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Are matrices A and B inverses? Look in comments to see matrices.
 8 months ago
 8 months ago
Are matrices A and B inverses? Look in comments to see matrices.
 8 months ago
 8 months ago

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Buddhayourlord&savoirBest ResponseYou've already chosen the best response.0
dw:1375487302704:dw
 8 months ago

itsmylifeBest ResponseYou've already chosen the best response.0
just multiply them ,if your gona get identity matrix then yes they are inverse else no
 8 months ago

Buddhayourlord&savoirBest ResponseYou've already chosen the best response.0
What do you mean by "identity matrix"
 8 months ago

Buddhayourlord&savoirBest ResponseYou've already chosen the best response.0
identical?
 8 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
\(\bf I = \left[ \begin{matrix} 1&0\\ 0&1 \end{matrix}\right]\)
 8 months ago

Euler271Best ResponseYou've already chosen the best response.0
And for 2x2 matrices only: \[A = \left[\begin{matrix}a & b \\ c & d\end{matrix}\right]\] \[A^{1} = \frac{ 1 }{ detA } \left[\begin{matrix}d & b \\ c & a\end{matrix}\right]\]
 8 months ago

itsmylifeBest ResponseYou've already chosen the best response.0
dw:1375487630099:dw
 8 months ago

Buddhayourlord&savoirBest ResponseYou've already chosen the best response.0
therefore it is not an inverse since its not all the same?
 8 months ago

itsmylifeBest ResponseYou've already chosen the best response.0
dw:1375487648610:dw
 8 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
\( A \times B = \left[ \begin{matrix} 1&0\\ 0&1 \end{matrix}\right] = \textit{I} \implies B = A^{1}; A = B^{1}\)
 8 months ago

Euler271Best ResponseYou've already chosen the best response.0
watch out with that cross symbol ^_^
 8 months ago

Buddhayourlord&savoirBest ResponseYou've already chosen the best response.0
this isnt explaining anything at all guys :L
 8 months ago

Buddhayourlord&savoirBest ResponseYou've already chosen the best response.0
i get the equation but how do i know if it is or is not?
 8 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
well, you have just have to multiply them
 8 months ago

Buddhayourlord&savoirBest ResponseYou've already chosen the best response.0
Multiply what? AxB as a whole? The numbers in A with each other? Im sorry im feeling pretty hopeless, i just need a more indepth explanation please ;/
 8 months ago

Buddhayourlord&savoirBest ResponseYou've already chosen the best response.0
5*7=35 18*2=36 therefore the answer is no? right?
 8 months ago

primeralphBest ResponseYou've already chosen the best response.1
I just told you they are inverses.
 8 months ago

Buddhayourlord&savoirBest ResponseYou've already chosen the best response.0
oh, okay.
 8 months ago

Buddhayourlord&savoirBest ResponseYou've already chosen the best response.0
thanks man
 8 months ago
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