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PhoenixFire Group TitleBest ResponseYou've already chosen the best response.0
If you define the folowing functions as such: \[f:[0,\infty )\rightarrow [0,\infty )\quad f\left( x \right) :=\sqrt { x } \\ g:[0,\infty )\rightarrow { R }\quad g\left( x \right) :=\sqrt { x }\] Is the composite \( f\circ g\) properly defined? I would think it is NOT as g(x) maps to all Real numbers, while the domain of f(x) is \([0,\infty)\).
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.2
R is codomain for the second function it maps to the Range which is [0,infinity)
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.2
its defined just fine
 one year ago

PhoenixFire Group TitleBest ResponseYou've already chosen the best response.0
Ah, codomain not the range.
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.2
\[\sqrt{x}\ge0\] so \[\sqrt{\sqrt{x}}\] is fine
 one year ago

PhoenixFire Group TitleBest ResponseYou've already chosen the best response.0
@zzr0ck3r Thanks, codomain always confuses me. But I got it now.
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.2
codomain is what you are allowed to map to, range is what you map to
 one year ago
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