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PsymonBest ResponseYou've already chosen the best response.1
Now that's one that confuses me, too, lol x_x Not even sure what you're supposed to do with it. Curious to see what other people say.
 8 months ago

PsymonBest ResponseYou've already chosen the best response.1
Oh, wait, I think it just wants the function?
 8 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
we can all use the help.
 8 months ago

Yahoo!Best ResponseYou've already chosen the best response.0
Can We Use Lhospitals Rule ?
 8 months ago

PsymonBest ResponseYou've already chosen the best response.1
Don't even know how to do that :P But the only thing I would be able to do is recognize that the function is x^(3.25) and go from there. But that;d be cheating I think. And nah, lhopitals rule is above his class.
 8 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
i don't know. it's a derivative question.
 8 months ago

PsymonBest ResponseYou've already chosen the best response.1
L'hopitals rule is a calc II thing, so not much to worry about for yourself, lol.
 8 months ago

RoyaBest ResponseYou've already chosen the best response.0
If I were you i would use hopital phenomenal .
 8 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
yeah, no no hospital rule.
 8 months ago

chandanjhaBest ResponseYou've already chosen the best response.0
differentiate both numerator n denominator with respect to h u got ur answer n put h =0
 8 months ago

sami21Best ResponseYou've already chosen the best response.1
I was thinking the same as Psyman mentioned that the original function is y=x^(3.25) dy/dx=3.25x^(2.25) i guess in order to evaluate the limit Binomial expansion is required
 8 months ago

chandanjhaBest ResponseYou've already chosen the best response.0
simple l hopital rule wud do in this case
 8 months ago

PsymonBest ResponseYou've already chosen the best response.1
I was thinking the expansion wasn't what the question really wanted, though.
 8 months ago

sami21Best ResponseYou've already chosen the best response.1
He is Just Newbie in the calculus I think He dont know L'Hôpital's rule !
 8 months ago

PsymonBest ResponseYou've already chosen the best response.1
Yeah, he hasn't seen l'hopitals rule if he's just now doing this.
 8 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
SIGN: people who know this only.
 8 months ago

CarlosGPBest ResponseYou've already chosen the best response.0
\[\frac{ dx^p }{ dx }=\lim_{h \rightarrow 0}\frac{ (x+h)^px^p }{ h }=px^{p1}\] And in this case p=3.125
 8 months ago

CarlosGPBest ResponseYou've already chosen the best response.0
Then the solution:\[3.25x^{4.25}\]
 8 months ago

sami21Best ResponseYou've already chosen the best response.1
this is as mentioned above the derivative of the function \[\Large y=x^{3.25}\] using the power rule of derivative which states if \[\Large y=x^n\] \[\Large \frac{dy}{dx}=nx^{n1}\] here n=3.25 just appply the power rule formula \[\Large \frac{dy}{dx}=3.25x^{(3.251)}\] \[\Huge \frac{dy}{dx}=3.25x^{4.25}\]
 8 months ago

PsymonBest ResponseYou've already chosen the best response.1
Yeah, more of just a knowledge of what the power rule for a derivative is and where within that difference quotient the original function actually is. In the end, it's the start of getting used to nx^(n1) for derivatives :P
 8 months ago
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