Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

mathcalculus Group Title

HELP: find the horizontal limits of the function. (ATTACHED BELOW)

  • one year ago
  • one year ago

  • This Question is Closed
  1. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    • one year ago
  2. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @dumbcow

    • one year ago
  3. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i got 11/-6

    • one year ago
  4. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    and im not sure for the other one

    • one year ago
  5. sami-21 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    thats correct

    • one year ago
  6. Roya Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    dear by horizontal limit u mean limit in infinite ?

    • one year ago
  7. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    it doesnt say..

    • one year ago
  8. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    everything is attached

    • one year ago
  9. sami-21 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Horizantal limit is -11/6

    • one year ago
  10. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    it says and

    • one year ago
  11. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    is there 2 answers?

    • one year ago
  12. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    are*

    • one year ago
  13. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i wrote my answers thrre but im not sure if theyre correct

    • one year ago
  14. sami-21 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    no the one -11/6 is correct @Roya yes it means take the limit at infinity .

    • one year ago
  15. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    oh ok

    • one year ago
  16. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes its right

    • one year ago
  17. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    thank yoou

    • one year ago
  18. sami-21 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yw :)

    • one year ago
  19. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @sami-21 what if it is to -infinity

    • one year ago
  20. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    is it the same thing?

    • one year ago
  21. Roya Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    considering this you answer is correct .

    • one year ago
  22. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    what if it say as x approaches to negtive infinity

    • one year ago
  23. sami-21 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    its gonna produce similar result because the answer is depending on the coefficients of highest terms in both numerator and denominator .

    • one year ago
  24. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    lets say for this one. the first one: i got -2

    • one year ago
  25. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    • one year ago
  26. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    but the second question asks: if it's coming from - infinity. @sami-21

    • one year ago
  27. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @Roya

    • one year ago
  28. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @sami-21

    • one year ago
  29. sami-21 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    still -2

    • one year ago
  30. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    can someone explain why the negative infinity part right?

    • one year ago
  31. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @sami-21 i know it's -2 so how do we know it's -2? since i found the infinity part... and to find the negative infinity part would be.. ?

    • one year ago
  32. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    the same thing?

    • one year ago
  33. Roya Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    there is no different between + or - infinity. while solving these kind of question you ignore other part because infinity is so great. regardless it's positive or negative

    • one year ago
  34. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so if i solved for infinity, an it asked me the -infinity, the answer is the same?

    • one year ago
  35. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @Roya

    • one year ago
  36. Roya Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    yes the same answer

    • one year ago
  37. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    oh okay great thanks you

    • one year ago
  38. sami-21 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    as i mentioned above these limits depends on the coefficients of the highest terms in both numerator and denominator . lets give it a try divide both numerator and denominator with highest power (here it is simply x ) \[\Large \lim_{x \rightarrow -\infty} \frac{ \frac{4+8x}{x}}{\frac{3-4x}{x}}\] \[\Large \lim_{x \rightarrow -\infty} \frac{\frac{4}{x}+8}{\frac{3}{x}-4}\] apply the limits \[\Large \lim_{x \rightarrow -\infty} \frac{\frac{4}{-\infty}+8}{\frac{3}{-\infty}-4}\] \[\Large \frac{-0+8}{-0-4}=\frac{8}{-4}=-2\]

    • one year ago
  39. Roya Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    just take care of function with different behavior along x axis . I mean the fuction which have different function for each of the X axis part |dw:1375077760801:dw|

    • one year ago
  40. sami-21 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @mathcalculus I hope its clear now . in these cases yes both in _ or - infinity answer remains unchanged . just look at the coefficients of highest terms .

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.