A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.1i got 3/5 but it's wrong.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.1@kropot72 do you know this?

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.1@satellite73 any ideas?

hihihii
 one year ago
Best ResponseYou've already chosen the best response.0if the denominator grows bigger than the numerator, then the limit is 0

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.1oh so we don;t need to divide by x? or do anything to it?

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.1thanks! :) @hihihii

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow \infty} \dfrac{3x + 2}{3x^2  5x + 8}\] \[ =\lim_{x \rightarrow \infty} \dfrac{ x^2 \left( \frac{3}{x} + \frac{2}{x^2} \right) } {x^2 \left( 3  \frac{5}{x} + \frac{8}{x^2} \right) }\] \[ = \lim_{x \rightarrow \infty} \dfrac{ \frac{3}{x} + \frac{2}{x^2} } { 3  \frac{5}{x} + \frac{8}{x^2} } \] \[ = \dfrac{ 0 + 0} { 3  0 + 0 } \] \(= 0\)

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.1thanks u @mathstudent55
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.