago
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    @FutureMathProfessor do you know how to calculate? instead of sketching.

  5. Idealist
    • 2 years ago
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    The first one is undefined, the second one is 12, the third one is 1000 since it's undefined because the first 2 limits aren't equal to each other, which means undefined.

  6. mathcalculus
    • 2 years ago
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    are you guessing? @Idealist

  7. mathcalculus
    • 2 years ago
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    because it's wrong. the second one is ZERO.

  8. mathcalculus
    • 2 years ago
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    does anyone know how to calculate or not.

  9. mathcalculus
    • 2 years ago
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    i didn't ask for the answer.

  10. FutureMathProfessor
    • 2 years ago
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    @idealist Might wanna check your arithmatic

  11. Idealist
    • 2 years ago
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    I'm not guessing. Since the first limit is -2-, which means you must plug in -2 into the function where it says x<-2, the second limit is -2+, which means you must plug in to x>-2, whatever you get, if these 2 limits don't have the same answer, then the last limit will be undefined and the answer will be 1000.

  12. Idealist
    • 2 years ago
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    And you're right, if you plug in -2 for the second limit, the answer is 0. I was mindless because I plugged in 2 instead of -2. But now you know it. I'm not guessing.

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