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mathcalculus

  • one year ago

DERIVATIVES: (attached below)

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  1. mathcalculus
    • one year ago
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  2. Psymon
    • one year ago
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    Now that's one that confuses me, too, lol x_x Not even sure what you're supposed to do with it. Curious to see what other people say.

  3. Psymon
    • one year ago
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    Oh, wait, I think it just wants the function?

  4. mathcalculus
    • one year ago
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    invite people.

  5. mathcalculus
    • one year ago
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    we can all use the help.

  6. Yahoo!
    • one year ago
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    Can We Use L-hospitals Rule ?

  7. Psymon
    • one year ago
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    Don't even know how to do that :P But the only thing I would be able to do is recognize that the function is x^(-3.25) and go from there. But that;d be cheating I think. And nah, l-hopitals rule is above his class.

  8. mathcalculus
    • one year ago
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    i don't know. it's a derivative question.

  9. Psymon
    • one year ago
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    L'hopitals rule is a calc II thing, so not much to worry about for yourself, lol.

  10. Roya
    • one year ago
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    If I were you i would use hopital phenomenal .

  11. mathcalculus
    • one year ago
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    yeah, no no hospital rule.

  12. Psymon
    • one year ago
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    Hehe, hospital rule.

  13. chandanjha
    • one year ago
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    differentiate both numerator n denominator with respect to h u got ur answer n put h =0

  14. sami-21
    • one year ago
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    I was thinking the same as Psyman mentioned that the original function is y=x^(-3.25) dy/dx=-3.25x^(-2.25) i guess in order to evaluate the limit Binomial expansion is required

  15. chandanjha
    • one year ago
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    simple l hopital rule wud do in this case

  16. Psymon
    • one year ago
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    I was thinking the expansion wasn't what the question really wanted, though.

  17. sami-21
    • one year ago
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    He is Just Newbie in the calculus I think He dont know L'Hôpital's rule !

  18. Psymon
    • one year ago
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    Yeah, he hasn't seen l'hopitals rule if he's just now doing this.

  19. mathcalculus
    • one year ago
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    SIGN: people who know this only.

  20. CarlosGP
    • one year ago
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    \[\frac{ dx^p }{ dx }=\lim_{h \rightarrow 0}\frac{ (x+h)^p-x^p }{ h }=px^{p-1}\] And in this case p=-3.125

  21. CarlosGP
    • one year ago
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    Sorry, p=-3.25

  22. CarlosGP
    • one year ago
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    Then the solution:\[-3.25x^{-4.25}\]

  23. sami-21
    • one year ago
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    this is as mentioned above the derivative of the function \[\Large y=x^{-3.25}\] using the power rule of derivative which states if \[\Large y=x^n\] \[\Large \frac{dy}{dx}=nx^{n-1}\] here n=3.25 just appply the power rule formula \[\Large \frac{dy}{dx}=-3.25x^{(-3.25-1)}\] \[\Huge \frac{dy}{dx}=-3.25x^{-4.25}\]

  24. Psymon
    • one year ago
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    Yeah, more of just a knowledge of what the power rule for a derivative is and where within that difference quotient the original function actually is. In the end, it's the start of getting used to nx^(n-1) for derivatives :P

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