Here's the question you clicked on:
mathcalculus
help: calculating the limit and not by sketching the graph.
THe last one is 1000
that wasn't my question.
right. so can any one explain to me and show me how they calculated.
i don't need the answer. i need an explanation. understanding.
Limits of intersections of piecewise functions don't exist. Have a good day.
just take a look at the equation if you were below -2 I mean imagine -2.1the answer would be infinitive and when the number is greater than -2 imagine -1.9 the answer is near 0 so because the left and right limits are not the same , we conclude that the limit does not exist
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now i see the 1st answer. but not the 2nd. which is it zero?
how did you calculate.
i understand from looking at the graph
but i don't understand how you used calculation to find the answer.
For the first one, the left hand limit at -2: plug in something like -2.001 into the function -2/(x+2) and see what the result is. Then make x even closer to -2, like -2.000001 then -2.00000000001 and see if you notice a pattern. For the right hand limit, just plug x=-2 into 3x+6 and get the result.
if they say:CALCULATE. then there must be some sort of wy, not only by sketching.
^sometimes you have to do it numerically. CALCULATE can mean... use numerical methods.
when you put -2 instead of x in left hand limit you will see the answer is a number in num and zero in dem that means infinit
to calculate it you just have to find the left hand side and the right hand side limit and you should show they are not the same