A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
hello guys, can someone help me with related rates?
(attached)
anonymous
 3 years ago
hello guys, can someone help me with related rates? (attached)

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Eww, word problems *waits for the problem and prepares sword*

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, not a word problem :D okay, np with this one

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So whenever you take the derivative of y, you can mark it with (dy/dx). Whenever you take the derivative of an x, you can mark it with (d/dx). So take the derivative of both sides, put dy/dx and d/dx where necessary, and plug in the given values.

zzr0ck3r
 3 years ago
Best ResponseYou've already chosen the best response.1the derivative of 7x^3  10x with respect to t Is 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dx/dt = 0 so will dy/dt

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0alright let me try this step by step.

zzr0ck3r
 3 years ago
Best ResponseYou've already chosen the best response.1y is in terms of x, there are no t's so treat x's like a constant derivative of a constant is 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Pretty much. They made it a little easy on ya with there being a dx/dt, haha. But itd be nice practice if we said it was d/dx and made d/dx equal to 1.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay so the derivative to this would be: 21x^210

zzr0ck3r
 3 years ago
Best ResponseYou've already chosen the best response.1with respect to x, yes but they ask for it with respect to t (not x)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay. so do i multiply each by dx/dt?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Its like theyre saying, there is no t for there to be a derivative in respect to, so everything is 0. Thats why I said we should change the conditions of the problem for practice.

zzr0ck3r
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{d(f(x))}{dt}=0\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0x is some function of t, thus when we take the derivative of y with respect to t, we get \[\frac{ dy }{ dt }=\frac{ d }{ dt }\left( 7x ^{3}10x \right)=\frac{ d }{ dt }\left( 7x ^{3} \right)\frac{ d }{ dt }\left( 10x \right)=21x ^{2}\frac{ dx }{ dt }10\frac{ dx }{ dt }\]form there it's plug in what you know and compute

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0since dx/dt is 0, dy/dt is 0. y only depends on x. look at te function. if x doesn't change, neither will y. the math proves it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0question: why would it be zero?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the problem states that dx/dt = 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0each term in dy/dt is multiplied by dx/dt

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no, d/dt is an operator. it says take the derivative of wht follows with respect to t.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dy/dt is the derivative of y with respect to t.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do you know the chain rule for derivatives?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sort of, I need to refresh my memory with the chain rule.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.