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How can I solve a Bernoulli's Equation if the derived "v" is not equal to the original equation?
Ex: y' = 2x2ycot2x
by multiplying it to y^1:
y^1(y')  2x(y^1) = 2ycot2x
Am I doin' it right? Please answer. :<
 8 months ago
 8 months ago
How can I solve a Bernoulli's Equation if the derived "v" is not equal to the original equation? Ex: y' = 2x2ycot2x by multiplying it to y^1: y^1(y')  2x(y^1) = 2ycot2x Am I doin' it right? Please answer. :<
 8 months ago
 8 months ago

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oldrin.batakuBest ResponseYou've already chosen the best response.3
this is not even a Bernoulli equation:$$y'=2x2y\cot2x\\y'+(2\cot 2x)y=2x$$this is just a linear differential equation.
 8 months ago

RyuuseiBest ResponseYou've already chosen the best response.0
yeah. my classmates told me too. still, thanks for your answer.
 8 months ago
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