anonymous
  • anonymous
Are matrices A and B inverses? Look in comments to see matrices.
Mathematics
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
|dw:1375487302704:dw|
anonymous
  • anonymous
just multiply them ,if your gona get identity matrix then yes they are inverse else no
anonymous
  • anonymous
\[A*A^{-1}=I\]

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More answers

anonymous
  • anonymous
What do you mean by "identity matrix"
anonymous
  • anonymous
identical?
jdoe0001
  • jdoe0001
\(\bf I = \left[ \begin{matrix} 1&0\\ 0&1 \end{matrix}\right]\)
anonymous
  • anonymous
And for 2x2 matrices only: \[A = \left[\begin{matrix}a & b \\ c & d\end{matrix}\right]\] \[A^{-1} = \frac{ 1 }{ detA } \left[\begin{matrix}d & -b \\ -c & a\end{matrix}\right]\]
anonymous
  • anonymous
|dw:1375487630099:dw|
anonymous
  • anonymous
therefore it is not an inverse since its not all the same?
anonymous
  • anonymous
|dw:1375487648610:dw|
jdoe0001
  • jdoe0001
\( A \times B = \left[ \begin{matrix} 1&0\\ 0&1 \end{matrix}\right] = \textit{I} \implies B = A^{-1}; A = B^{-1}\)
anonymous
  • anonymous
watch out with that cross symbol ^_^
jdoe0001
  • jdoe0001
lol
jdoe0001
  • jdoe0001
\(A \cdot B \) :)
anonymous
  • anonymous
hehe
anonymous
  • anonymous
this isnt explaining anything at all guys :L
anonymous
  • anonymous
i get the equation but how do i know if it is or is not?
jdoe0001
  • jdoe0001
well, you have just have to multiply them
anonymous
  • anonymous
Multiply what? AxB as a whole? The numbers in A with each other? Im sorry im feeling pretty hopeless, i just need a more in-depth explanation please ;/
primeralph
  • primeralph
Yes. Inverses.
anonymous
  • anonymous
5*-7=-35 -18*2=-36 therefore the answer is no? right?
primeralph
  • primeralph
I just told you they are inverses.
anonymous
  • anonymous
oh, okay.
anonymous
  • anonymous
thanks man
primeralph
  • primeralph
You're welcome.

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