Buddhayourlord&savoir
Are matrices A and B inverses? Look in comments to see matrices.
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itsmylife
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just multiply them ,if your gona get identity matrix then yes they are inverse else no
itsmylife
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\[A*A^{-1}=I\]
Buddhayourlord&savoir
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What do you mean by "identity matrix"
jdoe0001
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\(\bf I = \left[
\begin{matrix}
1&0\\
0&1
\end{matrix}\right]\)
Euler271
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And for 2x2 matrices only:
\[A = \left[\begin{matrix}a & b \\ c & d\end{matrix}\right]\]
\[A^{-1} = \frac{ 1 }{ detA } \left[\begin{matrix}d & -b \\ -c & a\end{matrix}\right]\]
itsmylife
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|dw:1375487630099:dw|
Buddhayourlord&savoir
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therefore it is not an inverse since its not all the same?
itsmylife
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|dw:1375487648610:dw|
jdoe0001
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\( A \times B =
\left[
\begin{matrix}
1&0\\
0&1
\end{matrix}\right] = \textit{I} \implies B = A^{-1}; A = B^{-1}\)
Euler271
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watch out with that cross symbol ^_^
jdoe0001
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lol
jdoe0001
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\(A \cdot B \) :)
Euler271
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hehe
Buddhayourlord&savoir
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this isnt explaining anything at all guys :L
Buddhayourlord&savoir
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i get the equation but how do i know if it is or is not?
jdoe0001
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well, you have just have to multiply them
Buddhayourlord&savoir
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Multiply what? AxB as a whole? The numbers in A with each other? Im sorry im feeling pretty hopeless, i just need a more in-depth explanation please ;/
primeralph
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Yes. Inverses.
Buddhayourlord&savoir
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5*-7=-35
-18*2=-36
therefore the answer is no? right?
primeralph
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I just told you they are inverses.
primeralph
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You're welcome.