mathcalculus
HELP: find the horizontal limits of the function.
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mathcalculus
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mathcalculus
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@dumbcow
mathcalculus
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i got 11/-6
mathcalculus
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and im not sure for the other one
sami-21
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thats correct
Roya
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dear by horizontal limit u mean limit in infinite ?
mathcalculus
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it doesnt say..
mathcalculus
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everything is attached
sami-21
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Horizantal limit is -11/6
mathcalculus
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it says and
mathcalculus
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is there 2 answers?
mathcalculus
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are*
mathcalculus
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i wrote my answers thrre but im not sure if theyre correct
sami-21
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no the one -11/6 is correct
@Roya yes it means take the limit at infinity .
mathcalculus
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oh ok
mathcalculus
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yes its right
mathcalculus
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thank yoou
sami-21
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yw :)
mathcalculus
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@sami-21 what if it is to -infinity
mathcalculus
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is it the same thing?
Roya
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considering this you answer is correct .
mathcalculus
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what if it say as x approaches to negtive infinity
sami-21
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its gonna produce similar result because the answer is depending on the coefficients of highest terms in both numerator and denominator .
mathcalculus
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lets say for this one. the first one: i got -2
mathcalculus
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mathcalculus
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but the second question asks: if it's coming from - infinity. @sami-21
mathcalculus
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@Roya
mathcalculus
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@sami-21
sami-21
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still -2
mathcalculus
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can someone explain why the negative infinity part right?
mathcalculus
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@sami-21 i know it's -2 so how do we know it's -2? since i found the infinity part... and to find the negative infinity part would be.. ?
mathcalculus
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the same thing?
Roya
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there is no different between + or - infinity. while solving these kind of question you ignore other part because infinity is so great. regardless it's positive or negative
mathcalculus
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so if i solved for infinity, an it asked me the -infinity, the answer is the same?
mathcalculus
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@Roya
Roya
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yes the same answer
mathcalculus
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oh okay great thanks you
sami-21
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as i mentioned above these limits depends on the coefficients of the highest terms in both numerator and denominator .
lets give it a try
divide both numerator and denominator with highest power (here it is simply x )
\[\Large \lim_{x \rightarrow -\infty} \frac{ \frac{4+8x}{x}}{\frac{3-4x}{x}}\]
\[\Large \lim_{x \rightarrow -\infty} \frac{\frac{4}{x}+8}{\frac{3}{x}-4}\]
apply the limits
\[\Large \lim_{x \rightarrow -\infty} \frac{\frac{4}{-\infty}+8}{\frac{3}{-\infty}-4}\]
\[\Large \frac{-0+8}{-0-4}=\frac{8}{-4}=-2\]
Roya
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just take care of function with different behavior along x axis . I mean the fuction which have different function for each of the X axis part |dw:1375077760801:dw|
sami-21
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@mathcalculus I hope its clear now .
in these cases yes both in _ or - infinity answer remains unchanged . just look at the coefficients of highest terms .