## kshoaf 2 years ago how does (sec^2(x)-1)/(sec^2(x))=1-cos^2(x)

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1. Hashir

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2. Hashir

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3. Hashir

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4. kshoaf

lol thanks im thinking to hard

5. flixoe

First, split the left-side fraction into two: (sec^2(x)-1)/(sec^2(x))=1-cos^2(x) (sec^2(x)/(sec^2(x) - 1/(sec^2(x)) = 1 - cos^2(x) Then, simplify the first item to 1: (sec^2(x)/(sec^2(x) - 1/(sec^2(x)) = 1 - cos^2(x) 1 - 1/(sec^2(x)) = 1 - cos^2(x) Lastly, simplify sec^2(x) into cosine: 1 - 1/(sec^2(x)) = 1 - cos^2(x) 1 - cos^2(x) = 1 - cos^2(x) And it's equal.

6. Hashir

@kshoaf : LOL... pleasure :)

7. Hashir

thinking hard is not to good for health ;)

8. kshoaf

not at all...especially with a final tomorrow. How am I supposed to do the hard stuff when I'm over thinking the simple steps

9. Hashir

aw... you will ace it :) dont worry

10. Hashir

the best thing to do before a maths test is relax :D

11. kshoaf

Thanks!

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