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HELP: evaluating limits to infinity by dividing x
(ATTACHED BELOW)
 9 months ago
 9 months ago
HELP: evaluating limits to infinity by dividing x (ATTACHED BELOW)
 9 months ago
 9 months ago

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mathcalculusBest ResponseYou've already chosen the best response.1
i got 3/5 but it's wrong.
 9 months ago

mathcalculusBest ResponseYou've already chosen the best response.1
@kropot72 do you know this?
 9 months ago

mathcalculusBest ResponseYou've already chosen the best response.1
@satellite73 any ideas?
 9 months ago

hihihiiBest ResponseYou've already chosen the best response.0
if the denominator grows bigger than the numerator, then the limit is 0
 9 months ago

mathcalculusBest ResponseYou've already chosen the best response.1
oh so we don;t need to divide by x? or do anything to it?
 9 months ago

mathcalculusBest ResponseYou've already chosen the best response.1
thanks! :) @hihihii
 9 months ago

mathstudent55Best ResponseYou've already chosen the best response.1
\[\lim_{x \rightarrow \infty} \dfrac{3x + 2}{3x^2  5x + 8}\] \[ =\lim_{x \rightarrow \infty} \dfrac{ x^2 \left( \frac{3}{x} + \frac{2}{x^2} \right) } {x^2 \left( 3  \frac{5}{x} + \frac{8}{x^2} \right) }\] \[ = \lim_{x \rightarrow \infty} \dfrac{ \frac{3}{x} + \frac{2}{x^2} } { 3  \frac{5}{x} + \frac{8}{x^2} } \] \[ = \dfrac{ 0 + 0} { 3  0 + 0 } \] \(= 0\)
 9 months ago

mathcalculusBest ResponseYou've already chosen the best response.1
thanks u @mathstudent55
 9 months ago
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