Determine convergence or divergence.
(-1)^n/(n^3)
I know that I want to use the alternating series test. I used (bsubn) as 1/n^3 and (bsubn+1) as 1/(n+1)^3. I know that (bsubn) as n ----> infinity equals 0, but is (bsubn+1) less than or equal to (bsubn)?

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Or do i need to use a comparison test?

I know that those two conditions have to be met for it to be convergent...

is it
\[\sum_{n=1}^{\infty}\frac{(-1)^n}{n^3}\]

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