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Ryuusei

  • one year ago

How can I solve a Bernoulli's Equation if the derived "v" is not equal to the original equation? Ex: y' = 2x-2ycot2x by multiplying it to y^-1: y^-1(y') - 2x(y^-1) = -2ycot2x Am I doin' it right? Please answer. :<

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  1. oldrin.bataku
    • one year ago
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    this is not even a Bernoulli equation:$$y'=2x-2y\cot2x\\y'+(2\cot 2x)y=2x$$this is just a linear differential equation.

  2. Ryuusei
    • one year ago
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    yeah. my classmates told me too. still, thanks for your answer.

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