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Psymon Group TitleBest ResponseYou've already chosen the best response.1
Now that's one that confuses me, too, lol x_x Not even sure what you're supposed to do with it. Curious to see what other people say.
 one year ago

Psymon Group TitleBest ResponseYou've already chosen the best response.1
Oh, wait, I think it just wants the function?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
invite people.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
we can all use the help.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Can We Use Lhospitals Rule ?
 one year ago

Psymon Group TitleBest ResponseYou've already chosen the best response.1
Don't even know how to do that :P But the only thing I would be able to do is recognize that the function is x^(3.25) and go from there. But that;d be cheating I think. And nah, lhopitals rule is above his class.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i don't know. it's a derivative question.
 one year ago

Psymon Group TitleBest ResponseYou've already chosen the best response.1
L'hopitals rule is a calc II thing, so not much to worry about for yourself, lol.
 one year ago

Roya Group TitleBest ResponseYou've already chosen the best response.0
If I were you i would use hopital phenomenal .
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
yeah, no no hospital rule.
 one year ago

Psymon Group TitleBest ResponseYou've already chosen the best response.1
Hehe, hospital rule.
 one year ago

chandanjha Group TitleBest ResponseYou've already chosen the best response.0
differentiate both numerator n denominator with respect to h u got ur answer n put h =0
 one year ago

sami21 Group TitleBest ResponseYou've already chosen the best response.1
I was thinking the same as Psyman mentioned that the original function is y=x^(3.25) dy/dx=3.25x^(2.25) i guess in order to evaluate the limit Binomial expansion is required
 one year ago

chandanjha Group TitleBest ResponseYou've already chosen the best response.0
simple l hopital rule wud do in this case
 one year ago

Psymon Group TitleBest ResponseYou've already chosen the best response.1
I was thinking the expansion wasn't what the question really wanted, though.
 one year ago

sami21 Group TitleBest ResponseYou've already chosen the best response.1
He is Just Newbie in the calculus I think He dont know L'Hôpital's rule !
 one year ago

Psymon Group TitleBest ResponseYou've already chosen the best response.1
Yeah, he hasn't seen l'hopitals rule if he's just now doing this.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
SIGN: people who know this only.
 one year ago

CarlosGP Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ dx^p }{ dx }=\lim_{h \rightarrow 0}\frac{ (x+h)^px^p }{ h }=px^{p1}\] And in this case p=3.125
 one year ago

CarlosGP Group TitleBest ResponseYou've already chosen the best response.0
Sorry, p=3.25
 one year ago

CarlosGP Group TitleBest ResponseYou've already chosen the best response.0
Then the solution:\[3.25x^{4.25}\]
 one year ago

sami21 Group TitleBest ResponseYou've already chosen the best response.1
this is as mentioned above the derivative of the function \[\Large y=x^{3.25}\] using the power rule of derivative which states if \[\Large y=x^n\] \[\Large \frac{dy}{dx}=nx^{n1}\] here n=3.25 just appply the power rule formula \[\Large \frac{dy}{dx}=3.25x^{(3.251)}\] \[\Huge \frac{dy}{dx}=3.25x^{4.25}\]
 one year ago

Psymon Group TitleBest ResponseYou've already chosen the best response.1
Yeah, more of just a knowledge of what the power rule for a derivative is and where within that difference quotient the original function actually is. In the end, it's the start of getting used to nx^(n1) for derivatives :P
 one year ago
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