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mathcalculus
Group Title
Help: CONTINUITY and removable discontinuity:
(attached below)
 one year ago
 one year ago
mathcalculus Group Title
Help: CONTINUITY and removable discontinuity: (attached below)
 one year ago
 one year ago

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RogerSmith Group TitleBest ResponseYou've already chosen the best response.1
wouldn't the limit from the left be equal to 40, not 4
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
yes, it is 40. i sketched the graph. now i didn't see 40 in it.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
every graph that i sketched i usually can tell the answer. BUT for this one, i wasn't able to.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
can you tell me whats wrong? where did i go wrong in the problem?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
@RogerSmith
 one year ago

RogerSmith Group TitleBest ResponseYou've already chosen the best response.1
okay when you look at the piecewise function, you are first trying to see if the function is continuous. You can see that it is because if you look at the limit you have at the top (steps 13), you will see that when you approach a from the left, you must use the equation 8x8. If you are approaching the point from the right, you will use the other equation (1/x+4)
 one year ago

RogerSmith Group TitleBest ResponseYou've already chosen the best response.1
now the point in question is 6. It is asking you whether the function is continuous at a=6. That means if we take the limit from the left side, and the limit from the right side, they should both equal to the same number. Now you have the part correct when you approach 6 from the right. If you look at the piecewise function it says when a is GREATER THAN OR EQUAL TO 6, use the equation on the bottom. You correctly solved this by plugging in 6, and you see that your answer for the right hand limit is 1/10
 one year ago

RogerSmith Group TitleBest ResponseYou've already chosen the best response.1
Now, since we know that when we take the limit to the right of 6, you should be approaching the value of 1/10. however, check the left hand limit. if we are approaching 6 from the left, that means we are chosing values smaller than 6. If you look at the piecewise again, it says for values <6, use 8x8. Plug 6 in for X and solve. 8(6)8 = 488 = 40
 one year ago

RogerSmith Group TitleBest ResponseYou've already chosen the best response.1
The left and right hand limits do not equal the same thing. you can see that from the left, x approaches 40, while from the right, it approaches 1/10. Since the two don't match, there is a jump discontinuity. Therefore, the function is not continuous at x=6.
 one year ago

RogerSmith Group TitleBest ResponseYou've already chosen the best response.1
f(6) = 1/10 f(6) from the right =approaches 1/10 f(6) from left = approaches 40
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
okay i figured out from the right side. 1/10 but when i sketched the graph i couldn't tell where x appraoches to 6 from the left side
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
normally when i sketch i can tell, why is it that i couldn't see it before?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
@RogerSmith
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i see your point but i can't always plug in any number into the first function. it wouuld be wrong. in this case, we can.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
however, i want to know how to get 40 from the sketch.
 one year ago
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