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Buddhayourlord&savoir
Group Title
Are matrices A and B inverses? Look in comments to see matrices.
 one year ago
 one year ago
Buddhayourlord&savoir Group Title
Are matrices A and B inverses? Look in comments to see matrices.
 one year ago
 one year ago

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Buddhayourlord&savoir Group TitleBest ResponseYou've already chosen the best response.0
dw:1375487302704:dw
 one year ago

itsmylife Group TitleBest ResponseYou've already chosen the best response.0
just multiply them ,if your gona get identity matrix then yes they are inverse else no
 one year ago

itsmylife Group TitleBest ResponseYou've already chosen the best response.0
\[A*A^{1}=I\]
 one year ago

Buddhayourlord&savoir Group TitleBest ResponseYou've already chosen the best response.0
What do you mean by "identity matrix"
 one year ago

Buddhayourlord&savoir Group TitleBest ResponseYou've already chosen the best response.0
identical?
 one year ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
\(\bf I = \left[ \begin{matrix} 1&0\\ 0&1 \end{matrix}\right]\)
 one year ago

Euler271 Group TitleBest ResponseYou've already chosen the best response.0
And for 2x2 matrices only: \[A = \left[\begin{matrix}a & b \\ c & d\end{matrix}\right]\] \[A^{1} = \frac{ 1 }{ detA } \left[\begin{matrix}d & b \\ c & a\end{matrix}\right]\]
 one year ago

itsmylife Group TitleBest ResponseYou've already chosen the best response.0
dw:1375487630099:dw
 one year ago

Buddhayourlord&savoir Group TitleBest ResponseYou've already chosen the best response.0
therefore it is not an inverse since its not all the same?
 one year ago

itsmylife Group TitleBest ResponseYou've already chosen the best response.0
dw:1375487648610:dw
 one year ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
\( A \times B = \left[ \begin{matrix} 1&0\\ 0&1 \end{matrix}\right] = \textit{I} \implies B = A^{1}; A = B^{1}\)
 one year ago

Euler271 Group TitleBest ResponseYou've already chosen the best response.0
watch out with that cross symbol ^_^
 one year ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
\(A \cdot B \) :)
 one year ago

Buddhayourlord&savoir Group TitleBest ResponseYou've already chosen the best response.0
this isnt explaining anything at all guys :L
 one year ago

Buddhayourlord&savoir Group TitleBest ResponseYou've already chosen the best response.0
i get the equation but how do i know if it is or is not?
 one year ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
well, you have just have to multiply them
 one year ago

Buddhayourlord&savoir Group TitleBest ResponseYou've already chosen the best response.0
Multiply what? AxB as a whole? The numbers in A with each other? Im sorry im feeling pretty hopeless, i just need a more indepth explanation please ;/
 one year ago

primeralph Group TitleBest ResponseYou've already chosen the best response.1
Yes. Inverses.
 one year ago

Buddhayourlord&savoir Group TitleBest ResponseYou've already chosen the best response.0
5*7=35 18*2=36 therefore the answer is no? right?
 one year ago

primeralph Group TitleBest ResponseYou've already chosen the best response.1
I just told you they are inverses.
 one year ago

Buddhayourlord&savoir Group TitleBest ResponseYou've already chosen the best response.0
oh, okay.
 one year ago

Buddhayourlord&savoir Group TitleBest ResponseYou've already chosen the best response.0
thanks man
 one year ago

primeralph Group TitleBest ResponseYou've already chosen the best response.1
You're welcome.
 one year ago
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