HELP: find the horizontal limits of the function.
(ATTACHED BELOW)

- anonymous

HELP: find the horizontal limits of the function.
(ATTACHED BELOW)

- jamiebookeater

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- anonymous

##### 1 Attachment

- anonymous

@dumbcow

- anonymous

i got 11/-6

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## More answers

- anonymous

and im not sure for the other one

- anonymous

thats correct

- anonymous

dear by horizontal limit u mean limit in infinite ?

- anonymous

it doesnt say..

- anonymous

everything is attached

- anonymous

Horizantal limit is -11/6

- anonymous

it says and

- anonymous

is there 2 answers?

- anonymous

are*

- anonymous

i wrote my answers thrre but im not sure if theyre correct

- anonymous

no the one -11/6 is correct
@Roya yes it means take the limit at infinity .

- anonymous

oh ok

- anonymous

yes its right

- anonymous

thank yoou

- anonymous

yw :)

- anonymous

@sami-21 what if it is to -infinity

- anonymous

is it the same thing?

- anonymous

considering this you answer is correct .

- anonymous

what if it say as x approaches to negtive infinity

- anonymous

its gonna produce similar result because the answer is depending on the coefficients of highest terms in both numerator and denominator .

- anonymous

lets say for this one. the first one: i got -2

- anonymous

##### 1 Attachment

- anonymous

but the second question asks: if it's coming from - infinity. @sami-21

- anonymous

@Roya

- anonymous

@sami-21

- anonymous

still -2

- anonymous

can someone explain why the negative infinity part right?

- anonymous

@sami-21 i know it's -2 so how do we know it's -2? since i found the infinity part... and to find the negative infinity part would be.. ?

- anonymous

the same thing?

- anonymous

there is no different between + or - infinity. while solving these kind of question you ignore other part because infinity is so great. regardless it's positive or negative

- anonymous

so if i solved for infinity, an it asked me the -infinity, the answer is the same?

- anonymous

@Roya

- anonymous

yes the same answer

- anonymous

oh okay great thanks you

- anonymous

as i mentioned above these limits depends on the coefficients of the highest terms in both numerator and denominator .
lets give it a try
divide both numerator and denominator with highest power (here it is simply x )
\[\Large \lim_{x \rightarrow -\infty} \frac{ \frac{4+8x}{x}}{\frac{3-4x}{x}}\]
\[\Large \lim_{x \rightarrow -\infty} \frac{\frac{4}{x}+8}{\frac{3}{x}-4}\]
apply the limits
\[\Large \lim_{x \rightarrow -\infty} \frac{\frac{4}{-\infty}+8}{\frac{3}{-\infty}-4}\]
\[\Large \frac{-0+8}{-0-4}=\frac{8}{-4}=-2\]

- anonymous

just take care of function with different behavior along x axis . I mean the fuction which have different function for each of the X axis part |dw:1375077760801:dw|

- anonymous

@mathcalculus I hope its clear now .
in these cases yes both in _ or - infinity answer remains unchanged . just look at the coefficients of highest terms .

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