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melmelBest ResponseYou've already chosen the best response.0
bernoulli equation or homogeneous
 8 months ago

.Sam.Best ResponseYou've already chosen the best response.0
\[xdx + ( y 2x)dy= 0\] \[xdx=(y2x)dy \\ \frac{x}{y2x}=\frac{dy}{dx}\]  Try using y=vx Then \[\frac{dy}{dx}=v+x\frac{dv}{dx}\]
 8 months ago

.Sam.Best ResponseYou've already chosen the best response.0
Replace the y and \(\frac{dy}{dx}\) to v and the one given above \[\frac{x}{vx2x}=v+x\frac{dv}{dx} \\ \frac{1}{2v}=v+x\frac{dv}{dx}\]
 8 months ago

melmelBest ResponseYou've already chosen the best response.0
the numerator can break it for the denomentor?
 8 months ago

.Sam.Best ResponseYou've already chosen the best response.0
Then set all v into the other side \[\frac{12v+v^2}{(2v)x}=\frac{dv}{dx} \\ \frac{(2v)x}{12v+v^2}=\frac{dx}{dv} \\ \int\limits \frac{(2v)}{12v+v^2} dx=\int\limits \frac{1}{x}dx\]
 8 months ago

.Sam.Best ResponseYou've already chosen the best response.0
Should be dv \[\int\limits\limits \frac{(2v)}{12v+v^2} dv=\int\limits\limits \frac{1}{x}dx\]
 8 months ago

dumbcowBest ResponseYou've already chosen the best response.0
i think you get stuck here though...no way to solve for "v" the integral gives a fraction and a log
 8 months ago

melmelBest ResponseYou've already chosen the best response.0
i think we can use here synthetic division
 8 months ago

dumbcowBest ResponseYou've already chosen the best response.0
@melmel , no that only works if the "2v" was in denominator
 8 months ago

dumbcowBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=integral+%282v%29%2F%28v%5E22v%2B1%29
 8 months ago

dumbcowBest ResponseYou've already chosen the best response.0
turns out you can't solve for "y" directly http://www.wolframalpha.com/input/?i=y%27%28x%29+%3D+x%2F%282xy%28x%29%29
 8 months ago

melmelBest ResponseYou've already chosen the best response.0
can you help me to solve and to prove that?
 8 months ago

dumbcowBest ResponseYou've already chosen the best response.0
@.sam, already did but you cant go any further just sub in y/x for v
 8 months ago

melmelBest ResponseYou've already chosen the best response.0
so what is my final answer?
 8 months ago

dumbcowBest ResponseYou've already chosen the best response.0
i dunno depends on the instructions...ther is no "y =" answer
 8 months ago

melmelBest ResponseYou've already chosen the best response.0
CAN YO HELP ME @zepdrix
 8 months ago

melmelBest ResponseYou've already chosen the best response.0
coefficients by division?
 8 months ago
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