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mathcalculus

  • one year ago

HELP: find the horizontal limits of the function. (ATTACHED BELOW)

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  1. mathcalculus
    • one year ago
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  2. mathcalculus
    • one year ago
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    @dumbcow

  3. mathcalculus
    • one year ago
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    i got 11/-6

  4. mathcalculus
    • one year ago
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    and im not sure for the other one

  5. sami-21
    • one year ago
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    thats correct

  6. Roya
    • one year ago
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    dear by horizontal limit u mean limit in infinite ?

  7. mathcalculus
    • one year ago
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    it doesnt say..

  8. mathcalculus
    • one year ago
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    everything is attached

  9. sami-21
    • one year ago
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    Horizantal limit is -11/6

  10. mathcalculus
    • one year ago
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    it says and

  11. mathcalculus
    • one year ago
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    is there 2 answers?

  12. mathcalculus
    • one year ago
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    are*

  13. mathcalculus
    • one year ago
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    i wrote my answers thrre but im not sure if theyre correct

  14. sami-21
    • one year ago
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    no the one -11/6 is correct @Roya yes it means take the limit at infinity .

  15. mathcalculus
    • one year ago
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    oh ok

  16. mathcalculus
    • one year ago
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    yes its right

  17. mathcalculus
    • one year ago
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    thank yoou

  18. sami-21
    • one year ago
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    yw :)

  19. mathcalculus
    • one year ago
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    @sami-21 what if it is to -infinity

  20. mathcalculus
    • one year ago
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    is it the same thing?

  21. Roya
    • one year ago
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    considering this you answer is correct .

  22. mathcalculus
    • one year ago
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    what if it say as x approaches to negtive infinity

  23. sami-21
    • one year ago
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    its gonna produce similar result because the answer is depending on the coefficients of highest terms in both numerator and denominator .

  24. mathcalculus
    • one year ago
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    lets say for this one. the first one: i got -2

  25. mathcalculus
    • one year ago
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  26. mathcalculus
    • one year ago
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    but the second question asks: if it's coming from - infinity. @sami-21

  27. mathcalculus
    • one year ago
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    @Roya

  28. mathcalculus
    • one year ago
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    @sami-21

  29. sami-21
    • one year ago
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    still -2

  30. mathcalculus
    • one year ago
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    can someone explain why the negative infinity part right?

  31. mathcalculus
    • one year ago
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    @sami-21 i know it's -2 so how do we know it's -2? since i found the infinity part... and to find the negative infinity part would be.. ?

  32. mathcalculus
    • one year ago
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    the same thing?

  33. Roya
    • one year ago
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    there is no different between + or - infinity. while solving these kind of question you ignore other part because infinity is so great. regardless it's positive or negative

  34. mathcalculus
    • one year ago
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    so if i solved for infinity, an it asked me the -infinity, the answer is the same?

  35. mathcalculus
    • one year ago
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    @Roya

  36. Roya
    • one year ago
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    yes the same answer

  37. mathcalculus
    • one year ago
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    oh okay great thanks you

  38. sami-21
    • one year ago
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    as i mentioned above these limits depends on the coefficients of the highest terms in both numerator and denominator . lets give it a try divide both numerator and denominator with highest power (here it is simply x ) \[\Large \lim_{x \rightarrow -\infty} \frac{ \frac{4+8x}{x}}{\frac{3-4x}{x}}\] \[\Large \lim_{x \rightarrow -\infty} \frac{\frac{4}{x}+8}{\frac{3}{x}-4}\] apply the limits \[\Large \lim_{x \rightarrow -\infty} \frac{\frac{4}{-\infty}+8}{\frac{3}{-\infty}-4}\] \[\Large \frac{-0+8}{-0-4}=\frac{8}{-4}=-2\]

  39. Roya
    • one year ago
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    just take care of function with different behavior along x axis . I mean the fuction which have different function for each of the X axis part |dw:1375077760801:dw|

  40. sami-21
    • one year ago
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    @mathcalculus I hope its clear now . in these cases yes both in _ or - infinity answer remains unchanged . just look at the coefficients of highest terms .

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