HELP: find the horizontal limits of the function. (ATTACHED BELOW)

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HELP: find the horizontal limits of the function. (ATTACHED BELOW)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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i got 11/-6

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Other answers:

and im not sure for the other one
thats correct
dear by horizontal limit u mean limit in infinite ?
it doesnt say..
everything is attached
Horizantal limit is -11/6
it says and
is there 2 answers?
are*
i wrote my answers thrre but im not sure if theyre correct
no the one -11/6 is correct @Roya yes it means take the limit at infinity .
oh ok
yes its right
thank yoou
yw :)
@sami-21 what if it is to -infinity
is it the same thing?
considering this you answer is correct .
what if it say as x approaches to negtive infinity
its gonna produce similar result because the answer is depending on the coefficients of highest terms in both numerator and denominator .
lets say for this one. the first one: i got -2
but the second question asks: if it's coming from - infinity. @sami-21
still -2
can someone explain why the negative infinity part right?
@sami-21 i know it's -2 so how do we know it's -2? since i found the infinity part... and to find the negative infinity part would be.. ?
the same thing?
there is no different between + or - infinity. while solving these kind of question you ignore other part because infinity is so great. regardless it's positive or negative
so if i solved for infinity, an it asked me the -infinity, the answer is the same?
yes the same answer
oh okay great thanks you
as i mentioned above these limits depends on the coefficients of the highest terms in both numerator and denominator . lets give it a try divide both numerator and denominator with highest power (here it is simply x ) \[\Large \lim_{x \rightarrow -\infty} \frac{ \frac{4+8x}{x}}{\frac{3-4x}{x}}\] \[\Large \lim_{x \rightarrow -\infty} \frac{\frac{4}{x}+8}{\frac{3}{x}-4}\] apply the limits \[\Large \lim_{x \rightarrow -\infty} \frac{\frac{4}{-\infty}+8}{\frac{3}{-\infty}-4}\] \[\Large \frac{-0+8}{-0-4}=\frac{8}{-4}=-2\]
just take care of function with different behavior along x axis . I mean the fuction which have different function for each of the X axis part |dw:1375077760801:dw|
@mathcalculus I hope its clear now . in these cases yes both in _ or - infinity answer remains unchanged . just look at the coefficients of highest terms .

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