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mathcalculus

HELP: find the horizontal limits of the function. (ATTACHED BELOW)

  • 8 months ago
  • 8 months ago

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  1. mathcalculus
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    • 8 months ago
  2. mathcalculus
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    @dumbcow

    • 8 months ago
  3. mathcalculus
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    i got 11/-6

    • 8 months ago
  4. mathcalculus
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    and im not sure for the other one

    • 8 months ago
  5. sami-21
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    thats correct

    • 8 months ago
  6. Roya
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    dear by horizontal limit u mean limit in infinite ?

    • 8 months ago
  7. mathcalculus
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    it doesnt say..

    • 8 months ago
  8. mathcalculus
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    everything is attached

    • 8 months ago
  9. sami-21
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    Horizantal limit is -11/6

    • 8 months ago
  10. mathcalculus
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    it says and

    • 8 months ago
  11. mathcalculus
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    is there 2 answers?

    • 8 months ago
  12. mathcalculus
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    are*

    • 8 months ago
  13. mathcalculus
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    i wrote my answers thrre but im not sure if theyre correct

    • 8 months ago
  14. sami-21
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    no the one -11/6 is correct @Roya yes it means take the limit at infinity .

    • 8 months ago
  15. mathcalculus
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    oh ok

    • 8 months ago
  16. mathcalculus
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    yes its right

    • 8 months ago
  17. mathcalculus
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    thank yoou

    • 8 months ago
  18. sami-21
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    yw :)

    • 8 months ago
  19. mathcalculus
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    @sami-21 what if it is to -infinity

    • 8 months ago
  20. mathcalculus
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    is it the same thing?

    • 8 months ago
  21. Roya
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    considering this you answer is correct .

    • 8 months ago
  22. mathcalculus
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    what if it say as x approaches to negtive infinity

    • 8 months ago
  23. sami-21
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    its gonna produce similar result because the answer is depending on the coefficients of highest terms in both numerator and denominator .

    • 8 months ago
  24. mathcalculus
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    lets say for this one. the first one: i got -2

    • 8 months ago
  25. mathcalculus
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    • 8 months ago
  26. mathcalculus
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    but the second question asks: if it's coming from - infinity. @sami-21

    • 8 months ago
  27. mathcalculus
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    @Roya

    • 8 months ago
  28. mathcalculus
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    @sami-21

    • 8 months ago
  29. sami-21
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    still -2

    • 8 months ago
  30. mathcalculus
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    can someone explain why the negative infinity part right?

    • 8 months ago
  31. mathcalculus
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    @sami-21 i know it's -2 so how do we know it's -2? since i found the infinity part... and to find the negative infinity part would be.. ?

    • 8 months ago
  32. mathcalculus
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    the same thing?

    • 8 months ago
  33. Roya
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    there is no different between + or - infinity. while solving these kind of question you ignore other part because infinity is so great. regardless it's positive or negative

    • 8 months ago
  34. mathcalculus
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    so if i solved for infinity, an it asked me the -infinity, the answer is the same?

    • 8 months ago
  35. mathcalculus
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    @Roya

    • 8 months ago
  36. Roya
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    yes the same answer

    • 8 months ago
  37. mathcalculus
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    oh okay great thanks you

    • 8 months ago
  38. sami-21
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    as i mentioned above these limits depends on the coefficients of the highest terms in both numerator and denominator . lets give it a try divide both numerator and denominator with highest power (here it is simply x ) \[\Large \lim_{x \rightarrow -\infty} \frac{ \frac{4+8x}{x}}{\frac{3-4x}{x}}\] \[\Large \lim_{x \rightarrow -\infty} \frac{\frac{4}{x}+8}{\frac{3}{x}-4}\] apply the limits \[\Large \lim_{x \rightarrow -\infty} \frac{\frac{4}{-\infty}+8}{\frac{3}{-\infty}-4}\] \[\Large \frac{-0+8}{-0-4}=\frac{8}{-4}=-2\]

    • 8 months ago
  39. Roya
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    just take care of function with different behavior along x axis . I mean the fuction which have different function for each of the X axis part |dw:1375077760801:dw|

    • 8 months ago
  40. sami-21
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    @mathcalculus I hope its clear now . in these cases yes both in _ or - infinity answer remains unchanged . just look at the coefficients of highest terms .

    • 8 months ago
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