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Buddhayourlord&savoir
 one year ago
Are matrices A and B inverses? Look in comments to see matrices.
Buddhayourlord&savoir
 one year ago
Are matrices A and B inverses? Look in comments to see matrices.

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Buddhayourlord&savoir
 one year ago
Best ResponseYou've already chosen the best response.0dw:1375487302704:dw

itsmylife
 one year ago
Best ResponseYou've already chosen the best response.0just multiply them ,if your gona get identity matrix then yes they are inverse else no

Buddhayourlord&savoir
 one year ago
Best ResponseYou've already chosen the best response.0What do you mean by "identity matrix"

Buddhayourlord&savoir
 one year ago
Best ResponseYou've already chosen the best response.0identical?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf I = \left[ \begin{matrix} 1&0\\ 0&1 \end{matrix}\right]\)

Euler271
 one year ago
Best ResponseYou've already chosen the best response.0And for 2x2 matrices only: \[A = \left[\begin{matrix}a & b \\ c & d\end{matrix}\right]\] \[A^{1} = \frac{ 1 }{ detA } \left[\begin{matrix}d & b \\ c & a\end{matrix}\right]\]

itsmylife
 one year ago
Best ResponseYou've already chosen the best response.0dw:1375487630099:dw

Buddhayourlord&savoir
 one year ago
Best ResponseYou've already chosen the best response.0therefore it is not an inverse since its not all the same?

itsmylife
 one year ago
Best ResponseYou've already chosen the best response.0dw:1375487648610:dw

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0\( A \times B = \left[ \begin{matrix} 1&0\\ 0&1 \end{matrix}\right] = \textit{I} \implies B = A^{1}; A = B^{1}\)

Euler271
 one year ago
Best ResponseYou've already chosen the best response.0watch out with that cross symbol ^_^

Buddhayourlord&savoir
 one year ago
Best ResponseYou've already chosen the best response.0this isnt explaining anything at all guys :L

Buddhayourlord&savoir
 one year ago
Best ResponseYou've already chosen the best response.0i get the equation but how do i know if it is or is not?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0well, you have just have to multiply them

Buddhayourlord&savoir
 one year ago
Best ResponseYou've already chosen the best response.0Multiply what? AxB as a whole? The numbers in A with each other? Im sorry im feeling pretty hopeless, i just need a more indepth explanation please ;/

Buddhayourlord&savoir
 one year ago
Best ResponseYou've already chosen the best response.05*7=35 18*2=36 therefore the answer is no? right?

primeralph
 one year ago
Best ResponseYou've already chosen the best response.1I just told you they are inverses.

Buddhayourlord&savoir
 one year ago
Best ResponseYou've already chosen the best response.0oh, okay.

Buddhayourlord&savoir
 one year ago
Best ResponseYou've already chosen the best response.0thanks man
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