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when we evaluate the limit, do we not substitute?

this is where i'm confused.

in this case, i got the answer right. i kind of took a smart guess

@pgpilot326 a little

indeterminate form meaning.... 0/0?

i got the numerator..319/8 and the denominator -77/8

And indeterminate form can mean more than just 0/0. For the purposes of calc 1, yeah, 0/0

i simply subtracted and simplified.

but i saw that they asked infinity or non infinity etc etc

so i guessed.

oh...k

so what i did was wrong?

so.... how should i do it?

im more confused now. :/

yeah what if i wanted to use 11/8

it's kidn of the same thing... right?

i see that one goes really high up and the other goes really down.

Then you will get an undefined answer. An undefined answer does you no good.

no i didn't get an undefined answer...

Oh, I apologize, I did not look correctly. I'm brain cramping then, ignore what I've said x_x

oh boy.

x\

Wait, what? You DIDNT get an undefined? 11- 8(11/8)?

@pgpilot326 show it pls

Yeah. nvm, I'm clearly being confusing. I'll leave, sorry.

#1) can i simply substitute 11/8 into the equation? yes or no?

okay no, this method confused me from the beginning. :/

lemme erase all that nonsense and see if i can explain this :)

I plugged 11/8 directly in.

negative?

oh ok i see where you got the number from

negative? Is that in response to the question about the denominator?

i think, not sure. i think it's negative.

^ yah make sure you're comfortable with \(\large \lim_{x\to0}\dfrac{1}{x}\)
as pilot explained.

But don't forget what the top is doing too.

i know this: ex: 1/x all real numbers except x=0

with this problem. im just so so confused on to how to approach it.

ex: step by step. and the understanding part is the hardest part.

lol it does.

thanks i understand it much better.

i see that the left side is coming from the negative side. and right from the positive.

now let's say for this problem:

h/o

i substituted all 7 in.... the problem is the signs right and left.

i got them wrong.

i typed in n, p, dne