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melmel Group TitleBest ResponseYou've already chosen the best response.0
to find y any method
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
bernoulli equation or homogeneous
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
can you help me @.Sam.
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.0
\[xdx + ( y 2x)dy= 0\] \[xdx=(y2x)dy \\ \frac{x}{y2x}=\frac{dy}{dx}\]  Try using y=vx Then \[\frac{dy}{dx}=v+x\frac{dv}{dx}\]
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.0
Replace the y and \(\frac{dy}{dx}\) to v and the one given above \[\frac{x}{vx2x}=v+x\frac{dv}{dx} \\ \frac{1}{2v}=v+x\frac{dv}{dx}\]
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
the numerator can break it for the denomentor?
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.0
Then set all v into the other side \[\frac{12v+v^2}{(2v)x}=\frac{dv}{dx} \\ \frac{(2v)x}{12v+v^2}=\frac{dx}{dv} \\ \int\limits \frac{(2v)}{12v+v^2} dx=\int\limits \frac{1}{x}dx\]
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.0
Should be dv \[\int\limits\limits \frac{(2v)}{12v+v^2} dv=\int\limits\limits \frac{1}{x}dx\]
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.0
i think you get stuck here though...no way to solve for "v" the integral gives a fraction and a log
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
i think we can use here synthetic division
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
my Im right?
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.0
@melmel , no that only works if the "2v" was in denominator
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=integral+%282v%29%2F%28v%5E22v%2B1%29
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.0
turns out you can't solve for "y" directly http://www.wolframalpha.com/input/?i=y%27%28x%29+%3D+x%2F%282xy%28x%29%29
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
can you help me to solve and to prove that?
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.0
@.sam, already did but you cant go any further just sub in y/x for v
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
so what is my final answer?
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.0
i dunno depends on the instructions...ther is no "y =" answer
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
CAN YO HELP ME @zepdrix
 one year ago

melmel Group TitleBest ResponseYou've already chosen the best response.0
coefficients by division?
 one year ago
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