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fayaz803
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ABC is an isosceles triangle with AB=BC. The circumcircle of ABC has radius 8. Given that AC is a diameter of the circumcircle, what is the area of triangle ABC?
 11 months ago
 11 months ago
fayaz803 Group Title
ABC is an isosceles triangle with AB=BC. The circumcircle of ABC has radius 8. Given that AC is a diameter of the circumcircle, what is the area of triangle ABC?
 11 months ago
 11 months ago

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genius12 Group TitleBest ResponseYou've already chosen the best response.1
dw:1375617084417:dwNote that angle B will be a right angle (which can be proved using the 'Angle at the center theorem'). We also note that this triangle is isosceles and and it's base is the diameter of the circle \(\bf AC=16\). And the height of the triangle is just the radius of the circle which is given to us as 8. Hence of the triangle is:\[\bf Area \ of \ \triangle ABC=\frac{ 16 \times 8 }{ 2 }=64 \ units^2\]
 11 months ago

genius12 Group TitleBest ResponseYou've already chosen the best response.1
@fayaz803
 11 months ago

CGGURUMANJUNATH Group TitleBest ResponseYou've already chosen the best response.0
64
 11 months ago

srev98 Group TitleBest ResponseYou've already chosen the best response.0
true"genius" u have all concepts in ur finger tips!!!!!
 11 months ago
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