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mathcalculus
 one year ago
DERIVATIVES:
(attached below)
mathcalculus
 one year ago
DERIVATIVES: (attached below)

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Psymon
 one year ago
Best ResponseYou've already chosen the best response.1Now that's one that confuses me, too, lol x_x Not even sure what you're supposed to do with it. Curious to see what other people say.

Psymon
 one year ago
Best ResponseYou've already chosen the best response.1Oh, wait, I think it just wants the function?

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0we can all use the help.

Yahoo!
 one year ago
Best ResponseYou've already chosen the best response.0Can We Use Lhospitals Rule ?

Psymon
 one year ago
Best ResponseYou've already chosen the best response.1Don't even know how to do that :P But the only thing I would be able to do is recognize that the function is x^(3.25) and go from there. But that;d be cheating I think. And nah, lhopitals rule is above his class.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0i don't know. it's a derivative question.

Psymon
 one year ago
Best ResponseYou've already chosen the best response.1L'hopitals rule is a calc II thing, so not much to worry about for yourself, lol.

Roya
 one year ago
Best ResponseYou've already chosen the best response.0If I were you i would use hopital phenomenal .

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0yeah, no no hospital rule.

chandanjha
 one year ago
Best ResponseYou've already chosen the best response.0differentiate both numerator n denominator with respect to h u got ur answer n put h =0

sami21
 one year ago
Best ResponseYou've already chosen the best response.1I was thinking the same as Psyman mentioned that the original function is y=x^(3.25) dy/dx=3.25x^(2.25) i guess in order to evaluate the limit Binomial expansion is required

chandanjha
 one year ago
Best ResponseYou've already chosen the best response.0simple l hopital rule wud do in this case

Psymon
 one year ago
Best ResponseYou've already chosen the best response.1I was thinking the expansion wasn't what the question really wanted, though.

sami21
 one year ago
Best ResponseYou've already chosen the best response.1He is Just Newbie in the calculus I think He dont know L'Hôpital's rule !

Psymon
 one year ago
Best ResponseYou've already chosen the best response.1Yeah, he hasn't seen l'hopitals rule if he's just now doing this.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0SIGN: people who know this only.

CarlosGP
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ dx^p }{ dx }=\lim_{h \rightarrow 0}\frac{ (x+h)^px^p }{ h }=px^{p1}\] And in this case p=3.125

CarlosGP
 one year ago
Best ResponseYou've already chosen the best response.0Then the solution:\[3.25x^{4.25}\]

sami21
 one year ago
Best ResponseYou've already chosen the best response.1this is as mentioned above the derivative of the function \[\Large y=x^{3.25}\] using the power rule of derivative which states if \[\Large y=x^n\] \[\Large \frac{dy}{dx}=nx^{n1}\] here n=3.25 just appply the power rule formula \[\Large \frac{dy}{dx}=3.25x^{(3.251)}\] \[\Huge \frac{dy}{dx}=3.25x^{4.25}\]

Psymon
 one year ago
Best ResponseYou've already chosen the best response.1Yeah, more of just a knowledge of what the power rule for a derivative is and where within that difference quotient the original function actually is. In the end, it's the start of getting used to nx^(n1) for derivatives :P
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