## mathcalculus Group Title HELP: find the horizontal limits of the function. (ATTACHED BELOW) 11 months ago 11 months ago

1. mathcalculus Group Title

2. mathcalculus Group Title

@dumbcow

3. mathcalculus Group Title

i got 11/-6

4. mathcalculus Group Title

and im not sure for the other one

5. sami-21 Group Title

thats correct

6. Roya Group Title

dear by horizontal limit u mean limit in infinite ?

7. mathcalculus Group Title

it doesnt say..

8. mathcalculus Group Title

everything is attached

9. sami-21 Group Title

Horizantal limit is -11/6

10. mathcalculus Group Title

it says and

11. mathcalculus Group Title

12. mathcalculus Group Title

are*

13. mathcalculus Group Title

i wrote my answers thrre but im not sure if theyre correct

14. sami-21 Group Title

no the one -11/6 is correct @Roya yes it means take the limit at infinity .

15. mathcalculus Group Title

oh ok

16. mathcalculus Group Title

yes its right

17. mathcalculus Group Title

thank yoou

18. sami-21 Group Title

yw :)

19. mathcalculus Group Title

@sami-21 what if it is to -infinity

20. mathcalculus Group Title

is it the same thing?

21. Roya Group Title

considering this you answer is correct .

22. mathcalculus Group Title

what if it say as x approaches to negtive infinity

23. sami-21 Group Title

its gonna produce similar result because the answer is depending on the coefficients of highest terms in both numerator and denominator .

24. mathcalculus Group Title

lets say for this one. the first one: i got -2

25. mathcalculus Group Title

26. mathcalculus Group Title

but the second question asks: if it's coming from - infinity. @sami-21

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@Roya

28. mathcalculus Group Title

@sami-21

29. sami-21 Group Title

still -2

30. mathcalculus Group Title

can someone explain why the negative infinity part right?

31. mathcalculus Group Title

@sami-21 i know it's -2 so how do we know it's -2? since i found the infinity part... and to find the negative infinity part would be.. ?

32. mathcalculus Group Title

the same thing?

33. Roya Group Title

there is no different between + or - infinity. while solving these kind of question you ignore other part because infinity is so great. regardless it's positive or negative

34. mathcalculus Group Title

so if i solved for infinity, an it asked me the -infinity, the answer is the same?

35. mathcalculus Group Title

@Roya

36. Roya Group Title

37. mathcalculus Group Title

oh okay great thanks you

38. sami-21 Group Title

as i mentioned above these limits depends on the coefficients of the highest terms in both numerator and denominator . lets give it a try divide both numerator and denominator with highest power (here it is simply x ) $\Large \lim_{x \rightarrow -\infty} \frac{ \frac{4+8x}{x}}{\frac{3-4x}{x}}$ $\Large \lim_{x \rightarrow -\infty} \frac{\frac{4}{x}+8}{\frac{3}{x}-4}$ apply the limits $\Large \lim_{x \rightarrow -\infty} \frac{\frac{4}{-\infty}+8}{\frac{3}{-\infty}-4}$ $\Large \frac{-0+8}{-0-4}=\frac{8}{-4}=-2$

39. Roya Group Title

just take care of function with different behavior along x axis . I mean the fuction which have different function for each of the X axis part |dw:1375077760801:dw|

40. sami-21 Group Title

@mathcalculus I hope its clear now . in these cases yes both in _ or - infinity answer remains unchanged . just look at the coefficients of highest terms .