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anonymous
 3 years ago
DERIVATIVES:
(attached below)
anonymous
 3 years ago
DERIVATIVES: (attached below)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Now that's one that confuses me, too, lol x_x Not even sure what you're supposed to do with it. Curious to see what other people say.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, wait, I think it just wants the function?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we can all use the help.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Can We Use Lhospitals Rule ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Don't even know how to do that :P But the only thing I would be able to do is recognize that the function is x^(3.25) and go from there. But that;d be cheating I think. And nah, lhopitals rule is above his class.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i don't know. it's a derivative question.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0L'hopitals rule is a calc II thing, so not much to worry about for yourself, lol.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If I were you i would use hopital phenomenal .

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah, no no hospital rule.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0differentiate both numerator n denominator with respect to h u got ur answer n put h =0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I was thinking the same as Psyman mentioned that the original function is y=x^(3.25) dy/dx=3.25x^(2.25) i guess in order to evaluate the limit Binomial expansion is required

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0simple l hopital rule wud do in this case

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I was thinking the expansion wasn't what the question really wanted, though.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0He is Just Newbie in the calculus I think He dont know L'Hôpital's rule !

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah, he hasn't seen l'hopitals rule if he's just now doing this.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0SIGN: people who know this only.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ dx^p }{ dx }=\lim_{h \rightarrow 0}\frac{ (x+h)^px^p }{ h }=px^{p1}\] And in this case p=3.125

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Then the solution:\[3.25x^{4.25}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this is as mentioned above the derivative of the function \[\Large y=x^{3.25}\] using the power rule of derivative which states if \[\Large y=x^n\] \[\Large \frac{dy}{dx}=nx^{n1}\] here n=3.25 just appply the power rule formula \[\Large \frac{dy}{dx}=3.25x^{(3.251)}\] \[\Huge \frac{dy}{dx}=3.25x^{4.25}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah, more of just a knowledge of what the power rule for a derivative is and where within that difference quotient the original function actually is. In the end, it's the start of getting used to nx^(n1) for derivatives :P
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