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Buddhayourlord&savoir
 2 years ago
Are matrices A and B inverses? Look in comments to see matrices.
Buddhayourlord&savoir
 2 years ago
Are matrices A and B inverses? Look in comments to see matrices.

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Buddhayourlord&savoir
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1375487302704:dw

itsmylife
 2 years ago
Best ResponseYou've already chosen the best response.0just multiply them ,if your gona get identity matrix then yes they are inverse else no

Buddhayourlord&savoir
 2 years ago
Best ResponseYou've already chosen the best response.0What do you mean by "identity matrix"

Buddhayourlord&savoir
 2 years ago
Best ResponseYou've already chosen the best response.0identical?

jdoe0001
 2 years ago
Best ResponseYou've already chosen the best response.0\(\bf I = \left[ \begin{matrix} 1&0\\ 0&1 \end{matrix}\right]\)

Euler271
 2 years ago
Best ResponseYou've already chosen the best response.0And for 2x2 matrices only: \[A = \left[\begin{matrix}a & b \\ c & d\end{matrix}\right]\] \[A^{1} = \frac{ 1 }{ detA } \left[\begin{matrix}d & b \\ c & a\end{matrix}\right]\]

itsmylife
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1375487630099:dw

Buddhayourlord&savoir
 2 years ago
Best ResponseYou've already chosen the best response.0therefore it is not an inverse since its not all the same?

itsmylife
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1375487648610:dw

jdoe0001
 2 years ago
Best ResponseYou've already chosen the best response.0\( A \times B = \left[ \begin{matrix} 1&0\\ 0&1 \end{matrix}\right] = \textit{I} \implies B = A^{1}; A = B^{1}\)

Euler271
 2 years ago
Best ResponseYou've already chosen the best response.0watch out with that cross symbol ^_^

Buddhayourlord&savoir
 2 years ago
Best ResponseYou've already chosen the best response.0this isnt explaining anything at all guys :L

Buddhayourlord&savoir
 2 years ago
Best ResponseYou've already chosen the best response.0i get the equation but how do i know if it is or is not?

jdoe0001
 2 years ago
Best ResponseYou've already chosen the best response.0well, you have just have to multiply them

Buddhayourlord&savoir
 2 years ago
Best ResponseYou've already chosen the best response.0Multiply what? AxB as a whole? The numbers in A with each other? Im sorry im feeling pretty hopeless, i just need a more indepth explanation please ;/

Buddhayourlord&savoir
 2 years ago
Best ResponseYou've already chosen the best response.05*7=35 18*2=36 therefore the answer is no? right?

primeralph
 2 years ago
Best ResponseYou've already chosen the best response.1I just told you they are inverses.

Buddhayourlord&savoir
 2 years ago
Best ResponseYou've already chosen the best response.0oh, okay.

Buddhayourlord&savoir
 2 years ago
Best ResponseYou've already chosen the best response.0thanks man
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