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Are matrices A and B inverses? Look in comments to see matrices.

Mathematics
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|dw:1375487302704:dw|
just multiply them ,if your gona get identity matrix then yes they are inverse else no
\[A*A^{-1}=I\]

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Other answers:

What do you mean by "identity matrix"
identical?
\(\bf I = \left[ \begin{matrix} 1&0\\ 0&1 \end{matrix}\right]\)
And for 2x2 matrices only: \[A = \left[\begin{matrix}a & b \\ c & d\end{matrix}\right]\] \[A^{-1} = \frac{ 1 }{ detA } \left[\begin{matrix}d & -b \\ -c & a\end{matrix}\right]\]
|dw:1375487630099:dw|
therefore it is not an inverse since its not all the same?
|dw:1375487648610:dw|
\( A \times B = \left[ \begin{matrix} 1&0\\ 0&1 \end{matrix}\right] = \textit{I} \implies B = A^{-1}; A = B^{-1}\)
watch out with that cross symbol ^_^
lol
\(A \cdot B \) :)
hehe
this isnt explaining anything at all guys :L
i get the equation but how do i know if it is or is not?
well, you have just have to multiply them
Multiply what? AxB as a whole? The numbers in A with each other? Im sorry im feeling pretty hopeless, i just need a more in-depth explanation please ;/
Yes. Inverses.
5*-7=-35 -18*2=-36 therefore the answer is no? right?
I just told you they are inverses.
oh, okay.
thanks man
You're welcome.

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